MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 1187 Mcqs, each offering curated multiple-choice questions to sharpen your NEET knowledge and support exam preparation. Choose a topic below to get started.
| 701. |
Copper wire test for halogens is known as |
| A. | Duma's Test |
| B. | Beilstein's Test |
| C. | Liebig's Test |
| D. | Lassigne's Test |
| Answer» C. Liebig's Test | |
| 702. |
In the separation of \[C{{u}^{2+}}\] and \[C{{d}^{2+}}\] in 2nd group qualitative analysis of cations, tetrammine copper (II) sulphate and tetrammine cadmium (II) sulphate react with KCN to form the corresponding cyano complexes. Which one of the following pairs of the complexes and their relative stability enable the separation of \[C{{u}^{2+}}\] and \[C{{d}^{2+?}}\] |
| A. | \[{{K}_{3}}\left[ Cu{{\left( CN \right)}_{4}} \right]\] more stable and \[{{K}_{2}}[Cd{{(CN)}_{4}}]\] less stable |
| B. | \[{{K}_{2}}\left[ Cu{{\left( CN \right)}_{4}} \right]\] less stable and \[{{K}_{2}}[Cd{{(CN)}_{4}}]\] more stable |
| C. | \[{{K}_{2}}\left[ Cu{{\left( CN \right)}_{4}} \right]\] more stable and \[{{K}_{2}}[Cd{{(CN)}_{4}}]\] less stable |
| D. | \[{{K}_{3}}\left[ Cu{{\left( CN \right)}_{4}} \right]\]less stable and \[{{K}_{2}}[Cd{{(CN)}_{4}}]\] more stable |
| Answer» B. \[{{K}_{2}}\left[ Cu{{\left( CN \right)}_{4}} \right]\] less stable and \[{{K}_{2}}[Cd{{(CN)}_{4}}]\] more stable | |
| 703. |
Sodium carbonate cannot be used in place of \[{{(N{{H}_{4}})}_{2}}C{{O}_{3}}\] for the identification of \[C{{a}^{2+}},B{{a}^{2+}}\]and \[S{{r}^{2+}}\] ions (in group V) during mixture analysis because: |
| A. | \[M{{g}^{2+}}\] ions will also be precipitated. |
| B. | Concentration of \[CO_{3}^{2-}\] ions is very low. |
| C. | Sodium ions will react with acid radicals. |
| D. | \[N{{a}^{+}}\] ions will interfere with the detection of \[C{{a}^{2+}},B{{a}^{2+}},S{{r}^{2+}}\] ions. |
| Answer» B. Concentration of \[CO_{3}^{2-}\] ions is very low. | |
| 704. |
A metal chloride dissolves appreciably in cold water. When placed on a platinum wire in Bunsen flame no distinctive colour is noticed, the cation would be |
| A. | \[M{{g}^{2+}}\] |
| B. | \[B{{a}^{2+}}\] |
| C. | \[P{{b}^{2+}}\] |
| D. | \[C{{a}^{2+}}\] |
| Answer» B. \[B{{a}^{2+}}\] | |
| 705. |
A is a lighter phenol and B is an aromatic carboxylic acid. Separation of mixture of A and B can be carried out easily by using a solution of |
| A. | sodium hydroxide |
| B. | sodium sulphate |
| C. | calcium chloride |
| D. | sodium bicarbonate |
| Answer» E. | |
| 706. |
An aqueous solution of a salt X turns blood red on treatment with \[CN{{S}^{-}}\] and blue on treatment with\[{{K}_{4}}[Fe{{\left( CN \right)}_{6}}]\]. X also gives a positive chromyl chloride test. The salt X is: |
| A. | \[CuC{{l}_{2}}\] |
| B. | \[FeC{{l}_{3}}\] |
| C. | \[Cu{{(N{{O}_{3}})}_{2}}\] |
