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This section includes 19 Mcqs, each offering curated multiple-choice questions to sharpen your Theory Machines knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Two 20° involute spur gears have a module of 12 mm. The addendum is equal to 1.5 module. If the larger gear has 40 teeth and the pinion has 20 teeth, find the pressure angle at which interference can be avoided. |
| A. | 20.66° |
| B. | 21.96° |
| C. | 22.23° |
| D. | 21.24° |
| Answer» B. 21.96° | |
| 2. |
Two 25° involute spur gears have a module of 7 mm. The addendum is equal to one module. If the larger gear has 60 teeth and the pinion has 30 teeth, they will interfere with each other. True or false? |
| A. | True |
| B. | False |
| Answer» C. | |
| 3. |
Find the maximum value of addendum radius of the larger gear if the pinion has 17 teeth, the larger gear has 51 teeth and the pressure angle is equal to 15°. Take the value of module as 8 mm. |
| A. | 9.092 mm |
| B. | 8.923 mm |
| C. | 5.247 mm |
| D. | 4.389 mm |
| Answer» D. 4.389 mm | |
| 4. |
Find the maximum value of addendum radius of the pinion if the pinion has 25 teeth, the larger gear has 100 teeth and the pressure angle is equal to 20°. Take the value of module as 6 mm. |
| A. | 78.943 mm |
| B. | 71.345 mm |
| C. | 78.431 mm |
| D. | 74.459 mm |
| Answer» C. 78.431 mm | |
| 5. |
The number of teeth on a pinion is equal to 20 and the gear ratio is 3. The pressure angle is equal to 15°. If the module is equal to 6 mm, find the path of contact when interference is just avoided. |
| A. | 62.116 mm |
| B. | 73.324 mm |
| C. | 42.831 mm |
| D. | 51.483 mm |
| Answer» B. 73.324 mm | |
| 6. |
Find the maximum value of addendum radius of the larger gear if the pressure angle between two teeth is equal to 25°. T = 50 and t = 25. The gears have a module of 8 mm and the addendum is equal to one module. |
| A. | 211. 202 mm |
| B. | 231. 202 mm |
| C. | 221. 202 mm |
| D. | 201. 202 mm |
| Answer» D. 201. 202 mm | |
| 7. |
Two involute gears have a pressure angle of 20°. The gear ratio is given to be 3. The module is 5 mm and the value of addendum is equal to 1 module. Determine the minimum number of teeth on each wheel to avoid interference, if the pinion rotates at 100 rpm. |
| A. | T = 51, t= 17 |
| B. | T = 45, t =15 |
| C. | T = 60, t =20 |
| D. | T = 54, t = 18 |
| Answer» C. T = 60, t =20 | |
| 8. |
In the given diagram, identify the maximum value of addendum radius of the larger gear or the wheel to avoid interference. |
| A. | AD |
| B. | BE |
| C. | BC |
| D. | BA |
| Answer» C. BC | |
| 9. |
FIND_THE_MAXIMUM_VALUE_OF_ADDENDUM_RADIUS_OF_THE_PINION_IF_THE_PINION_HAS_25_TEETH,_THE_LARGER_GEAR_HAS_100_TEETH_AND_THE_PRESSURE_ANGLE_IS_EQUAL_TO_20¬¨ àû._TAKE_THE_VALUE_OF_MODULE_AS_6_MM.?$# |
| A. | 78.943 mm |
| B. | 71.345 mm |
| C. | 78.431 mm |
| D. | 74.459 mm |
| Answer» C. 78.431 mm | |
| 10. |
Two 25° involute spur gears have a module of 7 mm. The addendum is equal to one module. If the larger gear has 60 teeth and the pinion has 30 teeth, they will interfere with each other. True or false?$# |
| A. | True |
| B. | False |
| Answer» C. | |
| 11. |
