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This section includes 4 Mcqs, each offering curated multiple-choice questions to sharpen your Computational Fluid Dynamics Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
1. |
What is the relationship between \(\vec{E_f} \,and\, \vec{S_f}\) using the over-relaxed approach? |
A. | \(\vec{E_f}=(\vec{S_f} ).\vec{e}\) |
B. | \(\vec{E_f}=(\frac{S_f}{cos \theta}) \vec{e}\) |
C. | \(\vec{E_f}=(\vec{S_f})×\vec{e}\) |
D. | \(\vec{E_f}=((\vec{S_f}).\vec{e} ) \vec{e}\) |
Answer» C. \(\vec{E_f}=(\vec{S_f})×\vec{e}\) | |
2. |
In the over-relaxed approach, the importance of the term involving ΦF and ΦC _________ as the non-orthogonality _________ |
A. | decreases, increases |
B. | remains the same, increases |
C. | increases, remains the same |
D. | increases, increases |
Answer» E. | |
3. |
In the orthogonal correction approach, the relationship between \(\vec{E_f}\, and\, \vec{S_f}\) is ________ |
A. | \(\vec{E_f}=\vec{S_f}×\vec{e}\) |
B. | \(\vec{E_f}=S_f cos\theta\vec{e}\) |
C. | \(\vec{E_f}=S_f\vec{e}\) |
D. | \(\vec{E_f}=\vec{S_f}.\vec{e}\) |
Answer» D. \(\vec{E_f}=\vec{S_f}.\vec{e}\) | |
4. |
In the minimum correction approach of decomposing the surface vector of a non-orthogonal grid, the relationship between the vector connecting the owner and the neighbour node \((\vec{E_f})\) and the surface vector \((\vec{S_f})\) is given as _________ |
A. | \(\vec{S_f} sin\theta.\vec{e}\) |
B. | \(\vec{S_f} cos\theta.\vec{e}\) |
C. | \((S_f cos\theta) \vec{e}\) |
D. | \((S_f sin\theta) \vec{e}\) |
Answer» D. \((S_f sin\theta) \vec{e}\) | |