MCQOPTIONS
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MCQOPTIONS
This section includes 4 Mcqs, each offering curated multiple-choice questions to sharpen your Enzyme Technology Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The rate equation for _______________ inhibition is given by \(V=\frac{V_{max} [S]}{K_m (1+\frac{[P]}{K_p})+[S]}\). |
| A. | substrate |
| B. | non-competitive |
| C. | product |
| D. | competitive |
| Answer» D. competitive | |
| 2. |
The following rate equation is given by ___________ inhibition. |
| A. | \(V=\frac{\left (\frac{V_{max}}{1+\frac{[I]}{K_i’}}\right ) [S]}{\left (\frac{K_m}{1+\frac{[I]}{K_i’}}\right )+[S]}\) |
| B. | mixed |
| C. | competitive |
| D. | uncompetitive |
| E. | non-competitive |
| Answer» D. uncompetitive | |
| 3. |
If I = Ki = Ki‘, then what will happen to Vmax and Km when inhibitor acts non-competitively? |
| A. | Lowers to 0.5 Vmax and 0.5 Km |
| B. | Vmax is unchanged and Km increases 2Km |
| C. | Lowers to 0.5 Vmax and Km remains unchanged |
| D. | Lowers to 0.67 Vmax and Km increases to 2Km |
| Answer» D. Lowers to 0.67 Vmax and Km increases to 2Km | |
| 4. |
What happens to Vmax and Km in case of uncompetitive inhibition when I = Ki‘? |
| A. | Lowers to 0.5 Vmax and 0.5 Km |
| B. | Vmax is unchanged and Km increases 2Km |
| C. | Lowers to 0.5 Vmax and Km remains unchanged |
| D. | Lowers to 0.67 Vmax and Km increases to 2Km |
| Answer» B. Vmax is unchanged and Km increases 2Km | |