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				This section includes 32 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. | The cable AO exerts a force on the top of the pole of F = {120i  90j  80k} lb. If the cable has a length of 34 ft, determine the height z of the pole and the location (x,y) of its base. | 
| A. | x = 16 ft, y = 16 ft, z = 25 ft | 
| B. | x = 12 ft, y = 9 ft, z = 8 ft | 
| C. | x = 20 ft, y = 10 ft, z = 14 ft | 
| D. | x = 24 ft, y = 18 ft, z = 16 ft | 
| Answer» E. | |
| 2. | The gusset plate G of a bridge joint is subjected to the two member forces at A and B. If the force at B is horizontal and the force at A is directed at = 30°, determine the magnitude and direction of the resultant force. | 
| A. | R = 458 N, = 97.5° CCW | 
| B. | R = 252 N, = 82.5° CCW | 
| C. | R = 252 N, = 97.5° CCW | 
| D. | R = 458 N, = 82.5° CCW | 
| Answer» D. R = 458 N, = 82.5° CCW | |
| 3. | If = 20° and = 35°, determine the magnitudes of F1 and F2 so that the resultant force has a magnitude of 20 lb and is directed along the positive x axis. | 
| A. | F1 = 20.0 lb, F2 = 22.9 lb | 
| B. | F1 = 25.6 lb, F2 = 26.6 lb | 
| C. | F1 = 28.5 lb, F2 = 11.91 lb | 
| D. | F1 = 14.00 lb, F2 = 8.35 lb | 
| Answer» E. | |
| 4. | Determine the design angle ( | 
| A. | FAB = 321 lb, = 40.0° | 
| B. | FAB = 383 lb, = 36.9° | 
| C. | FAB = 171.1 lb, = 20.0° | 
| D. | FAB = 215 lb, = 52.7° | 
| Answer» E. | |
| 5. | Determine the magnitude of the x and y components of the 2kN force. | 
| A. | Fx = -1.414 kN, Fy = -1.414 kN | 
| B. | Fx = -1.000 kN, Fy = -1.732 kN | 
| C. | Fx = -1.732 kN, Fy = -1.000 kN | 
| D. | Fx = -4.000 kN, Fy = -2.312 kN | 
| Answer» C. Fx = -1.732 kN, Fy = -1.000 kN | |
| 6. | Two forces act on a block. Determine the angle between them. | 
| A. | = 135.0° | 
| B. | = 65.1° | 
| C. | = 45.0° | 
| D. | = 114.9° | 
| Answer» E. | |
| 7. | Determine the magnitude and direction angles of F2, so that the resultant of the two forces acts upward along the z axis of the pole and has a magnitude of 275 N. | 
| A. | F2 = 246 N, = 54.9°, = 114.0°, = 44.7° | 
| B. | F2 = 200 N, = 45.0°, = -60.0°, = 29.0° | 
| C. | F2 = 200 N, = 45.0°, = 120.0°, = 29.0° | 
| D. | F2 = 246 N, = 54.9°, = 66.0°, = 44.7° | 
| Answer» B. F2 = 200 N, = 45.0¬∞, = -60.0¬∞, = 29.0¬∞ | |
| 8. | If = 20° and = 35°, determine the magnitudes of F1 and F2 so that the resultant force has a magnitude of 20 lb and is directed along the positive x axis. | 
| A. | F1 = 20.0 lb, F2 = 22.9 lb | 
| B. | F1 = 25.6 lb, F2 = 26.6 lb | 
| C. | F1 = 28.5 lb, F2 = 11.91 lb | 
| D. | F1 = 14.00 lb, F2 = 8.35 lb | 
| Answer» E. | |
| 9. | The antenna tower is supported by three cables. The forces in these cables are as follows: FB = 520 N, FC = 680 N, and FD = 560 N. Write the resultant of these three forces as a vector. | 
| A. | R = (4i +16j-72k) N | 
| B. | R = (-120i +40 j-960k) N | 
| C. | R = (560i +720j+1440k) N | 
| D. | R = (80i +320j-1440k) N | 
| Answer» E. | |
| 10. | Determine the magnitudes of the resultant force and its direction measured from the positive x axis. | 
| A. | R = 12.49 kN, = 43.9° CW | 