| D. | \[Fe{{(N{{O}_{3}})}_{3}}\] |
| Answer» C. \[Cu{{(N{{O}_{3}})}_{2}}\] | |
| 707. |
A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the solution, a white precipitate is obtained which does not dissolve in dil. \[HN{{O}_{3}}\]. The anion could be |
| A. | \[CO_{3}^{2-}\] |
| B. | \[C{{l}^{-}}\] |
| C. | \[SO_{4}^{2-}\] |
| D. | \[{{S}^{2-}}\] |
| Answer» C. \[SO_{4}^{2-}\] | |
| 708. |
In the presence of a small amount of phosphorous, aliphatic carboxylic acids react with chlorine or bromine to yield a compound in which \[\alpha \]-hydrogen has been replaced by halogen. This reaction is known as: |
| A. | Wolff- Kishner reaction |
| B. | Rosenmund reaction |
| C. | Etard reaction |
| D. | Hell - Volhard - Zelinsky reaction |
| Answer» E. | |
| 709. |
Among the following the order of reactivity towards nucleophilic addition is |
| A. | \[C{{H}_{3}}CHO>C{{H}_{3}}COC{{H}_{3}}>HCHO\] |
| B. | \[HCHO>C{{H}_{3}}CHO>C{{H}_{3}}COC{{H}_{3}}\] |
| C. | \[C{{H}_{3}}CHO>HCHO>C{{H}_{3}}COC{{H}_{3}}\] |
| D. | \[C{{H}_{3}}COC{{H}_{3}}>C{{H}_{3}}CHO>HCHO\] |
| Answer» C. \[C{{H}_{3}}CHO>HCHO>C{{H}_{3}}COC{{H}_{3}}\] | |
| 710. |
Which of the following reagent(s) used for the conversion? |
| A. | \[glycol/LiAl{{H}_{4}}/{{H}_{3}}{{O}^{+}}\] |
| B. | \[glycol/NaH/{{H}_{3}}{{O}^{+}}\] |
| C. | \[LiAl{{H}_{4}}\] |
| D. | \[NaB{{H}_{4}}\] |
| Answer» B. \[glycol/NaH/{{H}_{3}}{{O}^{+}}\] | |
| 711. |
Tollen's reagent and Fehling solutions are used to distinguish between |
| A. | acids and alcohols |
| B. | alkanes and alcohols |
| C. | ketones and aldehydes |
| D. | n-alkanes and branched alkanes |
| Answer» D. n-alkanes and branched alkanes | |
| 712. |
Which of following can be used as a catalyst in the above reaction? |
| A. | \[C{{l}^{-}}\] |
| B. | \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-{{O}^{-}}\] |
| C. | \[Et{{O}^{-}}\] |
| D. | \[HSO_{4}^{-}\] |
| Answer» D. \[HSO_{4}^{-}\] | |
| 713. |
A substance \[{{C}_{4}}{{H}_{10}}O\] yields on oxidation a compound, \[{{C}_{4}}{{H}_{8}}O\] which gives an oxime and a positive iodoform test. The original substance on treatment with cone. \[{{H}_{2}}S{{O}_{4}}\] gives \[{{C}_{2}}{{H}_{8}}\] The structure of the compound is |
| A. | \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH\] |
| B. | \[C{{H}_{3}}CHOHC{{H}_{2}}C{{H}_{3}}\] |
| C. | \[{{\left( C{{H}_{3}} \right)}_{3}}COH\] |
| D. | \[C{{H}_{3}}C{{H}_{2}}-O-C{{H}_{2}}C{{H}_{3}}\] |
| Answer» C. \[{{\left( C{{H}_{3}} \right)}_{3}}COH\] | |
| 714. |
Predict the product 'B' in the sequence of reactions \[HC\equiv CH\xrightarrow[(percent) HgS{{O}_{4}}]{30(percent){{H}_{2}}S{{O}_{4}}}A\xrightarrow[{}]{NaOH}B\] |
| A. | \[C{{H}_{3}}COONa\] |
| B. | \[C{{H}_{3}}COOH\] |
| C. | \[C{{H}_{3}}CHO\] |
| D. | \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}-CHO\] |
| Answer» E. | |
| 715. |
