MCQOPTIONS
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MCQOPTIONS
This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Analog Circuits knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
WHAT_WILL_BE_THE_OSCILLATOR_FREQUENCY_OF_HARTLEY_OSCILLATOR_IF_INDUCTANCE_L1,_L2_ARE_EQUAL_TO_1MH_AND_2MH_RESPECTIVELY_AND_CAPACITOR_C_IS_10NF._(NEGLECT_MUTUAL_INDUCTANCE)?$ |
| A. | 50KHz |
| B. | 57KHz |
| C. | 40KHz |
| D. | 1MHz |
| Answer» C. 40KHz | |
| 2. |
Example for a self-limiting oscillator i? |
| A. | Hartley oscillator |
| B. | Weinbridge Oscillator |
| C. | RC phase shift oscillator |
| D. | Astable multivibrator |
| Answer» B. Weinbridge Oscillator | |
| 3. |
The Hartley oscillator is less preferred than due to Colpitts oscillator’s performance in$ |
| A. | All frequency region |
| B. | Mid frequency region |
| C. | High frequency region |
| D. | Low frequency region |
| Answer» D. Low frequency region | |
| 4. |
Hartley oscillator make use of ________ amplifiers. |
| A. | Class A |
| B. | Class B |
| C. | Class C |
| D. | Class D |
| Answer» D. Class D | |
| 5. |
The phase difference produced by active element of Hartley oscillator is |
| A. | 0 degree |
| B. | 180 degree |
| C. | 90 degree |
| D. | 120 degree |
| Answer» C. 90 degree | |
| 6. |
The gain device in the Hartley oscillator act as a |
| A. | Low pass filter |
| B. | High pass filter |
| C. | Band pass filter |
| D. | Band rejection filter |
| Answer» D. Band rejection filter | |
| 7. |
Phase shift provided by overall tank circuit in Hartley oscillator is |
| A. | 0 degree |
| B. | 90 degree |
| C. | 180 degree |
| D. | -90 degree |
| Answer» D. -90 degree | |
| 8. |
Which configuration of transistor amplifier is used for Hartley oscillator? |
| A. | Common emitter amplifier |
| B. | Common collector amplifier |
| C. | Common base amplifier |
| D. | Combination of both common emitter and common collector |
| Answer» B. Common collector amplifier | |
| 9. |
If L1 and L2 are the capacitance used in Hartley oscillator the effective capacitance in the equation of frequency calculation is equal to (Without considering mutual index) |
| A. | (L1√óL2)/(L1+L2) |
| B. | L2<sup>2</sup>/(L1+L2) |
| C. | L1+L2 |
| D. | L1-L2 |
| Answer» D. L1-L2 | |