MCQOPTIONS
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MCQOPTIONS
This section includes 2460 Mcqs, each offering curated multiple-choice questions to sharpen your Advanced Machining knowledge and support exam preparation. Choose a topic below to get started.
| 401. |
Which of the following clearly defines availability or exergy? |
| A. | it is the maximum useful work obtainable from a system as it reaches the dead state |
| B. | it is the minimum work required to bring the closed system from the dead state to the given state |
| C. | both of the mentioned |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 402. |
The morphology of the resulting pSi structures is dependent on the noble metal film. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 403. |
Lithographic approach along with noble metal is used to produce highly ordered pores. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 404. |
_____ is/are obtained when a homogeneous noble metal film is deposited on the surface of silicon. |
| A. | Conical structure |
| B. | Distorted and rough surfaces |
| C. | Honey-comb structure |
| D. | Wire-like structure |
| Answer» E. | |
| 405. |
Noble metal used in metal-assisted approach affects the formation of μpSi structures on the side walls of pores. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 406. |
An expansion gap of 5mm is provided in case of Junction fish plates. |
| A. | True |
| B. | False |
| Answer» C. | |
| 407. |
Why are Combination fish plates used? |
| A. | To connect rails of two different sections |
| B. | To connect two different fastenings |
| C. | To increase load |
| D. | To connect two rails of similar sections |
| Answer» B. To connect two different fastenings | |
| 408. |
The strength of fish plates are _______ as the rail section. |
| A. | Roughly same |
| B. | Almost double |
| C. | Almost half |
| D. | Roughly half |
| Answer» B. Almost double | |
| 409. |
In the steel used to manufacture fish plates what should be the composition of manganese? |
| A. | Exactly 0.6% |
| B. | Less than 0.8% |
| C. | Not more than 0.6% |
| D. | More than 0.6% |
| Answer» D. More than 0.6% | |
| 410. |
What is the function of Fish plates in a track? |
| A. | Joining rail to wooden sleepers |
| B. | Joining rail to cast iron sleepers |
| C. | Joining rail to steel trough sleepers |
| D. | Joining rail to rail |
| Answer» E. | |
| 411. |
The percentage of clay in zircon porcelain is about ________ |
| A. | 5-10% |
| B. | 7-13% |
| C. | 15-30% |
| D. | 40-60% |
| Answer» D. 40-60% | |
| 412. |
Which of the following statements about porcelain is not true? |
| A. | Low voltage porcelain is obtained by wet process |
| B. | Porcelain is hard and brittle |
| C. | Porcelain is non-porous |
| D. | Porcelain is prepared from felspar, clay, quartz and minerals |
| Answer» B. Porcelain is hard and brittle | |
| 413. |
Which of the following is also known as whiteware? |
| A. | Earthenware |
| B. | Stoneware |
| C. | Rockware |
| D. | Porcelain |
| Answer» E. | |
| 414. |
Polished terra-cotta is also known as _________ |
| A. | Porous terra-cotta |
| B. | Sawdust terra-cotta |
| C. | Faience |
| D. | Perforated terra-cotta |
| Answer» D. Perforated terra-cotta | |
| 415. |
Dried products formed after the drying process in the manufacturing of terra-cotta are burnt in _________ |
| A. | Blast furnace |
| B. | Cupola furnace |
| C. | Reverberatory furnace |
| D. | Muffle furnace |
| Answer» E. | |
| 416. |
The percentage of iron oxide in the clay taken to manufacture terra-cotta is ________ |
| A. | 1-3% |
| B. | 5-8% |
| C. | 12-15% |
| D. | 17-20% |
| Answer» C. 12-15% | |
