MCQOPTIONS
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MCQOPTIONS
This section includes 11 Mcqs, each offering curated multiple-choice questions to sharpen your Machine Kinematics Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Klein’s construction is useful to determine |
| A. | velocity of various parts |
| B. | acceleration of various parts |
| C. | displacement of various parts |
| D. | angular acceleration of various parts |
| Answer» C. displacement of various parts | |
| 2. |
Klien’s construction can be used when |
| A. | crank has a uniform angular velocity |
| B. | crank has non-uniform velocity |
| C. | crank has uniform angular acceleration |
| D. | crank has uniform angular velocity and angular acceleration |
| Answer» B. crank has non-uniform velocity | |
| 3. |
The sense of Coriol’s component is such that it |
| A. | leads the sliding velocity vector by 900 |
| B. | lags the sliding velocity vector by 900 |
| C. | is along the sliding velocity vector by 900 |
| D. | leads the sliding velocity vector by 1800 |
| Answer» B. lags the sliding velocity vector by 900 | |
| 4. |
Corioli’s component acts |
| A. | perpendicular to sliding surfaces |
| B. | along sliding surfaces |
| C. | both of the mentioned |
| D. | all of the mentioned |
| Answer» B. along sliding surfaces | |
| 5. |
Klien’s construction can be used to determine acceleration of various parts when the crank is at |
| A. | inner dead center |
| B. | outer dead center |
| C. | right angles to the link of the stroke |
| D. | all of the mentioned |
| Answer» E. | |
| 6. |
Klein’s construction gives a graphical construction for |
| A. | slider-crank mechanism |
| B. | velocity polygon |
| C. | acceleration polygon |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 7. |
Corioli’s component is encountered in |
| A. | quick return mechanism of shaper |
| B. | four bar chain mechanism |
| C. | slider crank mechanism |
| D. | all of the mentioned |
| Answer» B. four bar chain mechanism | |
| 8. |
In a rotary engine the angular velocity of the cylinder center line is 25 rad/sec and the relative velocity of a point on the cylinder center line w.r.t. cylinder is 10 m/sec. Corioli’s acceleration will be |
| A. | 500m/sec2 |
| B. | 250m/sec2 |
| C. | 1000m/sec2 |
| D. | 2000m/sec2 |
| Answer» B. 250m/sec2 | |
| 9. |
The magnitude of the Corioli’s component of acceleration of a slider moving at velocity V on a link rotating at angular speed ω is |
| A. | Vω |
| B. | 2Vω |
| C. | Vω/2 |
| D. | 2V/ω |
| Answer» C. Vω/2 | |
| 10. |
In a shaper mechanism, the Corioli’s component of acceleration will |
| A. | not exist |
| B. | exist |
| C. | depend on position of crank |
| D. | none of the mentioned |
| Answer» C. depend on position of crank | |
| 11. |
The direction of Corioli’s component of acceleration is the direction |
| A. | of relative velocity vector for the two coincident points rotated by 900 in the direction of the angular velocity of the rotation of the link |
| B. | along the centripetal acceleration |
| C. | along tangential acceleration |
| D. | along perpendicular to angular velocity |
| Answer» B. along the centripetal acceleration | |