MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 330 Mcqs, each offering curated multiple-choice questions to sharpen your Grade8 knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
By solving the 274 ⁄94, the answer will be |
| A. | 34 |
| B. | 3² |
| C. | 45 |
| D. | 4³ |
| Answer» B. 3² | |
| 52. |
By solving the (6a4 )², the answer will be |
| A. | 36x5 |
| B. | 36x8 |
| C. | 36x7 |
| D. | 36x9 |
| Answer» C. 36x7 | |
| 53. |
By expressing the answer in form of 10n, the answer of 108 ⁄10-2 x104 is |
| A. | 10³ |
| B. | 104 |
| C. | 106 |
| D. | 105 |
| Answer» D. 105 | |
| 54. |
The answer of 0.0523 in standard form is |
| A. | 5.23 x 10-2 |
| B. | 5.23 x 10-3 |
| C. | 5.23 x 10-4 |
| D. | 5.23 x 10-5 |
| Answer» B. 5.23 x 10-3 | |
| 55. |
If x4 y³ is dividend and x²y is divisor then the quotient is |
| A. | x²y² |
| B. | x³y5 |
| C. | x4 y² |
| D. | x6 y4 |
| Answer» B. x³y5 | |
| 56. |
If the circumference of circle is 64π then the area of circle (in terms of π) is |
| A. | 664 cm² |
| B. | 1024π cm² |
| C. | 1050π cm² |
| D. | 512π cm² |
| Answer» C. 1050π cm² | |
| 57. |
The value of tan π⁄7 considering radian is |
| A. | 0.357 |
| B. | 0.768 |
| C. | 0.481 |
| D. | 0.274 |
| Answer» D. 0.274 | |
| 58. |
The chord divides the circle into |
| A. | two segments |
| B. | three segments |
| C. | four segments |
| D. | five segments |
| Answer» B. three segments | |
| 59. |
The largest part of the circle divided by the chord is called |
| A. | circumference |
| B. | quadrant |
| C. | minor segment |
| D. | major segment |
| Answer» E. | |
| 60. |
If the radius is 18 cm and the angle at center of circle is 120° then the area of sector is |
| A. | 382.4 cm² |
| B. | 339.3 cm² |
| C. | 350 cm² |
| D. | 300 cm² |
| Answer» C. 350 cm² | |
| 61. |
The tool which is used to make indirect measurements of height and distance is called |
| A. | comparative geology |
| B. | trigonometry |
| C. | geometry |
| D. | none of the above |
| Answer» C. geometry | |
| 62. |
The product of sin 61° and tan 58° up to five significant figures is |
| A. | 3.7997 |
| B. | 3.9197 |
| C. | 1.3997 |
| D. | 2.3997 |
| Answer» D. 2.3997 | |
| 63. |
A distance between light house and a certain point is 30 m. If the angle of elevation of the top of the lighthouse is 57° then the height of the pole is |
| A. | 19.46 m |
| B. | 66.52 m |
| C. | 46.19 m |
| D. | 85.23 m |
| Answer» D. 85.23 m | |
| 64. |
If tan A is 1.847 then the value of angle A in a right angle triangle is |
| A. | 83.27° |
| B. | 75.63° |
| C. | 57.48° |
| D. | 61.57° |
| Answer» E. | |
| 65. |
The answer of tan 73.65° up to four significant figures is |
| A. | 2.408 |
| B. | 4.904 |
| C. | 2.409 |
| D. | 3.409 |
| Answer» E. | |
| 66. |
By solving the 79 ⁄74 for negative indices, the answer will be |
| A. | 1/7-4 |
| B. | 1/7-5 |
| C. | 1/7-6 |
| D. | 1/7-3 |