| B. | R = 13.6 kN, = 21.5° CW | 
| C. | R = 14.00 kN, = 60.0° CW | 
| D. | R = 10.80 kN, = 68.2° CW | 
| Answer» B. R = 13.6 kN, = 21.5¬∞ CW | |
| 11. | Cable BC exerts a force of F = 28 N on the top of the flagpole. Determine the projection of this force along the positive z axis of the pole. | 
| A. | F = 24 N | 
| B. | F = -24 N | 
| C. | F = 12 N | 
| D. | F = 12 N | 
| Answer» C. F = 12 N | |
| 12. | The ball joint is subjected to the three forces shown. Find the magnitude of the resultant force. | 
| A. | R = 5.30 kN | 
| B. | R = 5.74 kN | 
| C. | R = 5.03 kN | 
| D. | R = 6.20 kN | 
| Answer» E. | |
| 13. | Determine the design angle ( | 
| A. | FAB = 321 lb, = 40.0° | 
| B. | FAB = 383 lb, = 36.9° | 
| C. | FAB = 171.1 lb, = 20.0° | 
| D. | FAB = 215 lb, = 52.7° | 
| Answer» E. | |
| 14. | Determine the projection of the position vector r along the aa axis. | 
| A. | raa = 35.3 m | 
| B. | raa = 6.28 m | 
| C. | raa = 5.42 m | 
| D. | raa = 5.61 m | 
| Answer» D. raa = 5.61 m | |
| 15. | Express the Force F2 in Cartesian vector form. | 
| A. | F2 = (155 i + 155 j + 300 k) lb | 
| B. | F2 = (212 i + 212 j - 519 k) lb | 
| C. | F2 = (155 i + 155 j - 300 k) lb | 
| D. | F2 = (367 i + 367 j - 300 k) lb | 
| Answer» E. | |
| 16. | Determine the magnitude and direction of F so that this force has components of 40 lb acting from A toward B and 60lb acting from A toward C on the frame. | 
| A. | F = 44.7 lb, = 22.9° | 
| B. | F = 80.3 lb, = 46.2° | 
| C. | F = 62.9 lb, = 37.1° | 
| D. | F = 72.1 lb, = 56.3° | 
| Answer» C. F = 62.9 lb, = 37.1¬∞ | |
| 17. | Determine the design angle for connecting member A to the plate if the resultant force is to be directed vercially upward. Also, what is the magnitude of the resultant? | 
| A. | R = 400 N, = 53.5° | 
| B. | R = 250 N, = 30.0° | 
| C. | R = 300 N, = 36.9° | 
| D. | R = 640 N, = 38.6° | 
| Answer» D. R = 640 N, = 38.6¬∞ | |
| 18. | Determine the angle between the pole AC and the wire AB. | 
| A. | = 131.8° | 
| B. | = 70.5° | 
| C. | = 109.5° | 
| D. | = 48.2° | 
| Answer» C. = 109.5¬∞ | |
| 19. | Determine the magnitude of the x and y components of the 700-lb force. | 
| A. | Fx = -350 lb, Fy = 606 lb | 
| B. | Fx = -404 lb, Fy = 571 lb | 
| C. | Fx = -606 lb, Fy = 350 lb | 
| D. | Fx = -571 lb, Fy = 404 lb | 
| Answer» D. Fx = -571 lb, Fy = 404 lb | |
| 20. | What is the projection of the force F2 along the positive axis? | 
| A. | F2y = 170.0 N | 
| B. | F2y = —80.0 N | 
| C. | F2y = 90.0 N | 
| D. | F2y = 120.0 N | 
| Answer» D. F2y = 120.0 N | |
| 21. | The gusset plate G of a bridge joint is subjected to the two member forces at A and B. If the force at B is horizontal and the force at A is directed at = 30°, determine the magnitude and direction of the resultant force. | 
| A. | R = 458 N, = 97.5° CCW | 
| B. | R = 252 N, = 82.5° CCW | 
| C. | R = 252 N, = 97.5° CCW | 
| D. | R = 458 N, = 82.5° CCW | 
| Answer» D. R = 458 N, = 82.5¬∞ CCW | |
| 22. | Determine the magnitude and direction of the position vector r which points from point A to point B. | 
| A. | r = 12 ft, = 70.5°, = 48.2°, = 131.8° | 
| B. | r = 12 ft, = 109.5°, = 131.8°, = 48.2° | 
