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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Signals Systems knowledge and support exam preparation. Choose a topic below to get started.
1. |
The Laplace transform of the signal \(\int_0^t e^{-3t}\) cos2t dt is _____________ |
A. | \(\frac{-(s+3)}{s[(s+3)^2+4]}\) |
B. | \(\frac{(s+3)}{s[(s+3)^2+4]}\) |
C. | \(\frac{s(s+3)}{(s+3)^2+4}\) |
D. | \(\frac{-s(s+3)}{(s+3)^2+4}\) |
Answer» C. \(\frac{s(s+3)}{(s+3)^2+4}\) | |
2. |
The Laplace transform of the signal u(t-1) * e-2t u(t-1) is ___________ |
A. | \(\frac{e^{-2(s+1)}}{2s+1}\) |
B. | \(\frac{e^{-2(s+1)}}{s+1}\) |
C. | \(\frac{e^{-(s+2)}}{s+2}\) |
D. | \(\frac{e^{-2(s+1)}}{s+2}\) |
Answer» E. | |
3. |
The Laplace transform of the signal t3 u(t) is _____________ |
A. | \(\frac{3}{s^4}\) |
B. | \(\frac{-3}{s^4}\) |
C. | \(\frac{6}{s^4}\) |
D. | \(\frac{-6}{s^4}\) |
Answer» D. \(\frac{-6}{s^4}\) | |
4. |
The Laplace transform of the signal t u(t) * cos 2πt u(t) is _____________ |
A. | \(\frac{1}{s(s^2+4π^2)}\) |
B. | \(\frac{2π}{s^2 (s^2+4π^2)}\) |
C. | \(\frac{1}{s^2 (s^2+4π^2)}\) |
D. | \(\frac{s^3}{(s^2+4π^2)}\) |
Answer» B. \(\frac{2π}{s^2 (s^2+4π^2)}\) | |
5. |
The Laplace transform of the signal \(\frac{d}{dx}\)(te-t u(t)) is ______________ |
A. | \(\frac{1}{s(s+1)^2}\) |
B. | \(\frac{s}{(s+1)^2}\) |
C. | \(\frac{e^{-s}}{s+1}\) |
D. | \(\frac{e^{-s}}{(s+1)^2}\) |
Answer» C. \(\frac{e^{-s}}{s+1}\) | |
6. |
The Laplace transform of the signal u(t) – u(t-2) is ______________ |
A. | \(\frac{e^{-2s}-1}{s}\) |
B. | \(\frac{-e^{-2s}+1}{s}\) |
C. | \(\frac{2}{s}\) |
D. | \(\frac{-2}{s}\) |
Answer» C. \(\frac{2}{s}\) | |
7. |
The Laplace transform of the signal sin 5t is _____________ |
A. | \(\frac{5}{s^2+5}\) |
B. | \(\frac{s}{s^2+5}\) |
C. | \(\frac{5}{s^2+25}\) |
D. | \(\frac{s}{s^2+25}\) |
Answer» D. \(\frac{s}{s^2+25}\) | |
8. |
The Laplace transform of the signal e2tu(-t+2) is ___________ |
A. | \(\frac{e^{2(s-2)-1}}{s-2}\) |
B. | \(\frac{e^{-2s}}{s+2}\) |
C. | \(\frac{1-e^{-2(s-2)}}{s-2}\) |
D. | \(\frac{e^{-2s}}{s-2}\) |
Answer» D. \(\frac{e^{-2s}}{s-2}\) | |
9. |
The Laplace transform of the signal e-2tu(t+1) is ___________ |
A. | \(\frac{1}{s+2}\) |
B. | \(\frac{e^{-s}}{s+2}\) |
C. | \(\frac{e^{-(s+2)}}{s+2}\) |
D. | \(\frac{-e^{-s}}{s+2}\) |
Answer» B. \(\frac{e^{-s}}{s+2}\) | |
10. |
The Laplace transform of the signal u (t+2) is _________ |
A. | \(\frac{1}{s}\) |
B. | \(\frac{-1}{s}\) |
C. | \(\frac{e^{-2s}}{s}\) |
D. | \(\frac{-e^{-2s}}{s}\) |
Answer» B. \(\frac{-1}{s}\) | |
11. |
The Laplace transform of signal u(t-2) is ___________ |
A. | \(\frac{-e^{-2s}}{s}\) |
B. | \(\frac{e^{-2s}}{s}\) |
C. | \(\frac{e^{-2s}}{1+s}\) |
D. | Zero |
Answer» C. \(\frac{e^{-2s}}{1+s}\) | |
12. |
The inverse Laplace transform of F(s) = \(\frac{2}{s^2+3s+2}\) is ______________ |
A. | -2e-2t + 2e-t |
B. | 2e-2t + 2e-t |
C. | -2e-2t – 2e-t |
D. | 2e-t + e-2t |
Answer» B. 2e-2t + 2e-t | |
13. |
The inverse Laplace transform of F(s) = \(\frac{2}{s+c} e^{-bs}\) is _________________ |
A. | 2 e-k (t-b)b) 2 e-k (t-b) u (t-b)c) e-k (t-b) u (t-b)d) 2 u (t- |
B. | 2 e-k (t-b) u (t-b) |
C. | e-k (t-b) u (t-b) |
D. | 2 u (t-b) |
Answer» C. e-k (t-b) u (t-b) | |
14. |
Given f (t) = t2e-2x cos (3t). The value of L {f(t)} is __________________ |
A. | \(\frac{2(s+2)(s^2+4s-23)}{(s^2+4s+13)^3}\) |
B. | \(\frac{2(s-2)(s^2-4s-23)}{(s^2+4s+13)^3}\) |
C. | \(\frac{2(s+2)(s^2+4s+23)}{(s^2+4s+13)^3}\) |
D. | \(\frac{2(s-2)(s^2+4s-23)}{(s^2+4s-13)^3}\) |
Answer» B. \(\frac{2(s-2)(s^2-4s-23)}{(s^2+4s+13)^3}\) | |
15. |
The Laplace transform of f(t) = (e-2t – 1)2 is ________________ |
A. | \(\frac{2}{s+2} + \frac{1}{s}\) |
B. | \(\frac{1}{s+4}\) |
C. | \(\frac{1}{s+4} – \frac{2}{s+2} + \frac{1}{s}\) |
D. | –\(\frac{2}{s+2} + \frac{1}{s}\) |
Answer» D. –\(\frac{2}{s+2} + \frac{1}{s}\) | |