Find_the_maximum_value_of_addendum_radius_of_the_larger_gear_if_the_pinion_has_17_teeth,_the_larger_gear_has_51_teeth_and_the_pressure_angle_is_equal_to_15°._Take_the_value_of_module_as_8_mm.$# |
| A. | 9.092 mm |
| B. | 8.923 mm |
| C. | 5.247 mm |
| D. | 4.389 mm |
| Answer» D. 4.389 mm | |
| 12. |
Two_20°_involute_spur_gears_have_a_module_of_12_mm._The_addendum_is_equal_to_1.5_module._If_the_larger_gear_has_40_teeth_and_the_pinion_has_20_teeth,_find_the_pressure_angle_at_which_interference_can_be_avoided.$ |
| A. | 20.66° |
| B. | 21.96° |
| C. | 22.23° |
| D. | 21.24° |
| Answer» B. 21.96¬¨¬®‚Äö√†√ª | |
| 13. |
The number of teeth on a pinion is equal to 20 and the gear ratio is 3. The pressure angle is equal to 15°. If the module is equal to 6 mm, find the path of contact when interference is just avoided?# |
| A. | 62.116 mm |
| B. | 73.324 mm |
| C. | 42.831 mm |
| D. | 51.483 mm |
| Answer» B. 73.324 mm | |
| 14. |
Find the maximum value of addendum radius of the larger gear if the pressure angle between two teeth is equal to 25°. T = 50 and t = 25. The gears have a module of 8 mm and the addendum is equal to one module.$ |
| A. | 211. 202 mm |
| B. | 231. 202 mm |
| C. | 221. 202 mm |
| D. | 201. 202 mm |
| Answer» D. 201. 202 mm | |
| 15. |
Two involute gears have a pressure angle of 20°. The gear ratio is given to be 3. The module is 5 mm and the value of addendum is equal to 1 module. Determine the minimum number of teeth on each wheel to avoid interference, if the pinion rotates at 100 rpm.$ |
| A. | T = 51, t= 17 |
| B. | T = 45, t =15 |
| C. | T = 60, t =20 |
| D. | T = 54, t = 18 |
| Answer» C. T = 60, t =20 | |
| 16. |
If the maximum addendum radius of the wheel is given as 260 mm and the actual value of the addendum radius is found out to be 255 mm, the interference will occur. True or false? |
| A. | True |
| B. | False |
| Answer» C. | |
| 17. |
What is the maximum value of the addendum of the pinion? |
| A. | mt((1+G(G+2)sin<sup>2</sup> φ)<sup>0.5</sup>+1)/2 |
| B. | mt((1-G(G+2)sin<sup>2</sup> φ)<sup>0.5</sup>-1)/2 |
| C. | mt((1-G(G+2)sin<sup>2</sup> φ)<sup>0.5</sup>+1)/2 |
| D. | mt((1+G(G+2)sin<sup>2</sup> φ)<sup>0.5</sup>-1)/2 |
| Answer» E. | |
| 18. |
What is the formula for calculating the minimum number of teeth on the wheel ? |
| A. | T = 2a<sub>w</sub>/((1+(1/G)((1/G)+2)sin<sup>2</sup>φ)<sup>0.5</sup> – 1) |
| B. | T = a<sub>w</sub>/((1+(1/G)((1/G)+2)sin<sup>2</sup>φ)<sup>0.5</sup> – 1) |
| C. | T = 2a<sub>w</sub>/((1+(1/G)((1/G)+2)sin<sup>2</sup>φ)<sup>0.5</sup> |
| D. | T = 2a<sub>w</sub>/((1+(1/G)((1/G)+2)sin<sup>2</sup>φ)<sup>0.5</sup> + 1) |
| Answer» B. T = a<sub>w</sub>/((1+(1/G)((1/G)+2)sin<sup>2</sup>‚âà√¨‚àö√∫)<sup>0.5</sup> ‚Äö√Ñ√∂‚àö√ë‚àö¬® 1) | |
| 19. |
The maximum radius of addendum to avoid interference is given by the formula ____________ |
| A. | ((R cosφ)<sup>2</sup> + (R sinφ + r sinφ)<sup>2</sup>)<sup>0.5</sup> |
| B. | ((R cosφ)<sup>2</sup> + (R sinφ – r sinφ)<sup>2</sup>)<sup>0.5</sup> |
| C. | ((R cosφ)<sup>2</sup> – (R sinφ + r sinφ)<sup>2</sup>)<sup>0.5</sup> |
| D. | ((R cosφ)<sup>2</sup> – (R sinφ – r sinφ)<sup>2</sup>)<sup>0.5</sup> |
| Answer» B. ((R cos‚âà√¨‚àö√∫)<sup>2</sup> + (R sin‚âà√¨‚àö√∫ ‚Äö√Ñ√∂‚àö√ë‚àö¬® r sin‚âà√¨‚àö√∫)<sup>2</sup>)<sup>0.5</sup> | |