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This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Signals & Systems knowledge and support exam preparation. Choose a topic below to get started.
1. |
The Nyquist frequency for the signal x (t) = 3 cos 50 t + 10 sin 300 t cos 100t is ___________ |
A. | 50 Hz |
B. | 100 Hz |
C. | 200 Hz |
D. | 300 Hz |
Answer» E. | |
2. |
A discrete time signal is as given below
|
A. | 16 |
B. | 4 |
C. | 2 |
D. | Non-periodic |
Answer» B. 4 | |
3. |
A Discrete signal is said to be even or symmetric if X(-n) is equal to __________ |
A. | X(n) |
B. | 0 |
C. | X(n) |
D. | X(-n) |
Answer» B. 0 | |
4. |
A discrete time signal is as given below
|
A. | nThe period of the signal X [n] is _____________ |
B. | 16 |
C. | 16( +1) |
D. | 8 |
E. | Non-periodic |
Answer» E. Non-periodic | |
5. |
F(t) and G(t) are the one-sided z-transforms of discrete time functions f(nt) and g(nt), the z-transform of f(kt)g(nt-kt) is given by _____________ |
A. | f(nt)g(nt)z<sup>-n</sup> |
B. | f(nt)g(nt)z<sup>n</sup> |
C. | f(kt)g(nt-kt) z<sup>-n</sup> |
D. | f(nt-kt)g(nt)z<sup>-n</sup> |
Answer» B. f(nt)g(nt)z<sup>n</sup> | |
6. |
What is the steady state value of The DT signal F (t), if it is known that F(s) = ( frac{1}{(s+2)^2 (s+4)} )? |
A. | ( frac{1}{16} ) |
B. | Cannot be determined |
C. | 0 |
D. | ( frac{1}{8} ) |
Answer» D. ( frac{1}{8} ) | |
7. |
A discrete time signal is given as X [n] = cos ( frac{ n}{9} ) + sin ( ( frac{ n}{7} + frac{1}{2} )). The period of the signal X [n] is ______________ |
A. | 126 |
B. | 32 |
C. | 252 |
D. | Non-periodic |
Answer» B. 32 | |
8. |
The time system which operates with a continuous time signal and produces a continuous time output signal is _________ |
A. | CTF system |
B. | DTF System |
C. | Time invariant System |
D. | Time variant System |
Answer» B. DTF System | |
9. |
Given a discrete time signal x[k] defined by x[k] = 1, for -2 k 2 and 0, for |k|>2. Then, y[k] = x[3k-2] is ______________ |
A. | y[k] = 1, for k = 0, 1 and 0 otherwise |
B. | y[k] = 1, for k = 1 and -1 for k=-1 |
C. | y[k] = 1, for k = 0, 1 and -1 otherwise |
D. | y[k] = 1, for k = 0, 1 and 0 otherwise |
Answer» B. y[k] = 1, for k = 1 and -1 for k=-1 | |