Statement: The time period of a pendulum on a satellite orbiting the earth is infinity.Reason: The time period of a pendulum is inversely proportional to square to root of g.

Statement is true, but the reason is false

Both statement and reason are true and the reason is the correct explanation of the statement

Both statement and reason are true but the reason is not the correct explanation of the statement

Statement is true, but the reason is false

If a particle is oscillating on the same horizontal plane in the ground ___________

It has neither kinetic nor potential energies

It has only kinetic energy but no potential energy

It has only potential energy but no kinetic energy

It has both kinetic and potential energies

It has neither kinetic nor potential energies

A child swinging on a swing stands up. Then the time period of the swing will ___________

Increase, if the child is long and decreases if the child is short

A coin is placed on a horizontal platform, which undergoes vertical simple harmonic motion of angular frequency . The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time.

At the highest position of the platform

At the mean position of the platform

A particle free to move along the x-axis has potential energy given by U(x) = k [1-exp -x2] for - x + , where k is a positive constant of appropriate dimensions. Then?

The particle is in unstable equilibrium at points away from the origin

There is a force directed away from the origin for any finite nonzero value of x

It has its minimum kinetic energy at the origin if its total mechanical energy is k/2

The motion is simple harmonic for small displacement from x=0

Explore topic-wise MCQs in Engineering Physics.

This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Physics knowledge and support exam preparation. Choose a topic below to get started.

1.	A spring 40mm long is stretched by the acceleration of a force. If 10N force is required to stretch the spring through 1mm, then work done in stretching through 40mm is?
A.	84J
B.	48J
C.	24J
D.	8J
Answer» E.

Discussion

2.	Statement: The time period of a pendulum on a satellite orbiting the earth is infinity. Reason: The time period of a pendulum is inversely proportional to square to root of g.
A.	Both statement and reason are true and the reason is the correct explanation of the statement
B.	Both statement and reason are true but the reason is not the correct explanation of the statement
C.	Statement is true, but the reason is false
D.	Statement and reason are false
Answer» C. Statement is true, but the reason is false

Discussion

3.	If the length of simple pendulum is tripled, what will be its new time period in terms of original period T?
A.	0.7T
B.	1.73T
C.	T/2
D.	T
Answer» C. T/2

Discussion

4.	If a particle is oscillating on the same horizontal plane in the ground ___________
A.	It has only kinetic energy but no potential energy
B.	It has only potential energy but no kinetic energy
C.	It has both kinetic and potential energies
D.	It has neither kinetic nor potential energies
Answer» D. It has neither kinetic nor potential energies

Discussion

5.	A child swinging on a swing stands up. Then the time period of the swing will ___________
A.	Increase
B.	Decrease
C.	Remain the same
D.	Increase, if the child is long and decreases if the child is short
Answer» C. Remain the same

Discussion

6.	A coin is placed on a horizontal platform, which undergoes vertical simple harmonic motion of angular frequency . The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time.
A.	For an amplitude of g<sup>2</sup>/ <sup>2</sup>
B.	For an amplitude of g/ <sup>2</sup>
C.	At the highest position of the platform
D.	At the mean position of the platform
Answer» C. At the highest position of the platform

Discussion

7.	A simple pendulum has a time period T₁, when on the earth s surface; and T₂, when taken to a height R above the earth s surface (R is the radius of the earth). The value of T₂/T₁ is?
A.	1
B.	2
C.	4
D.	1
Answer» E.

Discussion

8.	A particle free to move along the x-axis has potential energy given by U(x) = k [1-exp -x²] for - x + , where k is a positive constant of appropriate dimensions. Then?
A.	The particle is in unstable equilibrium at points away from the origin
B.	There is a force directed away from the origin for any finite nonzero value of x
C.	It has its minimum kinetic energy at the origin if its total mechanical energy is k/2
D.	The motion is simple harmonic for small displacement from x=0
Answer» E.

Discussion

9.	A particle executes simple harmonic motion between x = -A and x = +A. The time taken for it to go from 0 to A/2 is T₁ and to go from A/2 to A is T₂. Then?
A.	T<sub>1</sub> < T<sub>2</sub>
B.	T<sub>1</sub> > T<sub>2</sub>
C.	T<sub>1</sub>=T<sub>2</sub>
D.	T<sub>1</sub>=2T<sub>2</sub>
Answer» B. T<sub>1</sub> > T<sub>2</sub>

Discussion

Explore topic-wise MCQs in Engineering Physics.

A spring 40mm long is stretched by the acceleration of a force. If 10N force is required to stretch the spring through 1mm, then work done in stretching through 40mm is?

Statement: The time period of a pendulum on a satellite orbiting the earth is infinity.Reason: The time period of a pendulum is inversely proportional to square to root of g.

If the length of simple pendulum is tripled, what will be its new time period in terms of original period T?

If a particle is oscillating on the same horizontal plane in the ground ___________

A child swinging on a swing stands up. Then the time period of the swing will ___________

A coin is placed on a horizontal platform, which undergoes vertical simple harmonic motion of angular frequency . The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time.

A simple pendulum has a time period T1, when on the earth s surface; and T2, when taken to a height R above the earth s surface (R is the radius of the earth). The value of T2/T1 is?

A particle free to move along the x-axis has potential energy given by U(x) = k [1-exp -x2] for - x + , where k is a positive constant of appropriate dimensions. Then?

A particle executes simple harmonic motion between x = -A and x = +A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then?

Statement: The time period of a pendulum on a satellite orbiting the earth is infinity.
Reason: The time period of a pendulum is inversely proportional to square to root of g.

A simple pendulum has a time period T₁, when on the earth s surface; and T₂, when taken to a height R above the earth s surface (R is the radius of the earth). The value of T₂/T₁ is?

A particle free to move along the x-axis has potential energy given by U(x) = k [1-exp -x²] for - x + , where k is a positive constant of appropriate dimensions. Then?

A particle executes simple harmonic motion between x = -A and x = +A. The time taken for it to go from 0 to A/2 is T₁ and to go from A/2 to A is T₂. Then?