Explore topic-wise MCQs in Mechanical Metallurgy Questions and Answers.

This section includes 6 Mcqs, each offering curated multiple-choice questions to sharpen your Mechanical Metallurgy Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.

1.

Stress analysis of structural material for the submarine gives the state of stress as shown in the figure. The yield strength of the material is 450 MPa. Using Tresca’s yielding criteria determine whether yielding will occur or not? If not, what is the factor of safety?

A. Yielding will not occur
B. Yielding will occur, and the factor of safety is 1.125
C. Yielding will occur, and the factor of safety is 1.53
D. Yielding will occur, and the factor of safety is 1.28
Answer» C. Yielding will occur, and the factor of safety is 1.53
Discussion
2.

The value of constant k in Tresca’s yielding criteria in case of pure shear will be equal to ___________ Given that Principle stress being σ1, σ2, σ3 and yield stress in tension and pure shear are equal to σo and τ.

A. k = σo
B. k = σo/2
C. k = σo/3
D. k = σo/4
Answer» C. k = σo/3
Discussion
3.

Tresca or maximum-shear stress criteria assumes that yielding occurs when the maximum shear stress reaches a value of the shear stress in the uniaxial tension test. Assume the principal stress being σ1, σ2, σ3 where σ1 is largest, and σ3 is the smallest principal stresses. Find the value of minimum shear stress to cause yielding, given that yield stress in tension is equal to σo?

A. τ = σo
B. τ = σo/2
C. τ = σo/3
D. τ = σo/4
Answer» C. τ = σo/3
Discussion
4.

Stress analysis of structural material for the submarine gives the state of stress as shown in the figure. The yield strength of the material is 450 MPa. Using Von-mises yielding criteria determine whether yielding will occur or not? If not, what is the factor of safety?

A. Yielding will not occur
B. Yielding will occur, and the factor of safety is 2.5
C. Yielding will occur, and the factor of safety is 1.53
D. Yielding will occur, and the factor of safety is 1.28
Answer» E.
Discussion
5.

The final result for von-Mises theory for the distortion relating the yield stress with stress deviator is:

A. σo = 1/√2 [(σ1-σ2)2+(σ2-σ3)2+(σ3-σ1)2]1/2
B. Where σo yield stress in uniaxial tension.
C. True
D. False
Answer» B. Where σo yield stress in uniaxial tension.
Discussion
6.

Von-mises or Distortion-energy Criteria proposed that yielding will occur when the second invariant of the stress deviator J2 exceeds some critical value. The second invariant of the stress deviator J2 is equal to __________

A. 1/6 [(σ1 – σ2)2+(σ2 – σ3)2+(σ3 – σ1)2]
B. 1/2 [(σ1 – σ2)2+(σ2 – σ3)2+(σ3 – σ1)2]
C. [σ1 + σ2 + σ3]
D. 1/2 [(σ1 – σ2)+(σ2 – σ3)+(σ3 – σ1)]
Answer» B. 1/2 [(σ1 – σ2)2+(σ2 – σ3)2+(σ3 – σ1)2]
Discussion