| 417. |
Terra in terra-cotta means _______ |
| A. | Oven |
| B. | Baked |
| C. | Earth |
| D. | Burnt |
| Answer» D. Burnt | |
| 418. |
Pot tiles are _________ in section. |
| A. | Semi-circular |
| B. | Circular |
| C. | Square |
| D. | Hexagonal |
| Answer» B. Circular | |
| 419. |
Pantiles are more curved than pot tiles. |
| A. | True |
| B. | False |
| Answer» C. | |
| 420. |
The number of Mangalore tiles required to cover 1 square metre of roof area is about ________ |
| A. | 5 |
| B. | 15 |
| C. | 25 |
| D. | 50 |
| Answer» C. 25 | |
| 421. |
Macromolecules like Enzymes, vitamins and hormones can be classified into a single category of biological chemicals. Why? |
| A. | all of these help in regulating metabolism |
| B. | all of these are exclusively synthesized in the body of a living organism as at present |
| C. | all of these are conjugated proteins |
| D. | all of these enhance oxidative metabolism |
| Answer» D. all of these enhance oxidative metabolism | |
| 422. |
Lipids are insoluble in water because of which of the following reason? |
| A. | lipid molecules are hydrophilic |
| B. | lipid molecules are hydrophobic |
| C. | lipid molecules are neutral |
| D. | lipid molecules are zwitterions |
| Answer» C. lipid molecules are neutral | |
| 423. |
Amino acids and proteins are ionized at typical biological pH such that both the amino group and the carboxyl group gain hydrogen ions to become -NH3+ and -COOH, respectively. |
| A. | True |
| B. | false |
| Answer» B. false | |
| 424. |
What happens when a macromolecule undergoes hydrolysis reaction? |
| A. | protein coils into its secondary structure |
| B. | the bond between two subunits of a macromolecule is broken |
| C. | a bond is formed between two subunits of a macromolecule |
| D. | water breaks ionic bonds |
| Answer» C. a bond is formed between two subunits of a macromolecule | |
| 425. |
How stagnation point on the topside of the airfoil reaches the trailing edge? |
| A. | Due to viscous forces |
| B. | Due to surface forces |
| C. | Due to pressure forces |
| D. | Due to drag forces |
| Answer» B. Due to surface forces | |
| 426. |
How airfoil increases its speed? |
| A. | Flow over the topside |
| B. | Flow over the leading edge |
| C. | Flow over the bottom side |
| D. | Flow over the trailing edge |
| Answer» B. Flow over the leading edge | |
| 427. |
How starting vortex is formed? |
| A. | As the airfoil begins to move vortex are formed |
| B. | As the airflows on the airfoil vortex are formed |
| C. | As the airfoil moves against the relative wind vortex are formed |
| D. | As the airflows on the circular body vortex are formed |
| Answer» B. As the airflows on the airfoil vortex are formed | |
| 428. |
Is high airspeed around the trailing edge causes strong viscous forces? |
| A. | False |
| B. | True |
| Answer» B. True | |
| 429. |
Vortex flow occurs at ___________ |
| A. | Leading edge |
| B. | Trailing edge |
| C. | Chord |
| D. | Chamber line |
| Answer» C. Chord | |
| 430. |
Is Kutta condition is applicable to solid bodies with sharp corners? |
| A. | True |
| B. | False |
| Answer» B. False | |
| 431. |
One of the drawbacks of Sutherland- Hodgeman algorithm is that it can’t produce ____________ areas. |
| A. | connected |
| B. | multiple |
| C. | discrete |
| D. | circular |
| Answer» B. multiple | |
| 432. |
In a convex polygon, each of the interior angles is less than ____degrees. |
| A. | 90 |
| B. | 180 |
| C. | 360 |
| D. | 45 |
| Answer» C. 360 | |
| 433. |
If the subject polygon is concave at vertices outside the clipping polygon, the new polygon may have coincident edges. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 434. |