| Answer» C. 1/7-6 | |
| 67. |
The product of 5x4 and 6x5 is |
| A. | 11x9 |
| B. | 30x20 |
| C. | 30x9 |
| D. | 30x² |
| Answer» D. 30x² | |
| 68. |
By solving the following (a³)³ ⁄a, the answer will be |
| A. | a10 |
| B. | a11 |
| C. | a8 |
| D. | a6 |
| Answer» D. a6 | |
| 69. |
The product of 5³ x 55 is |
| A. | 5³ |
| B. | 5² |
| C. | 58 |
| D. | 515 |
| Answer» D. 515 | |
| 70. |
By simplifying the (x³y²)² for negative indices, the answer will be |
| A. | x-6 y-4 |
| B. | 1/x-5 y-3 |
| C. | 1/x-4 y-2 |
| D. | 1/x-6 y-4 |
| Answer» E. | |
| 71. |
The answer of 4.38 x 104 in ordinary notation is |
| A. | 43800 |
| B. | 438 |
| C. | 4380 |
| D. | 438000 |
| Answer» B. 438 | |
| 72. |
By solving the following xy8 ⁄xy4 |
| A. | y-4 |
| B. | 1/y-4 |
| C. | 1/y4 |
| D. | 1/y-3 |
| Answer» C. 1/y4 | |
| 73. |
By simplifying the √4 x √5, the answer in radical form will be |
| A. | √4 + √5 |
| B. | √4 x 5 |
| C. | √4 - 5 |
| D. | 4² + 5² |
| Answer» C. √4 - 5 | |
| 74. |
If 125a = 625 then the value of 'a' is |
| A. | 4 1/3 |
| B. | 3 1/4 |
| C. | 2 1/3 |
| D. | 1 1/3 |
| Answer» E. | |
| 75. |
The answer of 412300 in standard form is |
| A. | 4.1 x 106 |
| B. | 4.1 x 106 |
| C. | 4.1 x 105 |
| D. | 4.1 x 107 |
| Answer» D. 4.1 x 107 | |
| 76. |
The product of 9.2 x 105 and 4.3 x 109 is |
| A. | 3.96 x 1011 |
| B. | 3.96 x 1013 |
| C. | 3.96 x 1019 |
| D. | 3.96 x 107 |
| Answer» C. 3.96 x 1019 | |
| 77. |
By simplifying the 3x-4 ⁄10y-4 for positive indices, the answer will be |
| A. | 3/10(y/x)4 |
| B. | 10/3(y/x)4 |
| C. | 10/3(x/y)4 |
| D. | (3x/10y)4 |
| Answer» B. 10/3(y/x)4 | |
| 78. |
If 4x = 1⁄64 then the value of 'x' is |
| A. | -1 |
| B. | -4 |
| C. | -3 |
| D. | -2 |
| Answer» D. -2 | |
| 79. |
If 52a10 is divided by 4a8 then the answer will be |
| A. | 15a² |
| B. | 18a² |
| C. | 21a² |
| D. | 13a² |
| Answer» E. | |
| 80. |
The product of a5 b² and a² is |
| A. | a³b² |
| B. | a4 b² |
| C. | a7 b² |
| D. | a10 b² |
| Answer» D. a10 b² | |
| 81. |
By simplifying the (xy²z)-3 ⁄(x³y³z³)-2, the answer will be |
| A. | x²y³ |
| B. | x-3 z-3 |
| C. | x³z³ |
| D. | x²z-3 |
| Answer» D. x²z-3 | |
| 82. |
By simplifying (2a³b4 )6 ⁄(4a³b)² x (a²b²), the answer will be |
| A. | 4a8 b18 |
| B. | 4a10 b20 |
| C. | 4a10 b15 |
| D. | 4a5 b8 |
| Answer» C. 4a10 b15 | |
| 83. |
By solving the (4x)³, the answer will be |
| A. | 84x² |
| B. | 64x² |
| C. | 64x4 |
| D. | 64x³ |
| Answer» E. | |
| 84. |
If 54x7 is divided by 6x² then the answer will be |
| A. | 9x9 |
| B. | 9x5 |
| C. | 5x9 |
| D. | 6x9 |
| Answer» C. 5x9 | |
| 85. |
By simplifying the following 2b4 x 8b7 ⁄16b5 x 2b³, the answer will be |
| A. | 3⁄2b³ |
| B. | 3⁄4b³ |
| C. | 1⁄2b³ |
| D. | 2b³ |
| Answer» D. 2b³ | |
| 86. |
In college library, 30% of books are classified as fiction and remainder as non-fiction. There are 2400 more books non-fiction category than fiction category. The total number of non-fiction books in library are |
