MCQOPTIONS
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MCQOPTIONS
This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Heat Transfer Operations knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If the mole fraction of solutes in the feed is 0.2 and in product is 0.75, then what is the evaporate formation rate if product formation rate is = 15kg/hr? |
| A. | 45.25 kg |
| B. | 44.25 kg |
| C. | 41.25 kg |
| D. | 43.25 kg |
| Answer» D. 43.25 kg | |
| 2. |
What is the correct representation of the solution temperature as the evaporation proceeds in an evaporator? |
| A. | <a href="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-written-test-questions-answers-q10a.png"><img alt="Representation of solution temperature as evaporation proceeds in an evaporator - option a" class="alignnone size-full wp-image-249868" height="191" src="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-written-test-questions-answers-q10a.png" width="209"/></a> |
| B. | <a href="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-questions-answers-enthalpy-single-evaporator-q10b.png"><img alt="Representation of solution temperature as evaporation proceeds in an evaporator - option b" class="alignnone size-full wp-image-248110" height="185" src="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-questions-answers-enthalpy-single-evaporator-q10b.png" width="200"/></a> |
| C. | <a href="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-questions-answers-enthalpy-single-evaporator-q10c.png"><img alt="Representation of solution temperature as evaporation proceeds in an evaporator - option c" class="alignnone size-full wp-image-248111" height="187" src="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-questions-answers-enthalpy-single-evaporator-q10c.png" width="196"/></a> |
| D. | <a href="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-questions-answers-enthalpy-single-evaporator-q10d.png"><img alt="Representation of solution temperature as evaporation proceeds in an evaporator - option d" class="alignnone size-full wp-image-248112" height="187" src="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-questions-answers-enthalpy-single-evaporator-q10d.png" width="200"/></a> |
| Answer» B. <a href="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-questions-answers-enthalpy-single-evaporator-q10b.png"><img alt="Representation of solution temperature as evaporation proceeds in an evaporator - option b" class="alignnone size-full wp-image-248110" height="185" src="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-questions-answers-enthalpy-single-evaporator-q10b.png" width="200"/></a> | |
| 3. |
Why is the calculated heat transfer area more than the inner surface heat transfer area of the evaporator? |
| A. | Because the area is outer surface area |
| B. | Because the area is equivalent to a large diameter |
| C. | Because the area is on a diameter between outer and inner diameter |
| D. | Area is more than outer surface area |
| Answer» D. Area is more than outer surface area | |
| 4. |
What is the overall heat transfer coefficient of an evaporator setup of internal diameter is 30cm and 1m length cylinder in order to evaporate 10kg of water from a feed of 50kg at a temperature of 25 to a final temperature of 150 ? Saturated temperature of steam = 160
|
| A. | nSpecific heat capacity of solution = 4 KJ/Kg K |
| B. | 503 kJ/m<sup>2</sup> K |
| C. | 553 kJ/m<sup>2</sup> K |
| D. | 5553 kJ/m<sup>2</sup> K |
| E. | 5053 kJ/m<sup>2</sup> K |
| Answer» D. 5553 kJ/m<sup>2</sup> K | |
| 5. |
What is the amount of heat that needs to be supplied in order to evaporate 10kg of water from a feed of 50kg at a temperature of 25 to a final temperature of 150 ?
|
| A. | nSpecific heat capacity of solution = 4 KJ/Kg K |
| B. | 52600 KJ |
| C. | 56200 KJ |
| D. | 2272.6 MJ |
| E. | 47600 KJ |
| Answer» E. 47600 KJ | |
| 6. |
If Qs is heat supplied by the steam and Qf is the heat evolved in the feed, then the overall heat transfer coefficient can be represented as? Here AF = Area of film and AW = Area of wall. |
| A. | U = Qf/A<sub>W</sub> T |
| B. | U = Qs/A<sub>F</sub> T |
| C. | U = (Qs Qf)/A<sub>W</sub> T |
| D. | U = (Qs Qf)/A<sub>F</sub> T |
| Answer» B. U = Qs/A<sub>F</sub> T | |
| 7. |
In the given equation, what do you understand by the enthalpy balance, which element is it applied for?
|
| A. | Feed |
| B. | Steam |
| C. | Vapour |
| D. | Evaporator wall |
| Answer» B. Steam | |
| 8. |
The amount of heat transferred through the evaporator wall is actually equal to which one of the following? |
| A. | The steam condensing on the outer wall |
| B. | The heat carried by the vapour leaving the evaporator |
| C. | The total heat of increasing the feed temperature to boiling point |
| D. | The total heat of increasing the feed temperature to boiling point and the vapour |
| Answer» E. | |
| 9. |
The flow of vapour in an evaporator is assumed to be non-condensable else the calculations would differ for the evaporator if the gas condenses. |
| A. | True |
| B. | False |
| Answer» C. | |
| 10. |
Which one of the following is not an assumption taken before applying enthalpy balance on the evaporator? |
| A. | No solid should precipitate out from the concentrating solution |
| B. | The superheat and sub-cooling conditions of the condensable steam is negligible |
| C. | No fouling should occur on the evaporator surface |
| D. | Flow of non-condensable gas is negligible |
| Answer» D. Flow of non-condensable gas is negligible | |