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This section includes 8 Mcqs, each offering curated multiple-choice questions to sharpen your Farm Machinery knowledge and support exam preparation. Choose a topic below to get started.
1. |
Engines of different cylinder dimensions, power and speed can be compared on the basis of __________ |
A. | maximum pressure |
B. | fuel consumption |
C. | mean effective pressure |
D. | unit power |
Answer» D. unit power | |
2. |
Which of the following is not a type of transmission dynamometer? |
A. | Epicyclic train dynamometer |
B. | Belt transmission dynamometer |
C. | Rope break dynamometer |
D. | Torsion dynamometer |
Answer» D. Torsion dynamometer | |
3. |
A four cylinder two- stroke cycle engine with a swept volume of 750 cm3 per cylinder gives a specific fuel consumption of 0.25 kg KW-1 h-1. When developing a brake mean effective mean pressure 650 kPa at 1500 rpm. What is the brake thermal efficiency, if the calorific value is 40 MJ kg-1? |
A. | 9% |
B. | 18% |
C. | 32% |
D. | 36% |
Answer» E. | |
4. |
What is the formula of controlling force (Fc) of a governor? |
A. | Fc = n2 ω r |
B. | Fc = m ω r |
C. | of a governor?a) Fc = n2 ω rb) Fc = m ω rc) Fc = m ω2 r |
D. | Fc = m ω r2 |
Answer» D. Fc = m ω r2 | |
5. |
What is the name of the phenomenon caused in a governor in which the speed of the engines fluctuates continuously above and below the mean speed? |
A. | Firing interval |
B. | Air-Supply measurement |
C. | Sensitiveness of Governor |
D. | Governor hunting |
Answer» E. | |
6. |
What is the formula for specific fuel consumption (i.s.f.c.)? |
A. | i.s.f.c.=\(\frac{60 I.P.}{Wf} \) |
B. | i.s.f.c.=\(\frac{60 Wf}{I.P.} \) |
C. | i.s.f.c.=\(\frac{120 Wf}{I.P.} \) |
D. | i.s.f.c.=\(\frac{120 I.P.}{Wf} \) |
Answer» C. i.s.f.c.=\(\frac{120 Wf}{I.P.} \) | |
7. |
What is value of ‘n’, if there is no missing cycle, in brake power when it is applied as double acting, two stroke engines? |
A. | 2N |
B. | N |
C. | N/2 |
D. | 4N |
Answer» B. N | |
8. |
What is the formula for indicated mean effective pressure? |
A. | Pi = \(\frac{(Area \, of \, indicator \, diagram)}{Length \, of \, indicator \, diagram \, * \, spring \, scale \, index} \) |
B. | Pi = \(\frac{(Length\, of \, indicator \, diagram \, * \, spring\, scale \,index)}{Area\, of \,indicator \, diagram} \) |
C. | Pi = \(\frac{Length \, of \, indicator \, diagram}{Area \,of \,indicator\, diagram \, * \, spring \, scale \, index} \) |
D. | Pi = \(\frac{Spring \, scale \, index}{Area \, of \, indicator \, diagram \, * \, Length \, of \, indicator \, diagram} \) |
Answer» B. Pi = \(\frac{(Length\, of \, indicator \, diagram \, * \, spring\, scale \,index)}{Area\, of \,indicator \, diagram} \) | |