MCQOPTIONS
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MCQOPTIONS
This section includes 287 Mcqs, each offering curated multiple-choice questions to sharpen your Computer Science knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
The ASCII code is a 7-bit code for |
| A. | letters |
| B. | numbers |
| C. | other symbols |
| D. | All of the above |
| Answer» E. | |
| 152. |
Which of the following boolean algebra statements represent commutative law |
| A. | (A+B)+CA+(B+C) |
| B. | A.(B+C)(A.B)+(A.C) |
| C. | A+BB+A |
| D. | A+AA |
| Answer» D. A+AA | |
| 153. |
In boolean algebra, the times sign stands for the _____ operation |
| A. | AND |
| B. | OR |
| C. | NAND |
| D. | NOR |
| Answer» B. OR | |
| 154. |
The maximum count which a 6-bit binary word can represent is |
| A. | 36 |
| B. | 64 |
| C. | 63 |
| D. | 65 |
| Answer» D. 65 | |
| 155. |
The output of the following gate is 0 only if at least one of the inputs is 1: |
| A. | AND gate |
| B. | OR gate |
| C. | EX-OR gate |
| D. | NOR gate |
| Answer» E. | |
| 156. |
Conversion of an octal number 1438 to hexadecimal number is |
| A. | 6316 |
| B. | 6016 |
| C. | 5016 |
| D. | 5716 |
| Answer» B. 6016 | |
| 157. |
Conversion of binary number 1011012 to its decimal number is |
| A. | 4510 |
| B. | 4310 |
| C. | 4010 |
| D. | 4710 |
| Answer» B. 4310 | |
| 158. |
The EXCLUSIVE - NOR gate is equivalent to an _____ gate followed by an invertor. |
| A. | OR |
| B. | AND |
| C. | NAND |
| D. | XOR |
| Answer» E. | |
| 159. |
What advantages do ICs have over discrete-device circuits due to their greater complexity (i.e. more circuitary in less area) |
| A. | Smaller size |
| B. | Higher reliability |
| C. | Lower cost |
| D. | All of the above |
| Answer» E. | |
| 160. |
Conversion of binary number 1011102 to an octal number is |
| A. | 358 |
| B. | 468 |
| C. | 568 |
| D. | 508 |
| Answer» D. 508 | |
| 161. |
Which of the following logic families use bipolar transistors? |
| A. | TTL |
| B. | GaAS |
| C. | NMOS |
| D. | CMOS |
| Answer» B. GaAS | |
| 162. |
Parallel adders are |
| A. | combinational logic circuits |
| B. | sequential logic circuits |
| C. | both of the above |
| D. | All of the above |
| Answer» B. sequential logic circuits | |
| 163. |
The dynamic race hazard problem occurs in |
| A. | combinational circuits only |
| B. | sequential circuits only |
| C. | both combinational and sequential circuits |
| D. | none of the combinational and sequential circuits |
| Answer» E. | |
| 164. |
When an inverter is placed between both inputs of an SR flip-flop, the resulting flip-flop is |
| A. | JK flip-flop |
| B. | D flip-flop |
| C. | T flip-flop |
| D. | Master slave JK flip-flop |
| Answer» C. T flip-flop | |
| 165. |
Addition of 1101011012, 1110111012, 0001111112, 1001011012, 1111101112 is |
| A. | 10110100000000 |
| B. | 11110100000000 |
| C. | 10001000000000 |
| D. | 10010000000000 |
| Answer» B. 11110100000000 | |
| 166. |
Computers use thousands of flip-flops. To coordinate the overall action, a common signal called the _____ is sent to each flip-flop. |
| A. | latch |
| B. | clock |
| C. | master |
| D. | slave |
| Answer» C. master | |
| 167. |
A NAND gate is equivalent to an AND gate followed by an inverter. All inputs must be _____ to get a low output |
| A. | low |
| B. | high |
| C. | some low and some high |
| D. | 0's |
| Answer» C. some low and some high | |
| 168. |
Conversion of binary number 1100002 to hexadecimal is |
| A. | 3016 |
| B. | 4016 |
| C. | 4316 |
| D. | 2716 |
| Answer» B. 4016 | |
| 169. |
Which of the following logic expression is wrong? |
| A. | 1 + 0=1 |
| B. | 1 + 1=0 |
| C. | 1+0+1 = 1 |
| D. | 1 + 1 + 1 = 1 |
| Answer» D. 1 + 1 + 1 = 1 | |
| 170. |
Conversion of binary number 11011001111110002 to hexadecimal number is |
| A. | D8F816 |
| B. | A8B916 |
| C. | 78916 |
| D. | D9F816 |
| Answer» E. | |
| 171. |
One way to simplify the sum-of-products equation is to use boolean algebra. Another way is the _____ map. |
| A. | De Morgan |
| B. | Standard |
| C. | Schottky |
| D. | Karnaugh |
| Answer» E. | |
| 172. |
Conversion of decimal number 2810 to it's octal number equivalent is |
| A. | 328 |
| B. | 408 |
| C. | 348 |
| D. | 368 |
| Answer» D. 368 | |
| 173. |
The _____ is a sequence of instructions that tells the computer how to process the data. |
| A. | data |
| B. | program |
| C. | controls |
| D. | instruction |
| Answer» C. controls | |
| 174. |
The leading bit stands for the _____ and the remaining bits for the _____ is known as signed binary numbers. |
