 
			 
			MCQOPTIONS
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				This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Mathematics Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
| 1. | A normal is drawn at a point P(x, y) of a curve. It meets the x-axis at Q. If PQ is of constant | 
| A. | length k. Then what is the differential equation describing such curve? | 
| B. | y(dy/dx) = ± √(k2 + x2) | 
| C. | y(dy/dx) = ± √(k2 – 2y2) | 
| D. | y(dy/dx) = ± √(k2 – y2) | 
| E. | Depends on the value of k | 
| Answer» D. y(dy/dx) = ± √(k2 – y2) | |
| 2. | What is the solution of the equation(y + x(√xy)(x + y))dx – (y + y(√xy)(x + y))dy = 0? | 
| A. | x2 + y2 = 2tan-1(√(y/x)) + c | 
| B. | x2 + y2 = 4tan-1(√(y/x)) + c | 
| C. | x2 + y2 = tan-1(√(y/x)) + c | 
| D. | x2 + y2 = 2tan-1(√(x/y)) + c | 
| Answer» C. x2 + y2 = tan-1(√(y/x)) + c | |
| 3. | What will be the value of x(x – 1)dy/dx – y = x2(x – 1)2? | 
| A. | xy = (x + 1)(x3/3 + c) | 
| B. | depends on x | 
| C. | depends on y | 
| D. | xy = (x – 1)(x3/3 + c) | 
| Answer» E. | |
| 4. | What will be the value of the differential equation dy/dx = (x + y)2/(x + 2)(y – 2)? | 
| A. | keY/X where, X = x + 2 and Y = y – 2 | 
| B. | ke2Y/X where, X = x + 2 and Y = y – 2 | 
| C. | ke2Y/X where, X = x and Y = 2y | 
| D. | ke2X/Y where, X = x – 2 and Y = y + 2 | 
| Answer» C. ke2Y/X where, X = x and Y = 2y | |
| 5. | What will be the general solution of differential equation for 2x – y dx + 2y – x dy = 0? | 
| A. | 22x + 22y = c | 
| B. | 2(22x + 22y) = c | 
| C. | 3(22x + 22y) = c | 
| D. | 4(22x + 22y) = c | 
| Answer» B. 2(22x + 22y) = c | |
| 6. | What is the value of the solution of dy/dx = (6x + 9y – 7)/(2x + 3y – 6)? | 
| A. | -c/3 | 
| B. | 3c/2 | 
| C. | 2c/3 | 
| D. | -2c/3 | 
| Answer» B. 3c/2 | |
| 7. | What is the differential equation whose solution represents the family c(y + c)2 = x3? | 
| A. | [2x/3 *(dy/dx) – y][x/3 *dy/dx]2 = x3 | 
| B. | [x/3 *(dy/dx) – y][x/3 *dy/dx]2 = x3 | 
| C. | [2x/3 *(dy/dx) – y][ 2x/3 *dy/dx]2 = x3 | 
| D. | [x/3 *(dy/dx) – y][ 2x/3 *dy/dx]2 = x3 | 
| Answer» D. [x/3 *(dy/dx) – y][ 2x/3 *dy/dx]2 = x3 | |