Explore topic-wise MCQs in Testing Subject.

This section includes 657 Mcqs, each offering curated multiple-choice questions to sharpen your Testing Subject knowledge and support exam preparation. Choose a topic below to get started.

1.

The following IPv4 addresses in hexadecimal notation is – 10000001 00001011 00001011 11101111-

A. 0x810B0BEF
B. 0x810D0AFF
C. 0x810B0BFE
D. 0x810C0CEF
Answer» B. 0x810D0AFF
2.

What is the error (if any) in the following representation – 11100010.23.14.67?

A. There should be no leading zeros
B. We cannot have more than 4 bytes in an IPv4 address
C. Each byte should be less than or equal to 255
D. None of the mentioned
Answer» E.
3.

What is the error (if any) in the following representation – 75.45.301.14?

A. There should be no leading zeros
B. We cannot have more than 4 bytes in an IPv4 address
C. Each byte should be less than or equal to 255
D. No error
Answer» D. No error
4.

What is the error (if any) in the following representation – 221.34.7.8.20?

A. There should be no leading zeros
B. Each byte should be less than or equal to 255
C. We cannot have more than 4 bytes in an IPv4 address
D. No error
Answer» D. No error
5.

What is the error (if any) in the following representation – 111.56.045.78?

A. There should be no leading zeros
B. We cannot have more than 4 bytes in an IPv4 address
C. Each byte should be less than or equal to 255
D. No error
Answer» B. We cannot have more than 4 bytes in an IPv4 address
6.

Convert the following dotted-decimal notation to binary notation – 111.56.45.78

A. 01101111 00111000 00101101 01001110
B. 11101111 00111000 00101101 10001110
C. 10000000 00001011 00000011 00011111
D. 10000001 00001011 00001011 11101111
Answer» B. 11101111 00111000 00101101 10001110
7.

Convert the following binary notation to dotted-decimal notation –10000001 00001011 00001011 11101111

A. 129.11.11.239
B. 128.11.12.231
C. 127.11.13.244
D. 129.12.1.231
Answer» B. 128.11.12.231
8.

Convert the following binary notation to hexadecimal notation –10000000 00001011 00000011 00011111

A. 0x 80 0B 03 1E
B. 0x 81 0B 04 1E
C. 0x 80 0C 03 1F
D. 0x 80 0B 03 1F
Answer» E.
9.

Convert the following binary notation to dotted-decimal notation –10000000 00001011 00000011 00011111

A. 128.11.5.32
B. 128.11.3.31
C. 127.11.3.32
D. 127.12.5.31
Answer» C. 127.11.3.32
10.

How can a production engineer enhance the production of a well?

A. Increasing bottom-hole flowing pressure
B. Increasing surface flowing pressure
C. Increasing reservoir pressure
D. By well stimulation
Answer» E.
11.

Consider a case, in which the actual production rate of the well is lower than that predicted based on the IPR equation, and also the bottom hole pressure measurement shows it to be lower than the expected value then what is the cause of this situation?

A. By a restriction in the wellbore
B. By formation damage
C. By an increase in reservoir pressure
D. No formation damage
Answer» C. By an increase in reservoir pressure
12.

What is the phasing shown in the diagram below?

A. 120°
B. 90°
C. 45°
D. 60°
Answer» E.
13.

A semi-circular structure with a dome shape roof erected over sacred relics of Buddha is known as ___________

A. edicts
B. pillars
C. stupas
D. monoliths
Answer» D. monoliths
14.

The small circular pattern in the plan represents __________

A. hole
B. beam
C. column
D. design
Answer» D. design
15.

The figure below represents octagonal structure.

A. True
B. False
Answer» C.
16.

The superstructure of a building is the part that is entirely above its foundation or basement.

A. True
B. False
Answer» B. False
17.

A refrigerator works on a reversed Carnot cycle. The Coefficient of performance is 7. If the capacity of the refrigerator is 12 TR. What is the value of heat rejected from the system?

