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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Soil Mechanics knowledge and support exam preparation. Choose a topic below to get started.
1. |
The partial differential of normal stress in y-direction in terms of effective stress is given by __________ |
A. | \(\frac{∂σ_y{‘}}{∂y}\) |
B. | \(\frac{∂σ_y{‘}}{∂y}-γ_w \frac{∂h}{∂y}\) |
C. | \(\frac{∂σ_y{‘}}{∂y}+γ_w \frac{∂h}{∂y}\) |
D. | \(\frac{∂σ_y{‘}}{∂y}*γ_w \frac{∂h}{∂y}\) |
Answer» D. \(\frac{∂σ_y{‘}}{∂y}*γ_w \frac{∂h}{∂y}\) | |
2. |
The partial differential of normal stress in x-direction in terms of effective stress is given by __________ |
A. | \(\frac{∂σ_x{‘}}{∂x}\) |
B. | \(\frac{∂σ_x{‘}}{∂x}-γ_w \frac{∂h}{∂x}\) |
C. | \(\frac{∂σ_x{‘}}{∂x}+γ_w \frac{∂h}{∂x}\) |
D. | \(\frac{∂σ_x{‘}}{∂x}*γ_w \frac{∂h}{∂x}\) |
Answer» D. \(\frac{∂σ_x{‘}}{∂x}*γ_w \frac{∂h}{∂x}\) | |
3. |
The normal stress in z-direction in terms of effective stress is given by __________ |
A. | σz= γw(h-he) |
B. | σz= σz’ |
C. | σz= σz’+γw(h-he) |
D. | σz= σz’-γw(h-h |
E. | σz= σz’c) σz= σz’+γw(h-he)d) σz= σz’-γw(h-he) |
Answer» D. σz= σz’-γw(h-h | |
4. |
The normal stress in y-direction in terms of effective stress is given by __________ |
A. | σy= σy’-γw(h-he) |
B. | σy= σy’+γw(h-he) |
C. | σy= σy’/γw(h-he) |
D. | σy= σy’*γw(h-h |
E. | σy= σy’+γw(h-he)c) σy= σy’/γw(h-he)d) σy= σy’*γw(h-he) |
Answer» C. σy= σy’/γw(h-he) | |
5. |
The normal stress in x-direction in terms of effective stress is given by __________ |
A. | σx= σx’+γw(h-he) |
B. | σx= σx’*γw(h-he) |
C. | σx= σx’-γw(h-he) |
D. | σx= σx’ |
E. | σx= σx’*γw(h-he)c) σx= σx’-γw(h-he)d) σx= σx’ |
Answer» B. σx= σx’*γw(h-he) | |
6. |
The equilibrium equations in terms of total stresses formed by summing all forces on z-direction is ________ |
A. | \(\frac{∂σ_x}{∂x} + \frac{∂τ_{yx}}{∂y} + \frac{∂τ_{zx}}{∂z} +Z=0\) |
B. | \(\frac{∂τ_{xy}}{∂x}+\frac{∂σ_y}{∂y}+\frac{∂τ_{zy}}{∂z}=0\) |
C. | \(\frac{∂τ_{xz}}{∂x} +\frac{∂τ_{yz}}{∂y} +\frac{∂σ_z}{∂z} +γ=0\) |
D. | \(\frac{∂σ_x}{∂x}+\frac{∂τ_{yx}}{∂y} +\frac{∂τ_{zx}}{∂z} = 0\) |
Answer» D. \(\frac{∂σ_x}{∂x}+\frac{∂τ_{yx}}{∂y} +\frac{∂τ_{zx}}{∂z} = 0\) | |
7. |
The equilibrium equations in terms of total stresses formed by summing all forces on y-direction is ________ |
A. | \(\frac{∂σ_x}{∂x} + \frac{∂τ_{yx}}{∂y} + \frac{∂τ_{zx}}{∂z} +X=0\) |
B. | \(\frac{∂τ_{xy}}{∂x}+\frac{∂σ_y}{∂y}+\frac{∂τ_{zy}}{∂z}=0\) |
C. | \(\frac{∂τ_{xz}}{∂x} +\frac{∂τ_{yz}}{∂y} +\frac{∂σ_z}{∂z} +Z=0\) |
D. | \(\frac{∂σ_x}{∂x}+\frac{∂τ_{yx}}{∂y} +\frac{∂τ_{zx}}{∂z} = 0\) |
Answer» C. \(\frac{∂τ_{xz}}{∂x} +\frac{∂τ_{yz}}{∂y} +\frac{∂σ_z}{∂z} +Z=0\) | |
8. |
The equilibrium equations in terms of total stresses formed by summing all forces on x-direction is ________ |
