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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Refrigeration knowledge and support exam preparation. Choose a topic below to get started.
1. |
If a condenser and evaporator temperatures are 250 K and 100 K respectively, then reverse Carnot C.O.P is _________ |
A. | 5.5 |
B. | 1.5 |
C. | 2.5 |
D. | 3.0 |
Answer» C. 2.5 | |
2. |
The C.O.P for reverse Carnot refrigerator is 2. The ratio of lowest temperature to highest temperature will be _____ |
A. | twice |
B. | half |
C. | four times |
D. | three times |
Answer» E. | |
3. |
If a condenser and evaporator temperatures are 312 K and 273 K respectively, then reverse Carnot C.O.P is _________ |
A. | ( frac{1}{5} ) |
B. | ( frac{1}{6} ) |
C. | ( frac{1}{7} ) |
D. | ( frac{1}{8} ) |
Answer» D. ( frac{1}{8} ) | |
4. |
The C.O.P. of reverse Carnot cycle is most strongly dependent on which of the following? |
A. | Evaporator temperature |
B. | Condenser temperature |
C. | Specific heat |
D. | Refrigerant |
Answer» B. Condenser temperature | |
5. |
If a condenser and evaporator temperatures are 120 K and 60 K respectively, then reverse Carnot C.O.P is _________ |
A. | 0.5 |
B. | 1 |
C. | 3 |
D. | 2 |
Answer» C. 3 | |
6. |
The reverse Carnot cycle C.O.P. can be expressed as _________ (Where t1 is the lower temperature and t2 is the higher temperature). |
A. | ( frac{t1-t2}{t2} ) |
B. | ( frac{t2-t1}{t2} ) |
C. | ( frac{t2-t1}{t1-t2} ) |
D. | ( frac{t2-t1}{t1} ) |
Answer» E. | |
7. |
In a refrigerating machine, if the lower temperature is fixed, then the C.O.P. of machine can be increased by? |
A. | Increasing the higher temperature |
B. | Decreasing the higher temperature |
C. | Operating the machine at lower speed |
D. | Operating the machine at higher speed |
Answer» C. Operating the machine at lower speed | |
8. |
The Co-efficient of Performance is always __________ |
A. | greater than 1 |
B. | less than 1 |
C. | equal to 1 |
D. | zero |
Answer» B. less than 1 | |
9. |
Which equation represents efficiency in general? |
A. | ( frac{Work ,Done}{Refrigeration ,effect} ) |
B. | ( frac{Heat ,Trasfer}{Work ,Done} ) |
C. | ( frac{Work , Done}{Heat ,Transfer} ) |
D. | ( frac{Refrigeration ,effect}{Work ,Done} ) |
Answer» D. ( frac{Refrigeration ,effect}{Work ,Done} ) | |
10. |
Find the C.O.P. of a refrigeration system if the work input is 30 KJ/kg and refrigeration effect produced is 120 KJ/kg of refrigerant flowing. |
A. | 3.00 |
B. | 4.00 |
C. | 0.75 |
D. | 0.25 |
Answer» C. 0.75 | |
11. |
Find the Relative C.O.P. of a refrigeration system if the work input is 60 KJ/kg and refrigeration effect produced is 130 KJ/kg of refrigerant flowing. Also Theoretical C.O.P. is 3. |
A. | 0.65 |
B. | 0.79 |
C. | 0.72 |
D. | 0.89 |
Answer» D. 0.89 | |
12. |
Find the C.O.P. of a refrigeration system if the work input is 40 KJ/kg and refrigeration effect produced is 130 KJ/kg of refrigerant flowing. |
A. | 3.00 |
B. | 2.25 |
C. | 3.75 |
D. | 3.25 |
Answer» E. | |
13. |
What is the term relative C.O.P. referred in terms of refrigeration? |
A. | ( frac{Actual ,C.O.P.}{Theoretical ,C.O.P.} ) |
B. | ( frac{Theoretical ,C.O.P.}{Actual ,C.O.P.} ) |
C. | ( frac{Actual ,C.O.P.}{Average ,C.O.P.} ) |
D. | ( frac{Average ,C.O.P.}{Theoretical ,C.O.P.} ) |
Answer» B. ( frac{Theoretical ,C.O.P.}{Actual ,C.O.P.} ) | |
14. |
C.O.P. can be expressed by which equation? |
A. | ( frac{Work ,Done}{Refrigeration ,effect} ) |
B. | ( frac{Refrigeration ,effect}{Work ,Done} ) |
C. | ( frac{Work , Done}{Heat ,Transfer} ) |
D. | ( frac{Heat ,Transfer}{Work ,Done} ) |
Answer» C. ( frac{Work , Done}{Heat ,Transfer} ) | |
15. |
What is the term C.O.P. referred in terms of refrigeration? |
A. | Capacity of Performance |
B. | Co-efficient of Plant |
C. | Co-efficient of Performance |
D. | Cooling for Performance |
Answer» D. Cooling for Performance | |