MCQOPTIONS
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MCQOPTIONS
This section includes 8 Mcqs, each offering curated multiple-choice questions to sharpen your Machine Dynamics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Torque due to weight of the connecting rod affects the torque due to connecting rod. |
| A. | True |
| B. | False |
| Answer» C. | |
| 2. |
Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 mFind angular acceleration of connecting rod in rad/s2. |
| A. | 16.782 |
| B. | 17.824 |
| C. | 15.142 |
| D. | 17.161 |
| Answer» C. 15.142 | |
| 3. |
From the data given:Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m ; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 m |
| A. | nFind the correcting couple in N-m? |
| B. | 52.7 |
| C. | 49.5 |
| D. | 59.5 |
| E. | 56.5 |
| Answer» D. 59.5 | |
| 4. |
Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 mFind the equivalent length L of a simple pendulum swung about an axis. |
| A. | 1.35 m |
| B. | 1.42 m |
| C. | 1.48 m |
| D. | 1.50 m |
| Answer» C. 1.48 m | |
| 5. |
For a steam engine, the following data is given:Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m ; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 m |
| A. | ncalculate inertia force at =30 degrees from IDC. |
| B. | 19000 N |
| C. | 19064 N |
| D. | 19032 N |
| E. | 20064 N |
| Answer» C. 19064 N | |
| 6. |
When mass of the reciprocating parts is neglected then the inertia force is _____ |
| A. | Maximum |
| B. | Minimum |
| C. | 0 |
| D. | Not defined |
| Answer» D. Not defined | |
| 7. |
Inertia forces on the reciprocating parts acts along the line of stroke. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 8. |
Force which does not act on the connecting rod is ______ |
| A. | Weight of connecting rod |
| B. | Inertia force of connecting rod |
| C. | Radial force |
| D. | Coriolis force |
| Answer» E. | |