A. 46 kW
B. 50 kW
C. 42 kJ/min
D. 48 kJ/min
Answer» E.
18.

A refrigerator works on a reversed Carnot cycle. The Coefficient of performance is 3.5. If the capacity of the refrigerator is 6 TR. Find out the power required to run the refrigerator.

A. 5 kW
B. 3.5 kW
C. 360 kJ/min
D. 520 kJ/min
Answer» D. 520 kJ/min
19.

Two refrigerators M and N operate in series. The refrigerator M absorbs energy at the rate of 1 kW from a body at temperature 400 K and rejects energy as heat to a body at a temperature T. The refrigerator N absorbs the same quantity of energy which is rejected by the refrigerator N from the body at temperature T, and rejects energy as heat to a body at temperature 800 K. If both the refrigerators have the same C.O.P., what is the value temperature T?

A. 600 K
B. 200 K
C. 565.68 K
D. 459.21 K
Answer» D. 459.21 K
20.

C.O.P. of the refrigerator is always _____ the C.O.P. of the heat pump when both are working between the same temperature limits.

A. less than
B. greater than
C. equal to
D. inverse of
Answer» B. greater than
21.

If the Coefficient of performance of a heat pump is 5, then what is the value of the Coefficient of performance of the refrigerator operating under the same conditions?

A. 4
B. 6
C. 0.2
D. 3
Answer» B. 6
22.

A reversed Carnot cycle is operating between temperature limits of 272 K and (+) 49°C. If it acts as a heat engine gives an efficiency of 15.52%. What is the value of C.O.P. of a refrigerator operating under the same conditions?

A. 6.44
B. 0.1838
C. 5.44
D. 2
Answer» D. 2
23.

If the reversed Carnot cycle operating as a refrigerator between temperature limits of 405 K and 255 K, then what is the value of C.O.P.?

A. 2.7
B. 0.588
C. 1.7
D. 0.370
Answer» D. 0.370
24.

For the systems working on reversed Carnot cycle, what is the relation between C.O.P. of Refrigerator i.e. (C.O.P.)R and Heat Pump i.e. (C.O.P.)P?

A. (C.O.P.)R + (C.O.P.)P = 1
B. (C.O.P.)R = (C.O.P.)P
C. (C.O.P.)R = (C.O.P.)P − 1
D. (C.O.P.)R + (C.O.P.)P + 1 = 0
Answer» D. (C.O.P.)R + (C.O.P.)P + 1 = 0
25.

The C.O.P. of a reversed Carnot refrigerator is 5. What is the ratio of highest temperature to lower temperature?

A. −1.2
B. 0.8
C. 1.2
D. −0.8
Answer» D. −0.8
26.

The efficiency of Carnot heat engine is 40%. What is the value of C.O.P. of a refrigerator operating on reversed Carnot cycle?

A. 2.5
B. 1.5
C. 4
D. 10
Answer» C. 4
27.

If the condenser and evaporator temperatures are 320 K and 240 K respectively, then what is the value of the C.O.P.?

A. 0.25
B. 4
C. 0.33
D. 3
Answer» E.
28.

In a refrigerating machine working on the reversed Carnot cycle, if the lower temperature is fixed, then what can be done to increase the C.O.P.?

A. Increasing higher temperature
B. Operating machine at higher speed
C. Decreasing higher temperature
D. Operating machine at a lower speed
Answer» D. Operating machine at a lower speed
29.

If a refrigeration system having T1 and T2 as lower and higher temperatures respectively then, what is the value of C.O.P of the refrigeration system working on the reversed Carnot cycle?

A. T2 / (T2 − T1)
B. (T2 − T1) / T1
C. (T2 − T1) / T2
D. T1 / (T2 − T1)
Answer» E.
30.

Cellular concrete is used for ______ insulation.