| C. | r = 12 ft, = 70.5°, = 48.2°, = 48.2° | 
| D. | r = 12 ft, = 109.5°, = 131.8°, = 131.8° | 
| Answer» B. r = 12 ft, = 109.5¬∞, = 131.8¬∞, = 48.2¬∞ | |
| 23. | The cable AO exerts a force on the top of the pole of F = {—120i — 90j — 80k} lb. If the cable has a length of 34 ft, determine the height z of the pole and the location (x,y) of its base. | 
| A. | x = 16 ft, y = 16 ft, z = 25 ft | 
| B. | x = 12 ft, y = 9 ft, z = 8 ft | 
| C. | x = 20 ft, y = 10 ft, z = 14 ft | 
| D. | x = 24 ft, y = 18 ft, z = 16 ft | 
| Answer» E. | |
| 24. | Determine the magnitude of the x and y components of the 2—kN force. | 
| A. | Fx = -1.414 kN, Fy = -1.414 kN | 
| B. | Fx = -1.000 kN, Fy = -1.732 kN | 
| C. | Fx = -1.732 kN, Fy = -1.000 kN | 
| D. | Fx = -4.000 kN, Fy = -2.312 kN | 
| Answer» C. Fx = -1.732 kN, Fy = -1.000 kN | |
| 25. | Determine the magnitude of the resultant force by adding the rectangular components of the three forces. | 
| A. | R = 29.7 N | 
| B. | R = 54.2N | 
| C. | R = 90.8 N | 
| D. | R = 24.0 N | 
| Answer» B. R = 54.2N | |
| 26. | Express force F as a Cartesian vector; then determine its direction angles. | 
| A. | F = (-2i +j+2k) kN, = 48.2°, = 70.5°, = 48.2° | 
| B. | F = (-2i +j+2k) kN, = 131.8°, = 70.5°, = 48.2° | 
| C. | F = (-4i +j+4k) kN, = 48.2°, = 70.5°, = 48.2° | 
| D. | F = (-4i +2j+4k) kN, = 131.8°, = 70.5°, = 48.2° | 
| Answer» C. F = (-4i +j+4k) kN, = 48.2¬∞, = 70.5¬∞, = 48.2¬∞ | |
| 27. | Determine the magnitude and direction of the resultant force. | 
| A. | R = 80.3 lb, = 106.2° CCW | 
| B. | R = 80.3 lb, = 73.8° CCW | 
| C. | R = 72.1 lb, = 63.6° CCW | 
| D. | R = 72.1 lb, = 116.4° CCW | 
| Answer» B. R = 80.3 lb, = 73.8¬∞ CCW | |
| 28. | Express the force F1 in Cartesian vector form. | 
| A. | F1 = (200 i - 200 j + 283 k) lb | 
| B. | F1 = (200 i + 200 j + 283 k) lb | 
| C. | F1 = (-200 i + 200 j + 565 k) lb | 
| D. | F1 = (-200 i + 200 j + 283 k) lb | 
| Answer» E. | |
| 29. | Force F acts on peg A such that one of its components, lying in the x-y plane, has a magnitude of 50 lb. Express F as a Cartesian vector. | 
| A. | F = (43.3 i + 25.0 j + 25.0 k) lb | 
| B. | F = (43.3 i + 25.0 j + 28.9 k) lb | 
| C. | F = (43.3 i - 25.0 j + 25.0 k) lb | 
| D. | F = (43.3 i - 25.0 j + 28.9 k) lb | 
| Answer» E. | |
| 30. | If F1 = F2 = 30lb, determine the angles and so that the resultant force is directed along the positive x axis and has a magnitude of FR = 20 lb. | 
| A. | = = 70.5° | 
| B. | = = 41.4° | 
| C. | = = 19.47° | 
| D. | = = 18.43° | 
| Answer» B. = = 41.4¬∞ | |
| 31. | Express each force in Cartesian vector form. | 
| A. | F1 = (2.50 i + 3.54 j + 2.50 k) kN, F2 = -2 j kN | 
| B. | F1 = (4.33 i + 3.54 j + 4.33 k) kN, F2 = -2 j kN | 
| C. | F1 = (2.17 i + 3.75 j + 4.33 k) kN, F2 = -2 j kN | 
| D. | F1 = (4.33 i + 3.75 j + 2.17 k) kN, F2 = -2 j kN | 
| Answer» B. F1 = (4.33 i + 3.54 j + 4.33 k) kN, F2 = -2 j kN | |
| 32. | The cord is attached between two walls. If it is 8 m long, determine the distance x to the point of attachment at B. | 
| A. | x = 7.75 m | 
| B. | x = 7.68 m | 
| C. | x = 6.93 m | 
| D. | x = 7.94 m | 
| Answer» C. x = 6.93 m | |