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This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Finite Element Method knowledge and support exam preparation. Choose a topic below to get started.
1. |
What is the reason for an element in the Serendipity family to have a smaller size of stiffness matrix compare to a similar element in the Lagrange family? |
A. | Absence of interior nodes |
B. | Modified element connectivity |
C. | Lesser interpolation functions |
D. | Irregular arrangements of nodes |
Answer» B. Modified element connectivity | |
2. |
Which nodes of the higher-order elements of the Lagrange family do not contribute to the inter-element connectivity? |
A. | Interior nodes |
B. | All nodes |
C. | Corner nodes |
D. | Intermediate nodes |
Answer» B. All nodes | |
3. |
What is the number of nodes present on the boundary of the Lagrange quadratic rectangular element used in FEM? |
A. | 1 |
B. | 4 |
C. | 8 |
D. | 9 |
Answer» D. 9 | |
4. |
Which option is not correct about the Lagrange family of triangular elements used in FEM? |
A. | 2<sup>nd</sup>-degree polynomial corresponds to 6 noded triangle |
B. | 0<sup>th</sup>-degree polynomial corresponds to 1 noded triangle |
C. | 1<sup>st</sup>-degree polynomial corresponds to 3 noded triangle |
D. | 3<sup>rd</sup>-degree polynomial corresponds to 9 noded triangle |
Answer» E. | |
5. |
Which option is not correct about the Lagrange rectangular element used in FEM? |
A. | Second-order Lagrange element has nine nodes |
B. | Zero-order Lagrange element has one node |
C. | First-order Lagrange element has four nodes |
D. | Third-order Lagrange element has fifteen nodes |
Answer» E. | |
6. |
In the Finite Element Method (FEM), if the geometry is represented by elements of a higher order than those used to approximate the field displacement variables, then it is called super-parametric formulation. |
A. | True |
B. | False |
Answer» B. False | |
7. |
In FEM, what are the elements in which the same shape functions describe the geometry and field displacement variables? |
A. | Iso-parametric |
B. | Axi-Symmetric |
C. | Super-parametric |
D. | Sub-parametric |
Answer» B. Axi-Symmetric | |
8. |
In FEM, which option is used to develop the Higher-order rectangular elements (i.e., rectangular elements with interpolation functions of higher degree) systematically? |
A. | A rectangular array of binomial coefficients |
B. | Galerkin method |
C. | Jacobi method |
D. | Delaunay triangulation |
Answer» B. Galerkin method | |
9. |
In FEM, what is the name of the shape function of an Euler-Bernoulli beam element? |
A. | Hermite cubic interpolation function |
B. | Lagrange cubic interpolation function |
C. | Consistent element functions |
D. | Quadratic interpolation functions |
Answer» B. Lagrange cubic interpolation function | |
10. |
In FEM, what is the name of the element specified by a polynomial of order two or more? |
A. | Nonlinear element |
B. | Higher-order element |
C. | Linear element |
D. | Master element |
Answer» C. Linear element | |
11. |
If the geometry and other parameters of an element are defined in terms of only one spatial coordinate, then the element is a one-dimensional element? |
A. | True |
B. | False |
Answer» B. False | |
12. |
In the FEM element library, what is the correct name for a three noded triangular element? |
A. | Linear strain triangular element |
B. | Constant strain triangular element |
C. | Variable strain triangular element |
D. | Higher-order triangular element |
Answer» C. Variable strain triangular element | |