MCQOPTIONS
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MCQOPTIONS
This section includes 330 Mcqs, each offering curated multiple-choice questions to sharpen your Grade8 knowledge and support exam preparation. Choose a topic below to get started.
| 251. |
By expressing the ³√125x⁄(x + y) in index form, the answer will be |
| A. | 6x1⁄2 (x + y)-1/3 |
| B. | 5x1⁄3 (x + y)1/3 |
| C. | 5x-1⁄3 (x + y)-1/3 |
| D. | 5x1⁄3 (x + y)-1/3 |
| Answer» E. | |
| 252. |
The answer of (4.5 x 10-6 )/(2.3 x 10-4 ) is |
| A. | 1.96 x 101 |
| B. | 2.96 x 10² |
| C. | 3.96 x 10³ |
| D. | 1.96 x 10² |
| Answer» B. 2.96 x 10² | |
| 253. |
By expressing the answer in form of 10n, the answer of 10-5 x 107 ⁄109 x 10-4 is |
| A. | 10-3 |
| B. | 10-4 |
| C. | 10-5 |
| D. | 10³ |
| Answer» B. 10-4 | |
| 254. |
The answer of 12(2.0 x 10³)⁄(4.0 x 10²) in standard form is |
| A. | 6.0 x 10² |
| B. | 6.0 x 10-2 |
| C. | 6.0 x 10-1 |
| D. | 6.0 x 101 |
| Answer» E. | |
| 255. |
If the height of wind mill is 95 m and its shadow is 65 m then the angle of elevation of sun at that particular moment is |
| A. | 55.62 m |
| B. | 58.62 m |
| C. | 62.36 m |
| D. | 65.85 m |
| Answer» B. 58.62 m | |
| 256. |
The answer of sin 62° up to four significant figures is |
| A. | 0.8829 |
| B. | 0.7829 |
| C. | 0.6829 |
| D. | 0.9258 |
| Answer» B. 0.7829 | |
| 257. |
If sin X is 1.578 then the value of angle X in a right angle triangle is |
| A. | 68° |
| B. | not possible |
| C. | 55° |
| D. | 85° |
| Answer» C. 55° | |
| 258. |
In a right angle triangle ABC, the hypotenuse is 15 and adjacent side is 'x' then A 74° is |
| A. | 3.148 |
| B. | 1.347 |
| C. | 4.134 |
| D. | 5.134 |
| Answer» D. 5.134 | |
| 259. |
If a building is 83 m high then the angle of elevation from point A (on level ground) which is 260 m away from the building is |
| A. | 70° |
| B. | 17.7° |
| C. | 19.70° |
| D. | 23.52° |
| Answer» C. 19.70° | |
| 260. |
By solving the inequality 5a - 4 > 6, the value of 'a' is |
| A. | greater than 2 |
| B. | less than 2 |
| C. | greater than 5 |
| D. | less than 6 |
| Answer» B. less than 2 | |
| 261. |
By solving the inequality 1⁄4(2 - x) > 1⁄3(4 - x) + 1⁄2, the answer will be |
| A. | x > 18 |
| B. | x > 16 |
| C. | x > 14 |
| D. | x > 11 |
| Answer» C. x > 14 | |
| 262. |
An engineering test consist of 100 questions. 2 points are awarded for correct answer and 1 point is deducted for wrongly answered questions. Ana attempted 85 questions and her total score was above 160. The minimum number of correct answers are |
| A. | x gt; 85 |
| B. | x gt; 86 |
| C. | x gt; 88 |
| D. | x gt; 82 |
| Answer» E. | |
| 263. |
By solving the inequality -8 + 2x < 16 - x, the answer will be |
| A. | x > 4 |
| B. | x < 10 |
| C. | x < 8 |
| D. | x > 6 |
| Answer» D. x > 6 | |
| 264. |
By solving the inequality a + 2 < 5, the value of 'a' must be |
| A. | greater than 5 |
| B. | less than 5 |
| C. | greater than 3 |
| D. | less than 3 |
| Answer» E. | |
| 265. |
Consider a right angle triangle XYZ, XY is 17 and XZ is supposed as unknown number 'a' then X 54.26° up to three significant figures is |
