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This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Chemistry knowledge and support exam preparation. Choose a topic below to get started.
1. |
Write 1 Faraday in terms of coulombs. |
A. | 96500 C |
B. | 95600 C |
C. | 9560 C |
D. | 9650 C |
Answer» B. 95600 C | |
2. |
In the equation, G = 2.303 RT logK, what is K? |
A. | change in temperature |
B. | kelvin |
C. | equilibrium constant |
D. | change in enthalpy |
Answer» D. change in enthalpy | |
3. |
Calculate the Gibbs free energy for the conversion of oxygen to Ozone at room temperature if KP is given as 2.47 x 10-29. |
A. | 163 kJ/mol |
B. | 163 J/mol |
C. | 163 kJ |
D. | 163 k/mol |
Answer» B. 163 J/mol | |
4. |
The Gibbs free energy is positive when a change in enthalpy and change in entropy are positive at ____________ |
A. | high temperatures |
B. | low temperature |
C. | all temperatures |
D. | only at 0 Kelvin |
Answer» C. all temperatures | |
5. |
Which of the following is not a type of exergonic reaction? |
A. | formation of table salt from Sodium and chlorine |
B. | combustion reaction |
C. | chemiluminescence |
D. | photosynthesis |
Answer» E. | |
6. |
The melting of ice into liquid water is an example of tube _______________ reaction. |
A. | endergonic |
B. | exergonic |
C. | exothermic |
D. | endothermic |
Answer» B. exergonic | |
7. |
In a reaction, the change in entropy is given as 2.4 cal/K and the change in Gibbs free energy is given as 3.4 kcal, calculate the change in heat at the temperature of 20-degree centigrade? |
A. | 3.4 kcal |
B. | 3.4 cal |
C. | 3.4 kJ |
D. | 3.4 J |
Answer» B. 3.4 cal | |
8. |
Calculate the Gibbs free energy for the reaction of conversion of ATP into ADP at 293 Kelvin the change in enthalpy is 19.07 Kcal and the change in entropy is 90 cal per Kelvin. |
A. | 7.3 cal |
B. | -5.3 Kcal |
C. | 7.3 Kcal |
D. | -7.3 Kcal |
Answer» E. | |
9. |
Find out whether the following reaction is spontaneous or not at 127 degrees centigrade? N2(g) + 3H2(g) ( rightleftharpoons ) 2NH3(g); H = 92.22 kJ/mol and S = -198.75 J/K-mol. |
A. | it is spontaneous |
B. | it is not spontaneous |
C. | it may be spontaneous |
D. | cannot predict |
Answer» C. it may be spontaneous | |