Explore topic-wise MCQs in Heat Transfer Operations Questions and Answers.

This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Heat Transfer Operations Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.

1.

If we have the areas calculated for the three effects as 1512, 1622, and 1892. Then the value we consider to manufacture the three effects of this triple effect evaporator is ______________

A. 1622
B. 1512
C. 1892
D. Their respective values
Answer» D. Their respective values
Discussion
2.

If the three areas obtained from steam calculation are 1512, 1622, and 1892. If the diameter and the length of the tube are 5cm and 150cm respectively, find the number of tubes required in this multiple effect evaporator.

A. 697
B. 802
C. 892
D. 502
Answer» C. 892
Discussion
3.

In a triple effect evaporator, given the enthalpies as and the flow rates

A. Feed rate = 25000kg/hr at 38℃, Feed conc = 0.10, Product conc = 0.50
B. Find the evaporate rate in 1st effect.
Answer» D.
Discussion
4.

Which one of the following is the correct equation for enthalpy balance for the final effect in a triple effect evaporator?

A. E2 ∇E2+P2 HP2=EHE+PHP
B. FHF+S∇S=EHE+PHP
C. E1 ∇E1+P1 HP1=E2 HE2+P2 HP2
D. FHF+S∇S=E1 HE+P1 HP
Answer» B. FHF+S∇S=EHE+PHP
Discussion
5.

In a triple effect evaporator, given the enthalpies as and the flow rates calculate the product formation rate in the 2nd effect.

A. Feed rate = 25000kg/hr at 38℃, Feed conc = 0.10, Product conc = 0.50
B. Find the evaporate rate in 3rd effect.
Answer» C.
Discussion
6.

Which one of the following is the correct equation for enthalpy balance for the 2nd effect in a triple effect evaporator?

A. FHF+S∇S=EHE+EHP
B. FHF+S∇S=EHE+PHP
C. E1 ∇E1+P1HP1=E2 HE2+P2 HP2
D. FHF+S∇S=E1 HE+P1HP
Answer» D. FHF+S∇S=E1 HE+P1HP
Discussion
7.

Which one of the following is the correct equation for enthalpy balance for the 1st effect in a triple effect evaporator?

A. FHF+S∇S=EHE+EHP
B. FHF+S∇S=EHE+PHP
C. E1 HE+P1 HP=E2 HE+P2 HP
D. FHF+S∇S=E1 HE+P1 HP
Answer» E.
Discussion