What is the relation between h(t) and Ha(s)?

Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{-st} dt\)

Ha(s)=\(\int_0^{\infty} h(t)e^{st} dt\)

Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{st} dt\)

Explore topic-wise MCQs in Digital Signal Processing Questions and Answers.

This section includes 2 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Signal Processing Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.

1.	If the conversion technique is to be effective, the jΩ axis in the s-plane should map into the unit circle in the z-plane.
A.	True
B.	False
Answer» B. False

Discussion

2.	What is the relation between h(t) and Ha(s)?
A.	Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{-st} dt\)
B.	Ha(s)=\(\int_0^{\infty} h(t)e^{st} dt\)
C.	Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{st} dt\)
D.	None of the mentioned
Answer» B. Ha(s)=\(\int_0^{\infty} h(t)e^{st} dt\)

Discussion

Explore topic-wise MCQs in Digital Signal Processing Questions and Answers.

If the conversion technique is to be effective, the jΩ axis in the s-plane should map into the unit circle in the z-plane.

What is the relation between h(t) and Ha(s)?