Explore topic-wise MCQs in Design Of Steel Structures.

This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Design Of Steel Structures knowledge and support exam preparation. Choose a topic below to get started.

1.

The compressive strength for ISMB 400 used as a column for length 5m with both ends hinged is

A. 275 kN
B. 375.4 kN
C. 453 kN
D. 382 kN
Answer» C. 453 kN
Discussion
2.

The value of design compressive strength is limited to

A. f<sub>y</sub> + <sub>m0</sub>
B. f<sub>y</sub>
C. f<sub>y</sub> <sub>m0</sub>
D. f<sub>y</sub> / <sub>m0</sub>
Answer» E.
Discussion
3.

The design compressive strength in terms of stress reduction factor is given by

A. Xf<sub>y</sub>
B. Xf<sub>y</sub> / <sub>m0</sub>
C. X /f<sub>y</sub> <sub>m0</sub>
D. Xf<sub>y</sub> <sub>m0</sub>
Answer» C. X /f<sub>y</sub> <sub>m0</sub>
Discussion
4.

What is the value of non dimensional slenderness ratio in the equation of design compressive strength?

A. (f<sub>y</sub> /f<sub>cc</sub>)
B. (f<sub>y</sub> f<sub>cc</sub>)
C. (f<sub>y</sub> /f<sub>cc</sub>)
D. (f<sub>y</sub> f<sub>cc</sub>)
Answer» D. (f<sub>y</sub> f<sub>cc</sub>)
Discussion
5.

Euler buckling stress fcc is given by

A. ( <sup>2</sup>E)/(KL/r)<sup>2</sup>
B. ( <sup>2</sup>E KL/r)<sup>2</sup>
C. ( <sup>2</sup>E)/(KL/r)
D. ( <sup>2</sup>E)/(KLr)<sup>2</sup>
Answer» B. ( <sup>2</sup>E KL/r)<sup>2</sup>
Discussion
6.

The value of in the equation of design compressive strength is given by

A. = 0.5[1- ( -0.2)+ <sup>2</sup>].
B. = 0.5[1- ( -0.2)-+ <sup>2</sup>].
C. = 0.5[1+ ( +0.2)- <sup>2</sup>].
D. = 0.5[1+ ( -0.2)+ <sup>2</sup>].
Answer» E.
Discussion
7.

If imperfection factor = 0.49, then what is the buckling class?

A. a
B. c
C. b
D. g
Answer» C. b
Discussion
8.

What is the value of imperfection factor for buckling class a?

A. 0.34
B. 0.75
C. 0.21
D. 0.5
Answer» D. 0.5
Discussion
9.

The design compressive stress, fcd of column is given by

A. [f<sub>y</sub> / <sub>m0</sub>]/ [ ( <sup>2</sup>- <sup>2</sup>)<sup>2</sup>].
B. [f<sub>y</sub> / <sub>m0</sub>] / [ + ( <sup>2</sup>- <sup>2</sup>)].
C. [f<sub>y</sub> / <sub>m0</sub>]/[ ( <sup>2</sup>- <sup>2</sup>)<sup>0.5</sup>].
D. [f<sub>y</sub> / <sub>m0</sub>] / [ + ( <sup>2</sup>- <sup>2</sup>)<sup>0.5</sup>].
Answer» E.
Discussion
10.

The design compressive strength of member is given by

A. A<sub>e</sub>f<sub>cd</sub>
B. A<sub>e</sub> /f<sub>cd</sub>
C. f<sub>cd</sub>
D. 0.5A<sub>e</sub>f<sub>cd</sub>
Answer» B. A<sub>e</sub> /f<sub>cd</sub>
Discussion