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MCQOPTIONS
This section includes 200950 Mcqs, each offering curated multiple-choice questions to sharpen your General Knowledge knowledge and support exam preparation. Choose a topic below to get started.
| 15351. |
When a negro marries white, how many phenotypes are obtained ? |
| A. | 8 |
| B. | 16 |
| C. | 10 |
| D. | 7 |
| Answer» E. | |
| 15352. |
The science dealing with heredity and variation is known as |
| A. | genetics |
| B. | embryology |
| C. | cytohistology |
| D. | cytology |
| Answer» B. embryology | |
| 15353. |
Who studied the inheritance of skin colour in negro and white population in USA ? |
| A. | Mendel |
| B. | Davenport and Davenport |
| C. | Karl Correns |
| D. | Hugo De Vries |
| Answer» C. Karl Correns | |
| 15354. |
AaBbCc is the genotype of |
| A. | albino |
| B. | pure black (negro) |
| C. | mulatto |
| D. | fair |
| Answer» D. fair | |
| 15355. |
Skin colour is controlled by |
| A. | 2 pairs of genes with an intragene |
| B. | 3 pairs of genes |
| C. | single gene |
| D. | 2 pairs of genes |
| Answer» C. single gene | |
| 15356. |
When red wheat kernel is crossed with white wheat kernel, the probability of getting red darkest plant is |
| A. | 2/16 |
| B. | 6/16 |
| C. | 4/16 |
| D. | 1/16 |
| Answer» E. | |
| 15357. |
Who discovered polygenic inheritance? |
| A. | Bateson |
| B. | Johannsen |
| C. | Davenport |
| D. | H. Nilsson -Ehle |
| Answer» E. | |
| 15358. |
The additive or cumulative effect is shown by |
| A. | Complementary genes |
| B. | Polygenes |
| C. | Monogene |
| D. | Pleiotropic gene |
| Answer» C. Monogene | |
| 15359. |
The phenotypic ratio of red (AABB) and white (aabb) kernel in F2 generation showing polygenic inheritance is |
| A. | 1:6:15:20:15:6:1 |
| B. | 1:6:4:4:1 |
| C. | 1:4:6:4:1 |
| D. | 1:2:1 |
| Answer» D. 1:2:1 | |
| 15360. |
When single character is controlled by two or more genes is called |
| A. | co-dominance |
| B. | polygenic inheritance |
| C. | multiple allelism |
| D. | pleiotropy |
| Answer» C. multiple allelism | |
| 15361. |
A marriage between two carriers of sickle – cell anaemic gene will result into |
| A. | 2 normal and 2 sickle – cell anaemic |
| B. | 1 sickle-cell anaemic |
| C. | both (1) and (2) |
| D. | 1 normal and 2 carriers |
| Answer» D. 1 normal and 2 carriers | |
| 15362. |
In pleiotropic inheritance different traits are controlled by |
| A. | mutation |
| B. | single gene |
| C. | one or two genes |
| D. | many genes |
| Answer» C. one or two genes | |
| 15363. |
Blood grouping in humans is controlled by |
| A. | 3 alleles in which A is dominant. |
| B. | 3 alleles in which none is dominant. |
| C. | 3 alleles in which AB is codominant. |
| D. | 4 alleles in which A is dominant. |
| Answer» D. 4 alleles in which A is dominant. | |
| 15364. |
In which disease, the RBC of a person becomes half moon-shaped |
| A. | leukemia |
| B. | thalesemia |
| C. | sickle – cell anaemia |
| D. | haemophilia |
| Answer» D. haemophilia | |
| 15365. |
Which of the following is an example of pleiotropy? |
| A. | Colour blindness |
| B. | Sickle cell anaemia |
| C. | Thalassemia |
| D. | Haemophilia |
| Answer» C. Thalassemia | |
| 15366. |
ABO blood grouping is based on |
| A. | multiple allelism |
| B. | epistasis |
| C. | incomplete dominance |
| D. | codominance |
| Answer» B. epistasis | |
| 15367. |
Multiple alleles of a gene always occupy |
| A. | different loci on a chromosome |
| B. | the same position on different |
| C. | the same locus on a chromosome |
| D. | different loci on different chromosomes |
| Answer» D. different loci on different chromosomes | |
| 15368. |
In incomplete dominance, one could get 1 : 2 : 1 ratio in |
| A. | R cross |
| B. | F1 generation |
| C. | F2 generation |
| D. | test cross |
| Answer» D. test cross | |
