Statement: The time period of a pendulum on a satellite orbiting the earth is infinity.

Reason: The time period of a pendulum is inversely proportional to square to root of g.

Both statement and reason are true and the reason is the correct explanation of the statement

Both statement and reason are true but the reason is not the correct explanation of the statement

Statement is true, but the reason is false

A coin is placed on a horizontal platform, which undergoes vertical simple harmonic motion of angular frequency ω. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time.

At the highest position of the platform

At the mean position of the platform

A particle free to move along the x-axis has potential energy given by U(x) = k [1-exp -x2] for -∞≤x≤+∞, where k is a positive constant of appropriate dimensions. Then?

The particle is in unstable equilibrium at points away from the origin

There is a force directed away from the origin for any finite nonzero value of x

It has its minimum kinetic energy at the origin if its total mechanical energy is k/2

The motion is simple harmonic for small displacement from x=0

Explore topic-wise MCQs in Engineering Physics Questions and Answers.

This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Physics Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.

1.	Statement: The time period of a pendulum on a satellite orbiting the earth is infinity.
A.	Reason: The time period of a pendulum is inversely proportional to square to root of g.
B.	Both statement and reason are true and the reason is the correct explanation of the statement
C.	Both statement and reason are true but the reason is not the correct explanation of the statement
D.	Statement is true, but the reason is false
E.	Statement and reason are false
Answer» C. Both statement and reason are true but the reason is not the correct explanation of the statement

Discussion

2.	A coin is placed on a horizontal platform, which undergoes vertical simple harmonic motion of angular frequency ω. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time.
A.	For an amplitude of g2/ω2
B.	For an amplitude of g/ω2
C.	At the highest position of the platform
D.	At the mean position of the platform
Answer» C. At the highest position of the platform

Discussion

3.	A simple pendulum has a time period T1, when on the earth’s surface; and T2, when taken to a height R above the earth’s surface (R is the radius of the earth). The value of T2/T1 is?
A.	1
B.	√2
C.	4
D.	1
Answer» E.

Discussion

4.	A particle free to move along the x-axis has potential energy given by U(x) = k [1-exp -x2] for -∞≤x≤+∞, where k is a positive constant of appropriate dimensions. Then?
A.	The particle is in unstable equilibrium at points away from the origin
B.	There is a force directed away from the origin for any finite nonzero value of x
C.	It has its minimum kinetic energy at the origin if its total mechanical energy is k/2
D.	The motion is simple harmonic for small displacement from x=0
Answer» E.

Discussion

5.	A particle executes simple harmonic motion between x = -A and x = +A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then?
A.	T1 < T2
B.	T1 > T2
C.	T1=T2
D.	T1=2T2
Answer» B. T1 > T2

Discussion

Explore topic-wise MCQs in Engineering Physics Questions and Answers.

Statement: The time period of a pendulum on a satellite orbiting the earth is infinity.

A coin is placed on a horizontal platform, which undergoes vertical simple harmonic motion of angular frequency ω. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time.

A simple pendulum has a time period T1, when on the earth’s surface; and T2, when taken to a height R above the earth’s surface (R is the radius of the earth). The value of T2/T1 is?

A particle free to move along the x-axis has potential energy given by U(x) = k [1-exp -x2] for -∞≤x≤+∞, where k is a positive constant of appropriate dimensions. Then?

A particle executes simple harmonic motion between x = -A and x = +A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then?