| A. | 4500 |
| B. | 2200 |
| C. | 4200 |
| D. | 3200 |
| Answer» D. 3200 | |
| 87. |
To buy a home, Nelda borrowed $250,000 for 5 years and paid $60,000 simple interest on loan. The rate of interest he paid is |
| A. | 8.40% |
| B. | 6.80% |
| C. | 5.60% |
| D. | 4.80% |
| Answer» E. | |
| 88. |
If Ana sells her house at loss of 10% on cost and paid $125000 for it then its selling price is |
| A. | $117,500 |
| B. | $124,500 |
| C. | $112,500 |
| D. | $122,500 |
| Answer» D. $122,500 | |
| 89. |
A money changer exchanged Peso & Euro at rate of 3.9 peso = 1 Euro. The amount received in Peso for 3500 Euro is |
| A. | 16650 peso |
| B. | 13650 peso |
| C. | 14650 peso |
| D. | 15650 peso |
| Answer» C. 14650 peso | |
| 90. |
A money changer exchanged Indian Rupee and US$ at rate of 38..95 Indian Rupee = US$1. The amount received for US$180 in Indian Rupee is |
| A. | 8055 R |
| B. | 7055 R |
| C. | 7011 R |
| D. | 8011 R |
| Answer» D. 8011 R | |
| 91. |
The height of a light house is 65 m. The angles of elevation and depression of the top and foot of a radar mast are 52° and 30° respectively. The height of radar mast is |
| A. | 102 m |
| B. | 305 m |
| C. | 209.09 m |
| D. | 109.09 m |
| Answer» D. 109.09 m | |
| 92. |
A bundle of 10 balloons has string of 35 cm attached to it and makes and elevation angle of 40°. The distance of balloons from the holders hand is |
| A. | 38.50 cm |
| B. | 25.50 cm |
| C. | 22.50 cm |
| D. | 32.50 cm |
| Answer» D. 32.50 cm | |
| 93. |
The sin P of triangle PQR with respect to P is calculated as |
| A. | QR/PQ |
| B. | QR/PR |
| C. | PQ/PR |
| D. | PR/PQ |
| Answer» C. PQ/PR | |
| 94. |
Consider a right angle triangle XYZ, XY = a, YZ = b, XZ = 25.6 and angle of X is 37° then the values of a and b respectively are |
| A. | 19.604, 40.045 |
| B. | 18.604, 42.025 |
| C. | 17.406, 21.455 |
| D. | 15.406, 20.445 |
| Answer» E. | |
| 95. |
Considering a right-angled triangle ABC, if opposite side is '12' and adjacent side of triangle is supposed as 'x' then A 48° is |
| A. | 15.31 |
| B. | 17.31 |
| C. | 18.31 |
| D. | 19.31 |
| Answer» B. 17.31 | |
| 96. |
On evaluating the (512)1⁄3, the answer will be |
| A. | 1⁄4 |
| B. | 1⁄2 |
| C. | 8 |
| D. | 1⁄8 |
| Answer» D. 1⁄8 | |
| 97. |
By evaluating the (4⁄5)-2 ⁄(3)0, the result will be |
| A. | 1⁄16 |
| B. | 25⁄16 |
| C. | 16⁄25 |
| D. | 1⁄25 |
| Answer» C. 16⁄25 | |
| 98. |
By solving a x (a²)9, the answer will be |
| A. | a15 |
| B. | a19 |
| C. | a18 |
| D. | a20 |
| Answer» C. a18 | |
| 99. |
By solving the following (5a²b³)², the answer will be |
| A. | 25a5 b6 |
| B. | 25a4 b6 |
| C. | 25a7 b5 |
| D. | 25a³b4 |
| Answer» C. 25a7 b5 | |
| 100. |
The product of b and 5b³ is |
| A. | 5b4 |
| B. | 6b³ |
| C. | 6b4 |
| D. | 6b² |
| Answer» B. 6b³ | |