| 15369. |
Co-dominance is different from incomplete dominance as in co-dominance |
| A. | genotypic ratio is 1 : 1 |
| B. | dominant is expressed in F1 |
| C. | both the genes are expressed equally |
| D. | the hybrid is intermediate |
| Answer» D. the hybrid is intermediate | |
| 15370. |
In Drosophila, the genotype of normal wings |
| A. | vg |
| B. | vgno |
| C. | Vg+ |
| D. | vgni |
| Answer» D. vgni | |
| 15371. |
R (red) flowered plant of Mirabilis is crossed with rr (white) flowered plant of Mirabilis. All the Rr offsprings are pink. This is an indication that the R gene is |
| A. | linked |
| B. | incompletely dominant |
| C. | recessive |
| D. | codominant |
| Answer» C. recessive | |
| 15372. |
When you reverse the digits of age of father, you will get the age of son. one year ago the age of father was twice that of son’s age. what are the current ages of father and son? |
| A. | 73 and 37 |
| B. | 45 and 54 |
| C. | 31 and 13 |
| D. | 24 and 42 |
| Answer» B. 45 and 54 | |
| 15373. |
Interaction between the alleles of different genes on the same or different chromosome is called |
| A. | both (1) and (2) |
| B. | intragenic |
| C. | nonallelic |
| D. | intergenic |
| Answer» B. intragenic | |
| 15374. |
Interaction between two alleles which are present on the same gene locus of two homologous chromosome is called |
| A. | both (1) and (2) |
| B. | intergenic interaction |
| C. | interallelic interaction |
| D. | intragenic interaction |
| Answer» B. intergenic interaction | |
| 15375. |
Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is the difference between R and Q’s age? |
| A. | 1 year |
| B. | 2 years |
| C. | 25 years |
| D. | Data insufficient |
| Answer» E. | |
| 15376. |
A started a business investing Rs. 45,000. After 3 months, B joined him with a capital of Rs. 60,000. After another 6 months, C joined them with a capital of Rs. 90,000. At the end of the year, they made a profit of Rs. 16,500. What is A's share of profit ? |
| A. | Rs. 5,500 |
| B. | Rs. 6,500 |
| C. | Rs. 6,900 |
| D. | Rs. 5,900 |
| Answer» B. Rs. 6,500 | |
| 15377. |
Find out the wrong statement. |
| A. | Test cross is done between F1 hybrid |
| B. | Back cross is always a test cross |
| C. | Test cross is a back cross |
| D. | Test cross ratio is 1:1 |
| Answer» C. Test cross is a back cross | |
| 15378. |
A and B are two taps which can fill a tank individually in 10 minutes and 20 minutes respectively. However, there is a leakage at the bottom which can empty a filled tank in 40 minutes. If the tank is empty initially, how much time will both the taps take to fill the tank (leakage is still there) ? |
| A. | 10 minutes |
| B. | 5 minutes |
| C. | 7 minutes |
| D. | 8 minutes |
| Answer» E. | |
| 15379. |
What is the next term in the series : 25, 34, 52,79, 115,? |
| A. | 160 |
| B. | 140 |
| C. | 153 |
| D. | 190 |
| Answer» B. 140 | |
| 15380. |
A candidate appearing for an examination has to secure 40% marks to pass paper I. But he secured only 40 marks and failed by 20 marks. What is the maximum mark for paper I? |
| A. | 100 |
| B. | 150 |
| C. | 180 |
| D. | 200 |
| Answer» C. 180 | |
| 15381. |
Which of the following ratio refers to back cross ? |
| A. | AA × AA |
| B. | Aa × AA |
| C. | Aa × Aa |
| D. | AA × Aa |
| Answer» C. Aa × Aa | |
| 15382. |
A cross between individual with unknown genotype for a particular trait with a recessive plant for that trait is called |
| A. | dihybrid cross |
| B. | monohybrid cross |
| C. | test cross |
| D. | back cross |
| Answer» D. back cross | |
| 15383. |
A person lost 10% when he sold goods at Rs.153. For how much should he sell them to gain 20%? |
| A. | Rs.232 |
| B. | Rs.240 |
| C. | Rs.204 |
| D. | Rs.250 |
| Answer» D. Rs.250 | |
| 15384. |
At what rate of simple interest per annum an amount will be doubled in 10 years? |
