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This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Chemistry knowledge and support exam preparation. Choose a topic below to get started.
1. |
Junker s calorimeter cannot be used for measuring the calorific value of volatile liquid fuel. |
A. | True |
B. | False |
Answer» B. False | |
2. |
Determine net calorific value of a volatile liquid fuel, having following results after using Boy s calorimeter: Volume of the liquid fuel burnt = 0.152 m3, weight of the water used for cooling = 48.5 kg, Weight of the steam condensed = 91 gm, Temperature of inlet water = 35.2 0C and Temperature of outlet water = 42.6 0C? |
A. | 2361.184 Kcal/m<sup>3</sup> |
B. | 2013.348 Kcal/m<sup>3</sup> |
C. | 2256.95 Kcal/m<sup>3</sup> |
D. | 2185.679 Kcal/m<sup>3</sup> |
Answer» C. 2256.95 Kcal/m<sup>3</sup> | |
3. |
Determine the gross calorific value (GCV) of a gas, having following results after using Boy s calorimeter: Volume of the gaseous fuel burnt = 0.093 m3, weight of the water used for cooling = 30.5 kg, Weight of the steam condensed = 31 gm, Temperature of inlet water = 26.1 0C and Temperature of outlet water = 36.5 0C? |
A. | 3100 Kcal/m<sup>3</sup> |
B. | 3310 cal/gm |
C. | 3410 Kcal/m<sup>3</sup> |
D. | 3780 Kcal/gm |
Answer» D. 3780 Kcal/gm | |
4. |
What is the basic formula for calculating NCV in Boy s Calorimeter? |
A. | NCV = GCV (m/V) 587 |
B. | NCV = GCV (V/m) 587 |
C. | NCV = GCV + (m/V) 587 |
D. | NCV = GCV + (V/m) 587 |
Answer» B. NCV = GCV (V/m) 587 | |
5. |
What is the main source of error in conducting the experiment of Boy s calorimeter? |
A. | The temperature of gas is greater than the room temperature |
B. | Due to presence of moisture |
C. | The mass of the gas is comparatively low |
D. | Due to the rise in ambient temperature |
Answer» E. | |
6. |
What is the basic formula for calculating GCV in Boy s calorimeter? |
A. | GCV = w(t<sub>2</sub>+t<sub>1</sub>)/V |
B. | GCV = w(t<sub>2</sub>-t<sub>1</sub>)/V |
C. | GCV = V(t<sub>2</sub>+t<sub>1</sub>)/w |
D. | GCV = V(t<sub>2</sub>-t<sub>1</sub>)/w |
Answer» C. GCV = V(t<sub>2</sub>+t<sub>1</sub>)/w | |
7. |
What is the use of insulating baffles in Boy s thermometer? |
A. | To deflect the gas upwards so that it can pass through the holes of the calorimeter |
B. | To make the gas stable in copper tube |
C. | To decrease the rate of heating |
D. | To decrease the temperature of cold water which is obtained from inlet |
Answer» B. To make the gas stable in copper tube | |
8. |
The water condensed from the products of combustion is collected and settles in the Boy s bomb itself. |
A. | True |
B. | False |
Answer» C. | |
9. |
How many burners are used in Boy s calorimeter for finding the calorific value for gases and volatile liquid? |
A. | 4 |
B. | 3 |
C. | 1 |
D. | 2 |
Answer» E. | |
10. |
Apart from Boy s calorimeter, which process can be used for finding the calorific value of gases? |
A. | Bomb calorimeter |
B. | Heat balance calorimeter |
C. | Junker s calorimeter |
D. | Heat flow calorimeter |
Answer» D. Heat flow calorimeter | |