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This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Signals & Systems Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
1. |
Given x(t)=e-t u(t). Find the inverse Laplace transform of e-3s X(2s). |
A. | \(\frac{1}{2}\) e-(t-3)/2 u(t+3) |
B. | \(\frac{1}{2}\) e-(t-3)/2 u(t-3) |
C. | \(\frac{1}{2}\) e(t-3)/2 u(t-3) |
D. | \(\frac{1}{2}\) e(t-3)/2 u(t+3) |
Answer» C. \(\frac{1}{2}\) e(t-3)/2 u(t-3) | |
2. |
Find the inverse Laplace transform for the function X(s) = \(\frac{1+e^{-2s}}{3s^2+2s}\). |
A. | e-(2/3)t u(t) – u(t) + e-(2/3)(t-2) u(t-2)-u(t-2) |
B. | e-(2/3)t u(t) + e-(2/3)(t-2) u(t-2) |
C. | e-(2/3)(t-2) u(t-2) – u(t-2) |
D. | e-(2/3)t u(t) – u(t) |
Answer» B. e-(2/3)t u(t) + e-(2/3)(t-2) u(t-2) | |
3. |
Find the inverse Laplace transform for the function X(s) = \(\frac{2s-1}{s^2+4s+8}\). |
A. | e-2t cos2t u(t) – e-2t sin2t u(t) |
B. | 2e-2t cos2t u(t) – \(\frac{5}{2}\) e-2t sin2t u(t) |
C. | 2e-2t cos2t u(t) – e-2t sin2t u(t) |
D. | e-2t cos2t u(t) – \(\frac{5}{2}\) e-2t sin2t u(t) |
Answer» C. 2e-2t cos2t u(t) – e-2t sin2t u(t) | |
4. |
Find the inverse Laplace transform for X(s) = \(ln (\frac{s+a}{s+b})\). |
A. | \(\frac{e^{-at} – e^{-bt}}{t}\) |
B. | \(\frac{e^{-bt} – e^{-at}}{t}\) |
C. | \(\frac{e^{-at} + e^{-bt}}{t}\) |
D. | \(\frac{e^{bt} + e^{-at}}{t}\) |
Answer» C. \(\frac{e^{-at} + e^{-bt}}{t}\) | |
5. |
Find the inverse Laplace transform for X(s) = \(\frac{s}{2s^2-8}\). |
A. | cosh2t |
B. | \(\frac{1}{2}\) cosh2t |
C. | sinh2t |
D. | \(\frac{1}{2}\) sinh2t |
Answer» C. sinh2t | |
6. |
If F1 (s) = \(\frac{1}{s+2}\) and F2 (s) = \(\frac{1}{s+3}\), find the inverse Laplace transform of F(s) = F1 (s) F2 (s). |
A. | [e-2t + e-3t]u(t) |
B. | [e-2t – e-3t]u(t) |
C. | [e2t + e3t]u(t) |
D. | [e2t + e-3t]u(t) |
Answer» C. [e2t + e3t]u(t) | |
7. |
Find the inverse Laplace transform of X(s) = \(\frac{s}{(s^2+a^2)^2}\). |
A. | \(\frac{1}{a}\) t sinat |
B. | \(\frac{1}{2a}\) t sinat |
C. | \(\frac{1}{a}\) t cosat |
D. | \(\frac{1}{2a}\) t cosat |
Answer» C. \(\frac{1}{a}\) t cosat | |
8. |
Find the inverse Laplace transform of X(s) = \(\frac{s}{s^2 a^2+b^2}\). |
A. | \(\frac{1}{a^2} \,cos(\frac{a}{b})t\) |
B. | \(\frac{1}{a^2} \,cos(\frac{b}{a})t\) |
C. | \(\frac{1}{a^2} \,sin(\frac{b}{a})t\) |
D. | \(\frac{1}{a^2} \,sin(\frac{a}{b})t\) |
Answer» C. \(\frac{1}{a^2} \,sin(\frac{b}{a})t\) | |
9. |
Find the inverse Laplace transform for \(\frac{s}{(s+2)^2+1}\). |
A. | [2e-2t cost + e-2t sint]u(t) |
B. | [e-2t cost + 2e-2t sint]u(t) |
C. | [2e-2t cost – e-2t sint]u(t) |
D. | [e-2t cost – 2e-2t sint]u(t) |
Answer» E. | |
10. |
Find the inverse Laplace transform for \(\frac{s}{(s+2)^2}\). |
A. | te-t u(t) |
B. | e-t sint u(t) |
C. | e-2t (1-2t)u(t) |
D. | e2t (1-2t)u(t) |
Answer» D. e2t (1-2t)u(t) | |
11. |
Find the inverse Laplace transform for \(\frac{1}{(s+1)^2+1}\). |
A. | te-t u(t) |
B. | e-t sint u(t) |
C. | e-t cost u(t) |
D. | e-t u(t) |
Answer» C. e-t cost u(t) | |
12. |
Find the inverse Laplace transform for \(\frac{1}{(s+1)^2}\). |
A. | tet u(t) |
B. | te-t u(t) |
C. | tu(t) |
D. | et u(t) |
Answer» C. tu(t) | |