Explore topic-wise MCQs in Refrigeration.

This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Refrigeration knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the COP of an ideal vapour absorption refrigeration system using the following data.Qg = 1880Qe = 1045

A. 0.47
B. 0.65
C. 0.69
D. 0.55
Answer» E.
2.

In case the heat is discharged at different temperatures in condenser and absorber then the formula for COP would be?Ta = Temperature at which heat is discharged in the absorberTe and Tc are the temperature limits for Carnot refrigeratorTg and Tc are the temperature limits for Carnot engine

A. COP = \(\frac{T_e}{T_c – T_e} × \frac{T_g-T_c}{T_g}\)
B. COP = \(\frac{T_e}{T_c – T_e} × \frac{T_g-T_c}{T_g} × T_a\)
C. COP = \(\frac{T_e}{T_c – T_e} × \frac{T_g-T_c}{T_g} ± T_a\)
D. COP = \(\frac{T_e}{T_c – T_e} × \frac{T_g-T_c}{T_g}\)
Answer» E.
3.

The expression \(\frac{T_e}{T_c – T_e}\) in the formula for COP i.e. \(\frac{T_e}{T_c – T_e} × \frac{T_g-T_c}{T_g}\) refers to __________Te and Tc are the temperature limits for Carnot refrigeratorTg and Tc are the temperature limits for Carnot engine

A. COP of Carnot engine
B. COP of Carnot refrigerator
C. COP of Carnot pump
D. COP of Bell-Coleman cycle
Answer» C. COP of Carnot pump
4.

Find the COP of a vapour absorption refrigeration system using the following data.Te = 268Tg = 393.2Tc = 303

A. 1.53
B. 1.76
C. 1.66
D. 1.98
Answer» C. 1.66
5.

Find the COP of a vapour absorption refrigeration system using the following data.Qg = 6600Qe = 2100

A. 0.45
B. 0.65
C. 0.31
D. 0.35
Answer» D. 0.35
6.

An ideal vapour absorption refrigeration system may be regarded as a combination of _________

A. Carnot engine and Carnot pump
B. Carnot refrigerant and Carnot pump
C. Carnot engine and Carnot refrigerant
D. Carnot engine alone
Answer» D. Carnot engine alone
7.

What is the formula for COP of an ideal vapour absorption refrigeration system?Qg = the heat given to the refrigerant in the generatorQe= the heat absorbed by the refrigerant in the evaporator

A. \(\frac{Q_e}{Q_g}\)
B. \(\frac{Q_g}{Q_e}\)
C. Qg × Qe
D. Qg – Qe
Answer» B. \(\frac{Q_g}{Q_e}\)