MCQOPTIONS
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MCQOPTIONS
This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Signal Processing Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the causal signal x(n) having the z-transform X(z)=\(\frac{1}{(1+z^{-1})(1-z^{-1})^2}\)? |
| A. | [1/4(-1)n+3/4-n/2]u(n) |
| B. | [1/4(-1)n+3/4-n/2]u(-n-1) |
| C. | [1/4+3/4(-1)n-n/2]u(n) |
| D. | [1/4(-1)n+3/4+n/2]u(n) |
| Answer» E. | |
| 2. |
What is the inverse z-transform of X(z)=\(\frac{1}{1-1.5z^{-1}+0.5z^{-2}}\) if ROC is 0.5<|z|<1? |
| A. | -2u(-n-1)+(0.5)nu(n) |
| B. | -2u(-n-1)-(0.5)nu(n) |
| C. | -2u(-n-1)+(0.5)nu(-n-1) |
| D. | 2u(n)+(0.5)nu(-n-1) |
| Answer» C. -2u(-n-1)+(0.5)nu(-n-1) | |
| 3. |
What is the inverse z-transform of X(z)=\(\frac{1}{1-1.5z^{-1}+0.5z^{-2}}\) if ROC is |z|<0.5? |
| A. | [-2-0.5n]u(n) |
| B. | [-2+0.5n]u(n) |
| C. | [-2+0.5n]u(-n-1) |
| D. | [-2-0.5n]u(-n-1) |
| Answer» D. [-2-0.5n]u(-n-1) | |
| 4. |
What is the partial fraction expansion of X(z)=\(\frac{1}{(1+z^{-1})(1-z^{-1})^2}\)? |
| A. | \(\frac{z}{4(z+1)} + \frac{3z}{4(z-1)} + \frac{z}{2(z+1)^2}\) |
| B. | \(\frac{z}{4(z+1)} + \frac{3z}{4(z-1)} – \frac{z}{2(z+1)^2}\) |
| C. | \(\frac{z}{4(z+1)} + \frac{3z}{4(z-1)} + \frac{z}{2(z-1)^2}\) |
| D. | \(\frac{z}{4(z+1)} + \frac{z}{4(z-1)} + \frac{z}{2(z+1)^2}\) |
| Answer» D. \(\frac{z}{4(z+1)} + \frac{z}{4(z-1)} + \frac{z}{2(z+1)^2}\) | |
| 5. |
What is the partial fraction expansion of X(z)=\(\frac{1+z^{-1}}{1-z^{-1}+0.5z^{-2}}\)? |
| A. | \(\frac{z(0.5-1.5j)}{z-0.5-0.5j} – \frac{z(0.5+1.5j)}{z-0.5+0.5j}\) |
| B. | \(\frac{z(0.5-1.5j)}{z-0.5-0.5j} + \frac{z(0.5+1.5j)}{z-0.5+0.5j}\) |
| C. | \(\frac{z(0.5+1.5j)}{z-0.5-0.5j} – \frac{z(0.5-1.5j)}{z-0.5+0.5j}\) |
| D. | \(\frac{z(0.5+1.5j)}{z-0.5-0.5j} + \frac{z(0.5-1.5j)}{z-0.5+0.5j}\) |
| Answer» C. \(\frac{z(0.5+1.5j)}{z-0.5-0.5j} – \frac{z(0.5-1.5j)}{z-0.5+0.5j}\) | |
| 6. |
What is the partial fraction expansion of the proper function X(z)=\(\frac{1}{1-1.5z^{-1}+0.5z^{-2}}\)? |
| A. | \(\frac{2z}{z-1}-\frac{z}{z+0.5}\) |
| B. | \(\frac{2z}{z-1}+\frac{z}{z-0.5}\) |
| C. | \(\frac{2z}{z-1}+\frac{z}{z+0.5}\) |
| D. | \(\frac{2z}{z-1}-\frac{z}{z-0.5}\) |
| Answer» E. | |
| 7. |
What is the inverse z-transform of X(z)=log(1+az-1) |z|>|a|? |
| A. | x(n)=(-1)n+1 \(\frac{a^{-n}}{n}\), n≥1; x(n)=0, n≤0 |
| B. | x(n)=(-1)n-1 \(\frac{a^{-n}}{n}\), n≥1; x(n)=0, n≤0 |
| C. | x(n)=(-1)n+1 \(\frac{a^{-n}}{n}\), n≥1; x(n)=0, n≤0 |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 8. |
What is the inverse z-transform of X(z)=\(\frac{1}{1-1.5z^{-1}+0.5z^{-2}}\) if ROC is |z| < 0.5? |
| A. | {….62,30,14,6,2} |
| B. | {…..62,30,14,6,2,0,0} |
| C. | {0,0,2,6,14,30,62…..} |
| D. | {2,6,14,30,62…..} |
| Answer» C. {0,0,2,6,14,30,62…..} | |
| 9. |
What is the inverse z-transform of X(z)=\(\frac{1}{1-1.5z^{-1}+0.5z^{-2}}\) if ROC is |z|>1? |
| A. | {1,3/2,7/4,15/8,31/16,….} |
| B. | {1,2/3,4/7,8/15,16/31,….} |
| C. | {1/2,3/4,7/8,15/16,31/32,….} |
| D. | None of the mentioned |
| Answer» B. {1,2/3,4/7,8/15,16/31,….} | |