A. Thermal
B. Chemical
C. Sound
D. Electrical
Answer» D. Electrical
31.

Cork has a low thermal conductivity of _____ W/m K.

A. 0.01
B. 0.04
C. 0.07
D. 0.1
Answer» D. 0.1
32.

The resistance of an insulating material ______ as the temperature increases.

A. Increases
B. Decreases
C. Remains the same
D. Becomes infinitely large
Answer» C. Remains the same
33.

Mannitol enzyme II has been purified from _____________

A. E.coli
B. Salmonella typhimurium
C. Saccharomyces cerevisiae
D. Lactobacillus
Answer» B. Salmonella typhimurium
34.

In phosphotransferase system(PTS), the sugar-phosphate is released inside the cell by which of the following?

A. Enzyme I
B. Enzyme II
C. Enzyme III
D. HPr
Answer» C. Enzyme III
35.

HPr stands for ______________

A. heat-stable carrier protein
B. hydrogen carrier protein
C. pyruvate dehydrogenase
D. high-energy protein
Answer» B. hydrogen carrier protein
36.

Which of the following has no detectable ATPase activity?

A. cilia
B. eukaryotic flagella
C. bacterial flagella
D. endoflagella
Answer» D. endoflagella
37.

What are the ends of the two arms of YAC vectors composed of ____________

A. TEL sequences
B. Origin
C. Gene of interest
D. SUP4
Answer» B. Origin
38.

What is the maximum approximate length of the genes that can be cloned using YACs?

A. 100kb
B. 300kb
C. 600kb
D. 1000kb
Answer» E.
39.

In the insertional inactivation of SUP4, red colonies are recombinants.

A. True
B. False
Answer» C.
40.

Which of the following restriction sites are used in a pYAC3 vector?

A. EcoR1, BamHI
B. BamHI, SnaBI
C. SnaBI, EcoR1
D. HindIII, BamHI
Answer» C. SnaBI, EcoR1
41.

Torque due to weight of the connecting rod affects the torque due to connecting rod.

A. True
B. False
Answer» C.
42.

Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 mFind angular acceleration of connecting rod in rad/s2.

A. 16.782
B. 17.824
C. 15.142
D. 17.161
Answer» C. 15.142
43.

From the data given:Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m ; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 mFind the correcting couple in N-m?

A. 52.7
B. 49.5
C. 59.5
D. 56.5
Answer» D. 56.5
44.

Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 mFind the equivalent length L of a simple pendulum swung about an axis.

A. 1.35 m
B. 1.42 m
C. 1.48 m
D. 1.50 m
Answer» C. 1.48 m
45.

For a steam engine, the following data is given:Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m ; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 mcalculate inertia force at θ=30 degrees from IDC.

A. 19000 N
B. 19064 N
C. 19032 N
D. 20064 N
Answer» C. 19032 N
46.

When mass of the reciprocating parts is neglected then the inertia force is _____

A. Maximum
B. Minimum
C. 0
D. Not defined
Answer» D. Not defined
47.

Inertia forces on the reciprocating parts acts along the line of stroke.

A. True
B. False
Answer» B. False
48.

Force which does not act on the connecting rod is ______

A. Weight of connecting rod
B. Inertia force of connecting rod
C. Radial force
D. Coriolis force
Answer» E.
49.

The ends A and B of a rod of 20cm length are kept at 30°C and 80°C until steady state prevails. What is the condition u(x,0)?

A. 20 + 5⁄2 x
B. 30 + 5⁄2 x
C. 30 + 2x
D. 20 + 2x
Answer» C. 30 + 2x
50.

If two ends of a bar of length l is insulated then what are the conditions to solve the heat flow equation?

A. ux(0,t) = 0 = ux(l,t)
B. ut(0,t) = 0 = ut(l,t)
C. u(0,t) = 0 = u(l,t)
D. uxx(0,t) = 0 = uxx(l,t)
Answer» B. ut(0,t) = 0 = ut(l,t)