| A. | 25.1 |
| B. | 26.1 |
| C. | 27.1 |
| D. | 29.1 |
| Answer» E. | |
| 266. |
The answer of tan 40° up to three significant figures is |
| A. | 0.583 |
| B. | 0.839 |
| C. | 1.839 |
| D. | 2.839 |
| Answer» C. 1.839 | |
| 267. |
The corporate office building is 50m high and angle of elevation at top of building is 52° when seen from a point on level ground. The distance between point and foot of the building is |
| A. | 21.35 m |
| B. | 52 m |
| C. | 25 m |
| D. | 31.25 m |
| Answer» E. | |
| 268. |
The cos P of triangle PQR with respect to P is calculated as |
| A. | QR/PQ |
| B. | QR/PR |
| C. | PQ/PR |
| D. | PR/PQ |
| Answer» D. PR/PQ | |
| 269. |
Consider a right angle triangle PQR, if PQ is 27 and QR is 17 then the value of angle P is |
| A. | 32.19° |
| B. | 45.19° |
| C. | 49.58° |
| D. | 62.46° |
| Answer» B. 45.19° | |
| 270. |
Considering radian, the value of sin 1.9 is |
| A. | 0.386 |
| B. | 0.258 |
| C. | 0.946 |
| D. | 2.876 |
| Answer» D. 2.876 | |
| 271. |
The sum of 45 nanometers and 75 picometers (in standard form) is |
| A. | 4.5075 x 10-8 |
| B. | 4.5075 x 10-6 |
| C. | 4.5075 x 10-7 |
| D. | 4.5075 x 10-9 |
| Answer» B. 4.5075 x 10-6 | |
| 272. |
The answer of (4.88 x 8.79 )/(2.118 /8.37 ) is |
| A. | 3.47 x 10-5 |
| B. | 3.47 x 10² |
| C. | 3.47 x 10-4 |
| D. | 3.47 x 10-2 |
| Answer» C. 3.47 x 10-4 | |
| 273. |
By evaluating the (3⁄4)-2 x (2)0, the result will be |
| A. | 16⁄9 |
| B. | 9⁄16 |
| C. | 1⁄2 |
| D. | 2 |
| Answer» B. 9⁄16 | |
| 274. |
The answer of 6.2 x 10-5 in ordinary notation is |
| A. | 0.0000062 |
| B. | 0.000062 |
| C. | 0.00062 |
| D. | 0.0062 |
| Answer» C. 0.00062 | |
| 275. |
By simplifying the b3⁄5 x b-4⁄3, the answer will be |
| A. | b-11⁄15 |
| B. | b-11⁄13 |
| C. | b-9⁄13 |
| D. | b-7⁄12 |
| Answer» B. b-11⁄13 | |
| 276. |
By simplifying the x1⁄3 x x2⁄3, the answer will be |
| A. | x³ |
| B. | 1 |
| C. | x² |
| D. | x |
| Answer» E. | |
| 277. |
By expressing the sin 170° in terms of trigonometrical ratios, the answer will be |
| A. | sin 10° = 0.1631 |
| B. | sin 10° = 0.1736 |
| C. | sin 10° = 0.3761 |
| D. | sin 10° = 1.7362 |
| Answer» C. sin 10° = 0.3761 | |
| 278. |
The dimensions of plane includes |
| A. | breadth and length |
| B. | length only |
| C. | breadth only |
| D. | depth and length |
| Answer» B. length only | |
| 279. |
The product of 2a6 b4 and a7 b8 is |
| A. | 4a10 b7 |
| B. | 4a11 b12 |
| C. | 2a19 b15 |
| D. | 2a13 b12 |
| Answer» E. | |
| 280. |
By solving (3x²)³ x 3x², the answer will be |
| A. | 81x5 |
| B. | 81x4 |
| C. | 81x8 |
| D. | 81x6 |
| Answer» D. 81x6 | |
| 281. |
By simplifying the (x²)5, the answer will be |
| A. | x12 |
| B. | x7 |
| C. | x10 |
| D. | x12 |
| Answer» D. x12 | |
| 282. |
The answer of 2(3.4 x 107 ) in ordinary notation is |
| A. | 0.068 |
| B. | 0.0068 |
| C. | 6800 |
| D. | 0.00068 |
| Answer» C. 6800 | |
| 283. |
By simplifying the (a6 b5 )³, the answer will be |
| A. | a18 b15 |
| B. | a8 b4 |
| C. | a12 b4 |
