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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Statistical Quality Control knowledge and support exam preparation. Choose a topic below to get started.
1. |
Some cusums can have different sensitivity of the lower cusum than the upper cusum. |
A. | True |
B. | False |
Answer» B. False | |
2. |
Only two-sided cusums are useful all over the industries. |
A. | True |
B. | False |
Answer» C. | |
3. |
The values of Si+ or Si– at the starting are ____ if the FIR feature is not used. |
A. | 1 |
B. | H |
C. | H/2 |
D. | 0 |
Answer» E. | |
4. |
What is the value of lower cusum in the standardized scale cusum chart for process variability? |
A. | \(S_i^+=max\left\{0,v_i-k+S_{i-1}^+\right\}\) |
B. | \(S_i^-=max\left\{0,v_i-k+S_{i-1}^+\right\}\) |
C. | \(S_i^-=max\left\{0,-v_i-k+S_{i-1}^-\right\}\) |
D. | \(S_i^+=max\left\{0,-v_i-k+S_{i-1}^+\right\}\) |
Answer» D. \(S_i^+=max\left\{0,-v_i-k+S_{i-1}^+\right\}\) | |
5. |
The two-sided standardized scale, i.e. standard deviation cusums will have its upper cusum value equal to ___________ |
A. | \(S_i^+=max\left\{0,v_i-k+S_{i-1}^+\right\}\) |
B. | \(S_i^+=max\left\{0,v_i+k-S_{i-1}^+\right\}\) |
C. | \(S_i^+=max\left\{0,v_i-k-S_{i-1}^-\right\}\) |
D. | \(S_i^+=max\left\{0,v_i-k+S_{i-1}^-\right\}\) |
Answer» B. \(S_i^+=max\left\{0,v_i+k-S_{i-1}^+\right\}\) | |
6. |
The standardized variable vi was subjected to vary more with respect to ____________ than process mean. |
A. | Sample mean |
B. | Sample variance |
C. | Process variance |
D. | Process standard deviation |
Answer» D. Process standard deviation | |
7. |
What is the standardized variable value for the cusum charts from Hawkins? |
A. | \(v_i=\frac{\sqrt{|y_i|}-0.822}{0.349}\) |
B. | \(v_i=\frac{\sqrt{|y_i|}-0.822}{0.500}\) |
C. | \(v_i=\frac{3\sqrt{|y_i|}-0.822}{0.349}\) |
D. | \(v_i=\frac{2\sqrt{|y_i|}-0.822}{0.349}\) |
Answer» B. \(v_i=\frac{\sqrt{|y_i|}-0.822}{0.500}\) | |
8. |
What is the meaning of the 50% headstart? |
A. | The value of C0– equal to H/2 |
B. | The value of C0+ equal to H/2 |
C. | Both the values of C0+ and C0– equal to H/2 |
D. | Both the values of C0+ and C0– lesser than H/2 |
Answer» D. Both the values of C0+ and C0– lesser than H/2 | |
9. |
What is the full form of FIR feature in the cusum charts? |
A. | First initial response |
B. | Fast initial response |
C. | First initiation response |
D. | Free initial response |
Answer» C. First initiation response | |
10. |
To apply Shewhart-cusum combined procedure, the Shewhart control limits should be applied almost _________ standard deviation from the center. |
A. | 2 |
B. | 1 |
C. | 1.5 |
D. | 3.5 |
Answer» E. | |
11. |
Combined Cusum-Shewhart procedure is applied _____________ |
A. | On-line control |
B. | On-line measure |
C. | Off-line control |
D. | On-line measure |
Answer» B. On-line measure | |
12. |
Which of these is an advantage of the standardized cusum chart? |
A. | There can be same means chosen for different processes |
B. | There can be same standard deviations chosen for different processes |
C. | The choices of k and h parameters are not scale dependent |
D. | No variability at all |
Answer» D. No variability at all | |
13. |
What is the value of the one-sided lower cusum of the standardized cusum chart? |
A. | \(C_i^+=max\left\{0,-y_i-k+C_{i-1}^+\right\}\) |
B. | \(C_i^-=max\left\{0,y_i-k+C_{i-1}^-\right\}\) |
C. | \(C_i^-=max\left\{0,-y_i-k+C_{i-1}^-\right\}\) |
D. | \(C_i^+=max\left\{0,-y_i-k+C_{i-1}^-\right\}\) |
Answer» D. \(C_i^+=max\left\{0,-y_i-k+C_{i-1}^-\right\}\) | |
14. |
What is the value of one sided upper cusum of the standardized cusum chart? |
A. | \(C_i^+=max\left\{0,y_i-k+C_{i-1}^+\right\}\) |
B. | \(C_i^+=max\left\{0,y_i+k+C_{i-1}^+\right\}\) |
C. | \(C_i^+=min\left\{0,y_i+k+C_{i-1}^+\right\}\) |
D. | \(C_i^+=min\left\{0,y_i-k+C_{i-1}^+\right\}\) |
Answer» B. \(C_i^+=max\left\{0,y_i+k+C_{i-1}^+\right\}\) | |
15. |
What is the standardized value used for xi in the standardized cusum chart? |
A. | \(y_i=\frac{x_i-μ_0}{3σ}\) |
B. | \(y_i=\frac{x_i-μ_0}{σ}\) |
C. | \(y_i=\frac{x_i-μ_0}{2σ}\) |
D. | \(y_i=\frac{x_i-μ_0}{6σ}\) |
Answer» C. \(y_i=\frac{x_i-μ_0}{2σ}\) | |