| A. | 10% |
| B. | 7.5% |
| C. | 15% |
| D. | 16% |
| Answer» B. 7.5% | |
| 15385. |
The perimeter of a rectangular field is 480 meters and the ratio between the length and breadth is 5:3. The area of the field is ? |
| A. | 14,500 m2 |
| B. | 11,500 m2 |
| C. | 12,500 m2 |
| D. | 13,500 m2 |
| Answer» E. | |
| 15386. |
Water is filled in a cylindrical vessel in such a way that its volume doubles after every five minutes. If it takes 30 minutes for the vessel to be full, then the vessel will be one fourth full in |
| A. | 10 minutes |
| B. | 20 minutes |
| C. | 25 minutes |
| D. | 15 minutes |
| Answer» C. 25 minutes | |
| 15387. |
A school has enough food for 400 children for 12 days. How long will the food last if 80 more children join them? |
| A. | 10 days |
| B. | 7 days |
| C. | 8 days |
| D. | 9 days |
| Answer» B. 7 days | |
| 15388. |
In F2 hybrid, to check the tall plant is homozygous or heterozygous, which cross is |
| A. | both (1) and (2) |
| B. | monohybrid cross |
| C. | back cross |
| D. | test cross |
| Answer» B. monohybrid cross | |
| 15389. |
A test cross |
| A. | none of these. |
| B. | both (1) and (2) |
| C. | involves mating of F1 hybrid with |
| D. | is used to investigate whether theindependent assortmentsegregationdominance−recessivenesscodominancequantitative recorddominant expression is homozygous orheterozygou |
| Answer» B. both (1) and (2) | |
| 15390. |
42 oranges are distributed among some boys and girls. If each boy gets 3, then each girl gets 6. But if each boy gets 6 and each girl gets 3, it needs 6 more. The number of girls is ? |
| A. | 10 |
| B. | 4 |
| C. | 6 |
| D. | 8 |
| Answer» C. 6 | |
| 15391. |
The reason behind the success of Mendel was |
| A. | maintenance of qualitative and |
| B. | use of pure line |
| C. | choice of material |
| D. | all of the above |
| Answer» E. | |
| 15392. |
Mendel did not propose law of |
| A. | independent assortment |
| B. | incomplete dominance |
| C. | dominance |
| D. | segregation |
| Answer» C. dominance | |
| 15393. |
A two digit number is three times the sum of its digits. If 45 is added to it, the digits are reversed. The number is ? |
| A. | 23 |
| B. | 32 |
| C. | 27 |
| D. | 72 |
| Answer» D. 72 | |
| 15394. |
The three important laws of heredity proposed by Mendel relate to |
| A. | segregation, independent assortment and |
| B. | segregation, independent assortment and |
| C. | gene linkage, dominance and |
| D. | gene linkage, character segregation and |
| Answer» C. gene linkage, dominance and | |
| 15395. |
Law of independent assortment is applicable for the traits which |
| A. | both (B) and (C) |
| B. | are located on homologous |
| C. | are located on same chromosome |
| D. | are located on different chromosomes |
| Answer» E. | |
| 15396. |
4 men u0026 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it? |
| A. | 25 days |
| B. | 35 days |
| C. | 40 days |
| D. | 30 days |
| Answer» D. 30 days | |
| 15397. |
10 cats caught 10 rats in 10 seconds. How many cats are required to catch 100 rats in 100 seconds ? |
| A. | 50 |
| B. | 100 |
| C. | 10 |
| D. | 20 |
| Answer» D. 20 | |
| 15398. |
_______ occurs due to crossing over taking place during meiosis. |
| A. | Mutation |
| B. | Segregation |
| C. | Recombination |
| D. | Linkage |
| Answer» E. | |
| 15399. |
Law of independent assortment can be explained by |
| A. | all of the above |
| B. | trihybrid cross and trihybrid ratio |
| C. | dihybrid cross and dihybrid ratio |
| D. | monohybrid cross and monohybrid ratio |
| Answer» D. monohybrid cross and monohybrid ratio | |
| 15400. |
New character combinations appear in F2generation of a dihybrid cross mainly because of |
| A. | independent assortment |
| B. | principle of unit character |
| C. | recessiveness |
| D. | dominance |
| Answer» B. principle of unit character | |