| D. | a10 b³ |
| Answer» B. a8 b4 | |
| 284. |
By solving the following (4x9 ) x (x²) ⁄x5, the answer will be |
| A. | 8x5 |
| B. | 9x6 |
| C. | 4x16 |
| D. | 4x6 |
| Answer» E. | |
| 285. |
By simplifying the 18x10 ⁄(3x4 )², the answer will be |
| A. | 2x³ |
| B. | 2x² |
| C. | 2x4 |
| D. | 2x5 |
| Answer» C. 2x4 | |
| 286. |
By solving a8 ⁄a, the quotient will be |
| A. | a10 |
| B. | a9 |
| C. | a7 |
| D. | a11 |
| Answer» D. a11 | |
| 287. |
The answer of 18.285 / 4.56³ is |
| A. | 2.15 x 104 |
| B. | 2.15 x 105 |
| C. | 2.15 x 107 |
| D. | 2.15 x 106 |
| Answer» B. 2.15 x 105 | |
| 288. |
By expressing the ³√64x18 in index form, the answer will be |
| A. | 4x³ |
| B. | 4x6 |
| C. | 4x5 |
| D. | 4x² |
| Answer» C. 4x5 | |
| 289. |
By evaluating 4 sin 25° + 5 tan 35°, the answer will be |
| A. | 1.1915 |
| B. | 3.1915 |
| C. | 4.1915 |
| D. | 5.1915 |
| Answer» E. | |
| 290. |
By solving the inequality 2(a⁄2 + 3⁄4) > 4(a⁄4 - 6), the answer will be |
| A. | a > -68 |
| B. | a > -48 |
| C. | a > -78 |
| D. | a > -56 |
| Answer» D. a > -56 | |
| 291. |
By solving the inequality 4x - 16 < 0, the answer will be |
| A. | x < 11 |
| B. | x > 6 |
| C. | x > 4 |
| D. | x < 4 |
| Answer» E. | |
| 292. |
By solving the inequality (2x + 3⁄4) - (x + 2⁄2) > 1 - (x + 3⁄2), the answer will be |
| A. | x < 15 |
| B. | x > 22 |
| C. | x < 22 |
| D. | x < 18 |
| Answer» D. x < 18 | |
| 293. |
If x < 25 and 25 < b then |
| A. | b = 0 |
| B. | a = 0 |
| C. | a < b |
| D. | a > b |
| Answer» D. a > b | |
| 294. |
In 2014, 200 workers received pays on hourly basis from $15/hour to $25/hour according to the difficulty of assigned tasks. The least possible amount paid to the workers for 10 working hours is |
| A. | $180 |
| B. | $150 |
| C. | $140 |
| D. | $115 |
| Answer» C. $140 | |
| 295. |
By evaluating cos 68° + sin 72°/tan 58° + cos 47°, the answer will be |
| A. | 1.5852 |
| B. | 0.588 |
| C. | 0.8085 |
| D. | 0.5808 |
| Answer» E. | |
| 296. |
In a right-angled triangle XYZ with respect to X, the cosine of the angle A is calculated as |
| A. | adjacent side/hypotenuse |
| B. | opposite side/hypotenuse |
| C. | opposite side/adjacent side |
| D. | hypotenuse + adjacent side |
| Answer» B. opposite side/hypotenuse | |
| 297. |
The only trigonometrical ratio whose value can be greater than 1 is |
| A. | cosine |
| B. | sine |
| C. | tangent |
| D. | none of the above |
| Answer» D. none of the above | |
| 298. |
If a building is 65m above the ground level and the angle of depression of loader truck on level ground is 51° then the distance of loader truck from the building is |
| A. | 50.23 m |
| B. | 48.23 m |
| C. | 52.63 m |
| D. | 55.63m |
| Answer» D. 55.63m | |
| 299. |
In a right angle triangle ABC, the BC is supposed as 'x' and AC is 15 then A 65° is |
| A. | 14.59 |
| B. | 16.59 |
| C. | 15.59 |
| D. | 13.59 |
| Answer» E. | |
| 300. |
By solving the inequality 2(x + 2) < 3(x + 1) + 8, the answer will be |
| A. | x < -9 |
| B. | x > -7 |
| C. | x > -13 |
| D. | x < -6 |
| Answer» D. x < -6 | |