| A. | sign, remainder |
| B. | sign, magnitude |
| C. | value, sign |
| D. | variable, value |
| Answer» C. value, sign | |
| 175. |
A shift register can be used for |
| A. | parallel to serial conversion |
| B. | serial to parallel conversion |
| C. | digital delay line |
| D. | All of the above |
| Answer» E. | |
| 176. |
A shift register can be used for: |
| A. | parallel to serial conversion |
| B. | serial to parallel conversion |
| C. | digital delay line |
| D. | all of the above |
| Answer» E. | |
| 177. |
Conversion of binary number 11000112 to an octal number is |
| A. | 1408 |
| B. | 1438 |
| C. | 1478 |
| D. | 1498 |
| Answer» C. 1478 | |
| 178. |
The radix of the binary number is: |
| A. | 3 |
| B. | 1 |
| C. | 2 |
| D. | 10 |
| Answer» D. 10 | |
| 179. |
The number of input words in a truth table always equals _____ where n is the number of inputs bits. |
| A. | 10n |
| B. | 2n |
| C. | 4n |
| D. | 8n |
| Answer» C. 4n | |
| 180. |
The digits used in a binary number system are _____ and _____ |
| A. | 9 and 0 |
| B. | 0 and 1 |
| C. | 1 and 2 |
| D. | 3 and 4 |
| Answer» C. 1 and 2 | |
| 181. |
The 2's compliment of binary number 0.01011 is: |
| A. | 1.10101 |
| B. | 0.10101 |
| C. | 1.101 |
| D. | 0.101 |
| Answer» B. 0.10101 | |
| 182. |
The main advantage of hexadecimal numbers is the case of conversion from hexadecimal to _____ and vice versa. |
| A. | decimal |
| B. | binary |
| C. | ASCE |
| D. | BCD |
| Answer» C. ASCE | |
| 183. |
The number of two-input NAND gates required to produce the two-input OR function is |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» D. 4 | |
| 184. |
An inventor is a gate with only _____ input; the output is always in the opposite state from the input |
| A. | one |
| B. | two |
| C. | more than one |
| D. | All of the above |
| Answer» B. two | |
| 185. |
Addition of 11012 and 10102 is |
| A. | 101012 |
| B. | 110002 |
| C. | 110112 |
| D. | 101112 |
| Answer» E. | |
| 186. |
How many bits are required to encode all twenty six letters ten symbols, and ten numerals? |
| A. | 5 |
| B. | 6 |
| C. | 2 |
| D. | 3 |
| Answer» C. 2 | |
| 187. |
Conversion of decimal number 9910 to hexadecimal number is |
| A. | 6316 |
| B. | 816 |
| C. | 6116 |
| D. | 5016 |
| Answer» B. 816 | |
| 188. |
Names, numbers, and other information needed to solve a problem are called _____ |
| A. | program |
| B. | instruction |
| C. | data |
| D. | controls |
| Answer» D. controls | |
| 189. |
Which logic family dissipates the minimum power? |
| A. | DTL |
| B. | TTL |
| C. | ECL |
| D. | CMOS |
| Answer» E. | |
| 190. |
Which of the following electronic component is not found in ordinary ICs? |
| A. | diodes |
| B. | resistors |
| C. | transistors |
| D. | inductors |
| Answer» E. | |
| 191. |
A NOR gate has two or more input signals. All input must be _____ to get a high output |
| A. | low |
| B. | high |
| C. | some low some high |
| D. | 1's |
| Answer» B. high | |
| 192. |
Conversion of binary number 10010012 to hexadecimal is |
| A. | 4016 |
| B. | 3916 |
| C. | 4916 |
| D. | 4216 |
| Answer» D. 4216 | |
| 193. |
Conversion of binary number 1100012 to its decimal number is |
| A. | 2710 |
| B. | 4910 |
| C. | 3910 |
| D. | 5010 |
| Answer» C. 3910 | |
| 194. |
Conversion of decimal number 1310 to it's octal number equivalent is |
| A. | 158 |
| B. | 178 |
| C. | 138 |
| D. | 118 |
| Answer» B. 178 | |
| 195. |
The _____ gate has two or more input signals. All inputs must be high to get a high output |
| A. | OR |
| B. | NAND |
| C. | AND |
| D. | NOR |
| Answer» D. NOR | |
| 196. |
Which of the following is not true? |
| A. | 0X0 = 0 |
| B. | 0 x 1 = 1 |
| C. | 1 x 0 = 0 |
| D. | 1 x 1 = 1 |
| Answer» C. 1 x 0 = 0 | |
| 197. |
Flip-flop outputs are always |
| A. | complimentary |
| B. | the same |
| C. | independent of each other |
| D. | same as inputs |
| Answer» B. the same | |
| 198. |
Resistor Ratio design is used in linear ICs because |
| A. | Ratios increase input resistance |
| B. | Ratios increase amplifier gain |
| C. | Precise resistor values are not possible with IC processes |
| D. | All of the above |
| Answer» D. All of the above | |
| 199. |
Express 8192 in K units. |
| A. | 8 x 103 K |
| B. | 8.192 k |
| C. | 8K |
| D. | All of the above |
| Answer» D. All of the above | |
| 200. |
What is the 2's complement of 0011 0101 1001 1100 number? |
| A. | 1100 1010 1100 1011 |
| B. | 1100 1010 0110 0011 |
| C. | 1100 1010 0110 0100 |
| D. | 1100 1010 1111 1111 |
| Answer» D. 1100 1010 1111 1111 | |