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This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Analog Circuits knowledge and support exam preparation. Choose a topic below to get started.
1. |
Given a MOSFET where gate to source capacitance is 300 pF and gate to drain capacitance is 500 pF. Calculate the gain bandwidth product if the transconductance is 30 m -1. |
A. | 5.98 Mhz |
B. | 4.9 Mhz |
C. | 6.5Mhz |
D. | 5.22Mhz |
Answer» B. 4.9 Mhz | |
2. |
Gain bandwidth frequency is GBP= 3000 Mhz. The cut-off frequency is f=10Mhz. What is the CE short circuit current gain at the cutoff frequency? |
A. | 212 |
B. | 220 |
C. | 300 |
D. | 200 |
Answer» B. 220 | |
3. |
Given that =200, input frequency is f = 20Mhz and short circuit current gain is A = 100. What is the unity gain frequency? |
A. | 2308 Mhz |
B. | 2000 Mhz |
C. | 2508 Mhz |
D. | 3000 Mhz |
Answer» B. 2000 Mhz | |
4. |
For given BJT, =200. The applied input frequency is 20 Mhz and net internal capacitance is 100 pF. What is the CE short circuit current gain at cut-off frequency? |
A. | 200 |
B. | 100 |
C. | 141.42 |
D. | 440.2 |
Answer» D. 440.2 | |
5. |
Given that transition capacitance is 5 pico F and diffusion capacitance is 80 pico F, and base emitter dynamic resistance is 1500 , find the cut-off frequency. |
A. | 7.8 x 10<sup>6</sup> rad/s |
B. | 8.0 x 10<sup>6</sup> rad/s |
C. | 49.2 x 10<sup>6</sup> rad/s |
D. | 22.7 x 10<sup>6</sup> rad/s |
Answer» B. 8.0 x 10<sup>6</sup> rad/s | |
6. |
Consider a CE circuit, where trans-conductance is 50m -1, diffusion capacitance is 100 pF, transition capacitance is 3 pF. IB = 20 A. Given base emitter dynamic resistance, rbe = 1000 , input VI is 20*sin(107t). What is the short circuit current gain? |
A. | 30 |
B. | 35 |
C. | 40 |
D. | 100 |
Answer» C. 40 | |
7. |
We cannot use h-parameter model in high frequency analysis because ____________ |
A. | They all can be ignored for high frequencies |
B. | Junction capacitances are not included in it |
C. | Junction capacitances have to be included in it |
D. | AC analysis is difficult for high frequency using it |
Answer» C. Junction capacitances have to be included in it | |