Explore topic-wise MCQs in Farm Machinery.

This section includes 8 Mcqs, each offering curated multiple-choice questions to sharpen your Farm Machinery knowledge and support exam preparation. Choose a topic below to get started.

1.

Engines of different cylinder dimensions, power and speed can be compared on the basis of __________

A. maximum pressure
B. fuel consumption
C. mean effective pressure
D. unit power
Answer» D. unit power
2.

Which of the following is not a type of transmission dynamometer?

A. Epicyclic train dynamometer
B. Belt transmission dynamometer
C. Rope break dynamometer
D. Torsion dynamometer
Answer» D. Torsion dynamometer
3.

A four cylinder two- stroke cycle engine with a swept volume of 750 cm3 per cylinder gives a specific fuel consumption of 0.25 kg KW-1 h-1. When developing a brake mean effective mean pressure 650 kPa at 1500 rpm. What is the brake thermal efficiency, if the calorific value is 40 MJ kg-1?

A. 9%
B. 18%
C. 32%
D. 36%
Answer» E.
4.

What is the formula of controlling force (Fc) of a governor?

A. F<sub>c</sub> = n<sup>2</sup> r
B. F<sub>c</sub> = m r
C. F<sub>c</sub> = m <sup>2</sup> r
D. F<sub>c</sub> = m r<sup>2</sup>
Answer» D. F<sub>c</sub> = m r<sup>2</sup>
5.

What is the name of the phenomenon caused in a governor in which the speed of the engines fluctuates continuously above and below the mean speed?

A. Firing interval
B. Air-Supply measurement
C. Sensitiveness of Governor
D. Governor hunting
Answer» E.
6.

What is the formula for specific fuel consumption (i.s.f.c.)?

A. i.s.f.c.= ( frac{60 I.P.}{Wf} )
B. i.s.f.c.= ( frac{60 Wf}{I.P.} )
C. i.s.f.c.= ( frac{120 Wf}{I.P.} )
D. i.s.f.c.= ( frac{120 I.P.}{Wf} )
Answer» C. i.s.f.c.= ( frac{120 Wf}{I.P.} )
7.

What is value of n , if there is no missing cycle, in brake power when it is applied as double acting, two stroke engines?

A. 2N
B. N
C. N/2
D. 4N
Answer» B. N
8.

What is the formula for indicated mean effective pressure?

A. P<sub>i</sub> = ( frac{(Area , of , indicator , diagram)}{Length , of , indicator , diagram , * , spring , scale , index} )
B. P<sub>i</sub> = ( frac{(Length , of , indicator , diagram , * , spring , scale ,index)}{Area , of ,indicator , diagram} )
C. P<sub>i</sub> = ( frac{Length , of , indicator , diagram}{Area ,of ,indicator , diagram , * , spring , scale , index} )
D. P<sub>i</sub> = ( frac{Spring , scale , index}{Area , of , indicator , diagram , * , Length , of , indicator , diagram} )
Answer» B. P<sub>i</sub> = ( frac{(Length , of , indicator , diagram , * , spring , scale ,index)}{Area , of ,indicator , diagram} )