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This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Applied Chemistry knowledge and support exam preparation. Choose a topic below to get started.
1. |
Calculate the HCV of the coal from the given data:Weight of the fuel burnt=0.92Initial temperature=120CFinal temperature=19.20CWeight of the water in calorimeter is 1458gWater equivalent of calorimeter = 14g. |
A. | 11520k.cal/m3 |
B. | 11560k.cal/m3 |
C. | 11000k.cal/m3 |
D. | 11590k.cal/m3 |
Answer» B. 11560k.cal/m3 | |
2. |
Modification of the dulong’s formula can be done by considering the ___________ |
A. | latent heat |
B. | heat |
C. | fuel state |
D. | liquid fuels |
Answer» B. heat | |
3. |
The dulong’s formula is not applicable for __________ |
A. | solid fuel |
B. | gaseous fuel |
C. | liquid fuel |
D. | any fuel |
Answer» C. liquid fuel | |
4. |
C=70%, O=10%, N=1%, S=5% and ash=4%.The NCV of the fuel was found to be 9210cal/g. percentage of hydrogen be x and HCV of the fuel be y. Find out y/x.a) 747.7b) 768c) 777d) 676.9 4.A formula giving the gross heating value of coal in terms of the weight fractions of carbon, hydrogen, oxygen and sulphur from the _________ |
A. | 747.7b) 768c) 777d) 676.9 4.A formula giving the gross heating value of coal in terms of the weight fractions of carbon, hydrogen, oxygen and sulphur from the _________a) ultimate analysis |
B. | 768c) 777d) 676.9 4.A formula giving the gross heating value of coal in terms of the weight fractions of carbon, hydrogen, oxygen and sulphur from the _________a) ultimate analysisb) proximate analysis |
C. | 777d) 676.9 4.A formula giving the gross heating value of coal in terms of the weight fractions of carbon, hydrogen, oxygen and sulphur from the _________a) ultimate analysisb) proximate analysisc) distillation |
D. | 676.9 4.A formula giving the gross heating value of coal in terms of the weight fractions of carbon, hydrogen, oxygen and sulphur from the _________a) ultimate analysisb) proximate analysisc) distillationd) filtrationView Answer |
Answer» B. 768c) 777d) 676.9 4.A formula giving the gross heating value of coal in terms of the weight fractions of carbon, hydrogen, oxygen and sulphur from the _________a) ultimate analysisb) proximate analysis | |
5. |
A coal has the following composition by weight: C=90%, O=4%, N=1%, S=0.5% and ash=5%.The NCV of the fuel was found to be 8480cal/g. Calculate the percentage of hydrogen and HCV of the fuel. |
A. | H=4.21%, HCV=8621.80cal/g |
B. | H=4.521%, HCV=8221.80cal/g |
C. | H=4.686%, HCV=8727.37cal/g |
D. | H=4.1%, HCV=8221.37cal/g |
Answer» D. H=4.1%, HCV=8221.37cal/g | |
6. |
Calculate the net calorific value of a coal sample having the following composition:C=80%, H=5%, O=4%, N=3%, S=3.5% and ash=5%. |
A. | 7251.8cal/g |
B. | 7780.5cal/g |
C. | 7621.5cal/g |
D. | 7830.75cal/g |
Answer» E. | |
7. |
While calculating HCV, if we need to apply the fuse wire, acid and cooling corrections then what is the formula for HCV? |
A. | HCV= [(W + w)(t2-t1+cooling correction)-(acid correction + fuse correction)]/weight of fuel |
B. | HCV= [(W + w)(t2+t1+cooling correction)-(acid correction + fuse correction)]/weight of fuel |
C. | HCV= [(W + w)(t2-t1+ acid correction)-( cooling correction + fuse correction)]/weight of fuel |
D. | CV= [(W + w)(t2+t1+ acid correction)-( cooling correction + fuse correction)]/weight of fuel |
Answer» B. HCV= [(W + w)(t2+t1+cooling correction)-(acid correction + fuse correction)]/weight of fuel | |
8. |
Modification of the dulong’s formula can be done by considering the______$ |
A. | latent heat |
B. | heat |
C. | fuel state |
D. | liquid fuels |
Answer» B. heat | |
9. |
The dulong’s formula is not applicable for_____$ |
A. | solid fuel |
B. | gaseous fuel |
C. | liquid fuel |
D. | any fuel |
Answer» C. liquid fuel | |
10. |
A formula giving the gross heating value of coal in terms of the weight fractions of carbon, hydrogen, oxygen and sulphur from the _________ |
A. | ultimate analysis |
B. | proximate analysis |
C. | distillation |
D. | filtration |
Answer» B. proximate analysis | |
11. |
C=70%, O=10%, N=1%, S=5% and ash=4%.The NCV of the fuel was found to be 9210cal/g. percentage of hydrogen be x and HCV of the fuel be y. Find out y/x. |
A. | 747.7 |
B. | 768 |
C. | 777 |
D. | 676.9 |
Answer» B. 768 | |
12. |
A coal has the following composition by weight: |
A. | |
B. | H=4.21%, HCV=8621.80cal/g |
C. | H=4.521%, HCV=8221.80cal/g |
Answer» D. | |