MCQOPTIONS
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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Refrigeration knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If a condenser and evaporator temperatures are 250 K and 100 K respectively, then reverse Carnot C.O.P is _________ |
| A. | 5.5 |
| B. | 1.5 |
| C. | 2.5 |
| D. | 3.0 |
| Answer» C. 2.5 | |
| 2. |
The C.O.P for reverse Carnot refrigerator is 2. The ratio of lowest temperature to highest temperature will be _____ |
| A. | twice |
| B. | half |
| C. | four times |
| D. | three times |
| Answer» E. | |
| 3. |
If a condenser and evaporator temperatures are 312 K and 273 K respectively, then reverse Carnot C.O.P is _________ |
| A. | ( frac{1}{5} ) |
| B. | ( frac{1}{6} ) |
| C. | ( frac{1}{7} ) |
| D. | ( frac{1}{8} ) |
| Answer» D. ( frac{1}{8} ) | |
| 4. |
The C.O.P. of reverse Carnot cycle is most strongly dependent on which of the following? |
| A. | Evaporator temperature |
| B. | Condenser temperature |
| C. | Specific heat |
| D. | Refrigerant |
| Answer» B. Condenser temperature | |
| 5. |
If a condenser and evaporator temperatures are 120 K and 60 K respectively, then reverse Carnot C.O.P is _________ |
| A. | 0.5 |
| B. | 1 |
| C. | 3 |
| D. | 2 |
| Answer» C. 3 | |
| 6. |
The reverse Carnot cycle C.O.P. can be expressed as _________ (Where t1 is the lower temperature and t2 is the higher temperature). |
| A. | ( frac{t1-t2}{t2} ) |
| B. | ( frac{t2-t1}{t2} ) |
| C. | ( frac{t2-t1}{t1-t2} ) |
| D. | ( frac{t2-t1}{t1} ) |
| Answer» E. | |
| 7. |
In a refrigerating machine, if the lower temperature is fixed, then the C.O.P. of machine can be increased by? |
| A. | Increasing the higher temperature |
| B. | Decreasing the higher temperature |
| C. | Operating the machine at lower speed |
| D. | Operating the machine at higher speed |
| Answer» C. Operating the machine at lower speed | |
| 8. |
The Co-efficient of Performance is always __________ |
| A. | greater than 1 |
| B. | less than 1 |
| C. | equal to 1 |
| D. | zero |
| Answer» B. less than 1 | |
| 9. |
Which equation represents efficiency in general? |
| A. | ( frac{Work ,Done}{Refrigeration ,effect} ) |
| B. | ( frac{Heat ,Trasfer}{Work ,Done} ) |
| C. | ( frac{Work , Done}{Heat ,Transfer} ) |
| D. | ( frac{Refrigeration ,effect}{Work ,Done} ) |
| Answer» D. ( frac{Refrigeration ,effect}{Work ,Done} ) | |
| 10. |
Find the C.O.P. of a refrigeration system if the work input is 30 KJ/kg and refrigeration effect produced is 120 KJ/kg of refrigerant flowing. |
| A. | 3.00 |
| B. | 4.00 |
| C. | 0.75 |
| D. | 0.25 |
| Answer» C. 0.75 | |
| 11. |
Find the Relative C.O.P. of a refrigeration system if the work input is 60 KJ/kg and refrigeration effect produced is 130 KJ/kg of refrigerant flowing. Also Theoretical C.O.P. is 3. |
| A. | 0.65 |
| B. | 0.79 |
| C. | 0.72 |
| D. | 0.89 |
| Answer» D. 0.89 | |
| 12. |
Find the C.O.P. of a refrigeration system if the work input is 40 KJ/kg and refrigeration effect produced is 130 KJ/kg of refrigerant flowing. |
| A. | 3.00 |
| B. | 2.25 |
| C. | 3.75 |
| D. | 3.25 |
| Answer» E. | |
| 13. |
What is the term relative C.O.P. referred in terms of refrigeration? |
| A. | ( frac{Actual ,C.O.P.}{Theoretical ,C.O.P.} ) |
| B. | ( frac{Theoretical ,C.O.P.}{Actual ,C.O.P.} ) |
| C. | ( frac{Actual ,C.O.P.}{Average ,C.O.P.} ) |
| D. | ( frac{Average ,C.O.P.}{Theoretical ,C.O.P.} ) |
| Answer» B. ( frac{Theoretical ,C.O.P.}{Actual ,C.O.P.} ) | |
| 14. |
C.O.P. can be expressed by which equation? |
| A. | ( frac{Work ,Done}{Refrigeration ,effect} ) |
| B. | ( frac{Refrigeration ,effect}{Work ,Done} ) |
| C. | ( frac{Work , Done}{Heat ,Transfer} ) |
| D. | ( frac{Heat ,Transfer}{Work ,Done} ) |
| Answer» C. ( frac{Work , Done}{Heat ,Transfer} ) | |
| 15. |
What is the term C.O.P. referred in terms of refrigeration? |
| A. | Capacity of Performance |
| B. | Co-efficient of Plant |
| C. | Co-efficient of Performance |
| D. | Cooling for Performance |
| Answer» D. Cooling for Performance | |