A. | \(\frac{∂σ_x}{∂x} + \frac{∂τ_{yx}}{∂y} + \frac{∂τ_{zx}}{∂z} +X=0\) |
B. | \(\frac{∂τ_{xy}}{∂x} + \frac{∂σ_y}{∂y} +\frac{∂τ_{zy}}{∂z}+Y=0\) |
C. | \(\frac{∂τ_{xz}}{∂x} +\frac{∂τ_{yz}}{∂y} +\frac{∂σ_z}{∂z} +Z=0\) |
D. | \(\frac{∂σ_x}{∂x}+\frac{∂τ_{yx}}{∂y} +\frac{∂τ_{zx}}{∂z} = 0\) |
Answer» E. | |
9. |
The three equations of static equilibrium of the problem of elasticity are not sufficient to solve the six unknown stress components. |
A. | True |
B. | False |
Answer» B. False | |
10. |
The problem of elasticity is _________ |
A. | strictly determinate |
B. | strictly indeterminate |
C. | in some cases indeterminate |
D. | cannot be classified as determinate or indeterminate |
Answer» C. in some cases indeterminate | |
11. |
The equilibrium equation obtained by summing all forces on z-direction is ________ |
A. | \(\frac{∂σ_x}{∂x} + \frac{∂τ_{yx}}{∂y} + \frac{∂τ_{zx}}{∂z} +X=0\) |
B. | \(\frac{∂τ_{xy}}{∂x} + \frac{∂σ_y}{∂y} +\frac{∂τ_{zy}}{∂z}+Y=0\) |
C. | \(\frac{∂τ_{xz}}{∂x} +\frac{∂τ_{yz}}{∂y} +\frac{∂σ_z}{∂z} +Z=0\) |
D. | \(\frac{∂σ_x}{∂x}+\frac{∂τ_{yx}}{∂y} +\frac{∂τ_{zx}}{∂z} = 0\) |
Answer» D. \(\frac{∂σ_x}{∂x}+\frac{∂τ_{yx}}{∂y} +\frac{∂τ_{zx}}{∂z} = 0\) | |
12. |
The equilibrium equation obtained by summing all forces on y-direction is ________ |
A. | \(\frac{∂σ_x}{∂x} + \frac{∂τ_{yx}}{∂y} + \frac{∂τ_{zx}}{∂z} +X=0\) |
B. | \(\frac{∂τ_{xy}}{∂x} + \frac{∂σ_y}{∂y} +\frac{∂τ_{zy}}{∂z}+Y=0\) |
C. | \(\frac{∂τ_{xz}}{∂x} +\frac{∂τ_{yz}}{∂y} +\frac{∂σ_z}{∂z} +Z=0\) |
D. | \(\frac{∂σ_x}{∂x}+\frac{∂τ_{yx}}{∂y} +\frac{∂τ_{zx}}{∂z} = 0\) |
Answer» C. \(\frac{∂τ_{xz}}{∂x} +\frac{∂τ_{yz}}{∂y} +\frac{∂σ_z}{∂z} +Z=0\) | |
13. |
The equilibrium equation obtained by summing all forces on x-direction is ________ |
A. | \(\frac{∂σ_x}{∂x} + \frac{∂τ_{yx}}{∂y} + \frac{∂τ_{zx}}{∂z} +X=0\) |
B. | \(\frac{∂τ_{xy}}{∂x} + \frac{∂σ_y}{∂y} +\frac{∂τ_{zy}}{∂z}+Y=0\) |
C. | \(\frac{∂τ_{xz}}{∂x} +\frac{∂τ_{yz}}{∂y} +\frac{∂σ_z}{∂z} +Z=0\) |
D. | \(\frac{∂σ_x}{∂x}+\frac{∂τ_{yx}}{∂y} +\frac{∂τ_{zx}}{∂z} = 0\) |
Answer» B. \(\frac{∂τ_{xy}}{∂x} + \frac{∂σ_y}{∂y} +\frac{∂τ_{zy}}{∂z}+Y=0\) | |
14. |
The normal stress component acting at the centre, in the given diagram, will be _________ to the face (A C C1 A1). |
A. | increased to \((σ_y+\frac{∂σ_y}{∂y}\frac{dy}{2}) \) |
B. | decreased to \((σ_y-\frac{∂σ_y}{∂y}\frac{dy}{2}) \) |
C. | equal to σY |
D. | equal to σz |
Answer» C. equal to σY | |
15. |
The normal stress component acting at the centre, in the given diagram, will be _________ to the face (B D D1 B1). |
A. | increased to \((σ_y+\frac{∂σ_y}{∂y}\frac{dy}{2}) \) |
B. | decreased to \((σ_y-\frac{∂σ_y}{∂y}\frac{dy}{2}) \) |
C. | equal to σY |
D. | equal to σz |
Answer» B. decreased to \((σ_y-\frac{∂σ_y}{∂y}\frac{dy}{2}) \) | |