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This section includes 62 Mcqs, each offering curated multiple-choice questions to sharpen your DNA Sequencing, Mutation and Repair knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
DNA ligase IV has been studied for its role in what process specifically? |
| A. | Homologous recombination |
| B. | Homology directed DNA repair |
| C. | None of the other answers |
| D. | Non-homologous end joining DNA repair |
| Answer» E. | |
| 52. |
Which of the following is true with regards to the leading strand during DNA replication? |
| A. | It does not require an RNA primer. |
| B. | It requires the joining of Okazaki fragments. |
| C. | It can read the template strand in the 5' to 3' direction. |
| D. | It only requires one DNA polymerase III in order to complete the strand. |
| Answer» E. | |
| 53. |
Why do microsatellites, such as the one that causes Huntington's disease, occur in genomes? |
| A. | Microsatellites are caused by insertion of DNA material by viruses |
| B. | Microsatellites are a result of very slow evolutionary processes |
| C. | The body is better able to interpret microsatellite sequences into proteins, so they are more common in the genome |
| D. | DNA polymerase "stutters" on repeated bases during DNA replication and adds or deletes bases |
| Answer» E. | |
| 54. |
Upon a double-stranded DNA break, a cell can repair the DNA by resecting damaged DNA by nucleases and resynthesis of DNA by DNA polymerase. Next, DNA ligase binds the resynthesized fragment to the original DNA strand. What best describes this process? |
| A. | Selective autophagy |
| B. | Non-homologous end joining repair |
| C. | Homologous recombination |
| D. | Homology-directed repair |
| Answer» C. Homologous recombination | |
| 55. |
What is the main reason for there being both a leading and a lagging strand during DNA replication? |
| A. | DNA polymerase can only read in the 3'-to-5' direction |
| B. | DNA polymerase can only synthesize one strand at a time |
| C. | Only one strand is available to be read at any given time |
| D. | There are not enough RNA primers to have both strands be synthesized simultaneously |
| Answer» B. DNA polymerase can only synthesize one strand at a time | |
| 56. |
Which of the following has the self-repairing mechanisms? |
| A. | DNA and RNA |
| B. | DNA, RNA and protein |
| C. | Only DNA |
| D. | DNA and proteins |
| Answer» D. DNA and proteins | |
| 57. |
What is the function of enzyme involved in base excision repair? |
| A. | Addition of correct base |
| B. | Addition of correct nucleotide |
| C. | Removal of incorrect base |
| D. | Removal of phosphodiester bond |
| Answer» D. Removal of phosphodiester bond | |
| 58. |
Which of the following mechanisms will remove uracil and incorporate the correct base? |
| A. | Direct repair |
| B. | Base excision repair |
| C. | Mismatch repair |
| D. | Nucleotide excision repair |
| Answer» C. Mismatch repair | |
| 59. |
If the mutation has a negligible effect on the function of a gene, it is known as a ____________ |
| A. | Silent mutation |
| B. | Frame shift mutation |
| C. | Substitution mutation |
| D. | Insertion mutation |
| Answer» B. Frame shift mutation | |
| 60. |
An alteration in a nucleotide sequence that changes a triplet coding for an amino acid into a termination codon is ____________ |
| A. | Nonsense mutation |
| B. | Mutagenesis |
| C. | Mutation |
| D. | Mutagen |
| Answer» B. Mutagenesis | |
| 61. |
The DNA polymerase involved in base excision repair is ____________ |
| A. | DNA polymerase |
| B. | DNA polymerase |
| C. | DNA polymerase |
| D. | DNA polymerase |
| Answer» C. DNA polymerase | |
| 62. |
The one gene one polypeptide theory states that |
| A. | the synthesis of each gene is catalyzed by one specific enzyme. |
| B. | the synthesis of each enzyme is catalyzed by one specific gene. |
| C. | the function of an individual gene is to dictate the production of a specific polypeptide. |
| D. | each polypeptide catalyzes a specific reaction. |
| Answer» D. each polypeptide catalyzes a specific reaction. | |