Explore topic-wise MCQs in Signals & Systems.

This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Signals & Systems knowledge and support exam preparation. Choose a topic below to get started.

1.

The Nyquist frequency for the signal x (t) = 3 cos 50 t + 10 sin 300 t cos 100t is ___________

A. 50 Hz
B. 100 Hz
C. 200 Hz
D. 300 Hz
Answer» E.
2.

A discrete time signal is as given below
X [n] = cos ( ( frac{ n}{2} )) sin ( ( frac{ n}{8} )) + 3 cos ( ( frac{ n}{4} + frac{ }{3}) )
The period of the signal X [n] is _____________

A. 16
B. 4
C. 2
D. Non-periodic
Answer» B. 4
3.

A Discrete signal is said to be even or symmetric if X(-n) is equal to __________

A. X(n)
B. 0
C. X(n)
D. X(-n)
Answer» B. 0
4.

A discrete time signal is as given below
X [n] = cos ( ( frac{n}{8} )) cos ( ( frac{ n}{8} ))

A. nThe period of the signal X [n] is _____________
B. 16
C. 16( +1)
D. 8
E. Non-periodic
Answer» E. Non-periodic
5.

F(t) and G(t) are the one-sided z-transforms of discrete time functions f(nt) and g(nt), the z-transform of f(kt)g(nt-kt) is given by _____________

A. f(nt)g(nt)z<sup>-n</sup>
B. f(nt)g(nt)z<sup>n</sup>
C. f(kt)g(nt-kt) z<sup>-n</sup>
D. f(nt-kt)g(nt)z<sup>-n</sup>
Answer» B. f(nt)g(nt)z<sup>n</sup>
6.

What is the steady state value of The DT signal F (t), if it is known that F(s) = ( frac{1}{(s+2)^2 (s+4)} )?

A. ( frac{1}{16} )
B. Cannot be determined
C. 0
D. ( frac{1}{8} )
Answer» D. ( frac{1}{8} )
7.

A discrete time signal is given as X [n] = cos ( frac{ n}{9} ) + sin ( ( frac{ n}{7} + frac{1}{2} )). The period of the signal X [n] is ______________

A. 126
B. 32
C. 252
D. Non-periodic
Answer» B. 32
8.

The time system which operates with a continuous time signal and produces a continuous time output signal is _________

A. CTF system
B. DTF System
C. Time invariant System
D. Time variant System
Answer» B. DTF System
9.

Given a discrete time signal x[k] defined by x[k] = 1, for -2 k 2 and 0, for |k|>2. Then, y[k] = x[3k-2] is ______________

A. y[k] = 1, for k = 0, 1 and 0 otherwise
B. y[k] = 1, for k = 1 and -1 for k=-1
C. y[k] = 1, for k = 0, 1 and -1 otherwise
D. y[k] = 1, for k = 0, 1 and 0 otherwise
Answer» B. y[k] = 1, for k = 1 and -1 for k=-1