Sutherland-Hodgeman clipping is an example of_________________ algorithm. |
| A. | line clipping |
| B. | polygon clipping |
| C. | text clipping |
| D. | curve clipping |
| Answer» C. text clipping | |
| 435. |
d/b plots are |
| A. | Exponential |
| B. | Logarithmic |
| C. | Linear |
| D. | Non linear |
| Answer» E. | |
| 436. |
d/b plots are used when there is |
| A. | Non key components |
| B. | Total reflux |
| C. | Boil up required |
| D. | Can’t be specified |
| Answer» B. Total reflux | |
| 437. |
d/b plots are also called as |
| A. | Key plots |
| B. | Mole plots |
| C. | Reflux plots |
| D. | Non Key plots |
| Answer» B. Mole plots | |
| 438. |
More volatile keys are defined as |
| A. | Heavy key (H) |
| B. | Over Key (O) |
| C. | Light Key (L) |
| D. | Down comer Key (D) |
| Answer» D. Down comer Key (D) | |
| 439. |
Which of the following is correct to trim an aircraft at positive AOA? |
| A. | Cm0 > 0 |
| B. | Cm0 < 0 |
| C. | Cm0 will not affect positive trim AOA |
| D. | Every value of cm0 will trim at positive AOA |
| Answer» B. Cm0 < 0 | |
| 440. |
Determine the corrections or otherwise of the following Assertion [A] and Reason [R]:Assertion [A]: For longitudinal static stability of an aircraft, slope of moment curve should be negative.Reason[R]: Positive slope will result in more static stability than negative slope. Hence, slope should be positive always. |
| A. | Both [A] and [R] are true and [R] is the correct reason for [A] |
| B. | Both [A] and [R] are true but [R] is not the correct reason for [A] |
| C. | [A] is true but [R] is false |
| D. | [A] is false but [R] is true |
| Answer» D. [A] is false but [R] is true | |
| 441. |
Elevator control power is given by _____ |
| A. | \(\frac{dCm}{d\delta e}\) |
| B. | Zero lift drag |
| C. | T = CD0 + K*CL |
| D. | DCL/ɑ |
| Answer» B. Zero lift drag | |
| 442. |
If CM0 is -0.052 and lift coefficient at zero angle CL0 is 0.92 then, find CMac. Consider rectangular wing. |
| A. | -0.282 |
| B. | 0.98 |
| C. | 2.5 |
| D. | 7.89 |
| Answer» B. 0.98 | |
| 443. |
A rectangular wing has chord of 2m. Fond neutral point for this wing. |
| A. | 50 cm |
| B. | 290 cm |
| C. | 189 cm |
| D. | 267 m |
| Answer» B. 290 cm | |
| 444. |
Find the appropriate value of pitching moment coefficient derivative if lift curve slope is 0.032 per degree and Xcg is 0.3. Consider neutral point is located at 60 % of chord from leading edge. |
| A. | -0.0096 per degree |
| B. | -7 per degree |
| C. | 2.56 per degree |
| D. | 0.1 |
| Answer» B. -7 per degree | |
| 445. |
If SM = 0.12 and cg is located at 20% chord from l.e. then, find appropriate neutral point location. |
| A. | 0.32 |
| B. | 0.87 |
| C. | 2.3 |
| D. | 1.54 |
| Answer» B. 0.87 | |
| 446. |
Determine required static margin if lift curve slope is 6.5 per rad and pitching moment coefficient slope as -0.58 per rad. |
| A. | 8.9% |
| B. | 78% |
| C. | 0.89 |
| D. | 8.403 |
| Answer» B. 78% | |
| 447. |
Find elevator control power in per rad. |
| A. | -0.0166 per rad |
| B. | -12.33 |
| C. | 0.0015 per rad |
| D. | 0.098 per °View Answer |
| Answer» B. -12.33 | |
| 448. |
Determine trim angle if, trim lift coefficient is 0.75 and lift curve slope is 4.5per rad. Consider elevator deflection as 1.056 per rad and trim elevator angle of 0.020 rad. |
| A. | 0.1619 rad |
| B. | 0.1619° |
| C. | 2.98 rad |
| D. | 34.23 rad |
| Answer» B. 0.1619° | |
| 449. |
Thrust will affect the stability of the aircraft. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 450. |
Canard will provide longitudinal static stability. |
| A. | False |
| B. | True |
| Answer» B. True | |