Which of the following reaction can produce \[R-CO-Ar?\] |
| A. | \[ArCOCl+H-Ar\xrightarrow{AlC{{l}_{3}}}\] |
| B. | \[RCOCl+ArMgX\xrightarrow{{}}\] |
| C. | \[ArCOCl+RMgX\xrightarrow{\text{ }}\] |
| D. | \[RCOCl+H-Ar\xrightarrow{Alc{{l}_{3}}}\] |
| Answer» B. \[RCOCl+ArMgX\xrightarrow{{}}\] | |
| 716. |
Consider the following transformations: \[C{{H}_{3}}COOH\xrightarrow{CaC{{O}_{3}}}A\xrightarrow{heat}B\xrightarrow[NaOH]{{{I}_{2}}}C\] The molecular formula of C is |
| A. | \[C{{H}_{3}}-\underset{I}{\overset{OH}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}\] |
| B. | \[IC{{H}_{2}}-COC{{H}_{3}}\] |
| C. | \[CH{{I}_{3}}\] |
| D. | \[C{{H}_{3}}I\] |
| Answer» D. \[C{{H}_{3}}I\] | |
| 717. |
In Cannizzaro reaction given below \[2PhCHO\xrightarrow{:O{{H}^{-}}}PhC{{H}_{2}}OH+PhC\overset{..}{\mathop{O}}\,_{2}^{-}\] the slowest step is: |
| A. | the transfer of proton to the carbonyl group |
| B. | the abstraction of proton from the carboxylic group |
| C. | the deprotonation of \[PhC{{H}_{2}}OH\] |
| D. | the attack of: \[\overline{O}H\] at the carboxyl group |
| Answer» B. the abstraction of proton from the carboxylic group | |
| 718. |
\[{{(C{{H}_{3}})}_{2}}CO\xrightarrow[(HCl)]{NaCN}A\xrightarrow[\Delta ]{{{H}_{3}}{{O}^{+}}}B\] In the above sequence of reactions A and B are |
| A. | \[{{(C{{H}_{3}})}_{2}}C(OH)CN,{{(C{{H}_{3}})}_{2}}C(OH)COOH\] |
| B. | \[{{(C{{H}_{3}})}_{2}}C(OH)CN,{{(C{{H}_{3}})}_{2}}C{{(OH)}_{2}}\] |
| C. | \[{{(C{{H}_{3}})}_{2}}C(OH)CN,{{(C{{H}_{3}})}_{2}}CHCOOH\] |
| D. | \[{{(C{{H}_{3}})}_{2}}C(OH)CN,{{(C{{H}_{3}})}_{2}}C=O\] |
| Answer» B. \[{{(C{{H}_{3}})}_{2}}C(OH)CN,{{(C{{H}_{3}})}_{2}}C{{(OH)}_{2}}\] | |
| 719. |
What is the product of the following reaction? |
| A. | 2 - methyl -1 - pentene |
| B. | 4 - methyl -1 - pentene |
| C. | 2 - methyl - 2- propyloxirane |
| D. | 1 - pentene |
| Answer» B. 4 - methyl -1 - pentene | |
| 720. |
Which one of the following orders of acid strength is correct? |
| A. | \[RCOOH>HOH>ROH>HC\equiv CH\] |
| B. | \[RCOOH>HOH>HC\equiv CH>ROH\] |
| C. | \[RCOOH>HC\equiv CH>HOH>ROH\] |
| D. | \[RCOOH>ROH>HOH>HC\equiv CH\] |
| Answer» B. \[RCOOH>HOH>HC\equiv CH>ROH\] | |
| 721. |
Carboxylic acid group does not give the usual addition and elimination reactions of aldehydes and ketones because |
| A. | \[O-H\] bond is more polar than group |
| B. | carboxylate ion gets ionized |
| C. | carboxylate ion gets stabilised by resonance |
| D. | it exists as \[-COOH\] and there is no carbonyl group |
| Answer» D. it exists as \[-COOH\] and there is no carbonyl group | |
| 722. |
The correct product of the following sequence of reactions \[{{(C{{H}_{3}})}_{2}}CHCOOH\text{ }\xrightarrow[(ii)\,{{H}_{2}}O]{(i)\,LiAl{{H}_{4}}}\,\,\,\xrightarrow{PB{{r}_{3}}}\] \[\xrightarrow[DMSO]{KCN}\,\,\,\,\xrightarrow[\Delta ]{{{H}_{2}}{{O}^{+}},\,{{H}^{+}}}\] |
| A. | \[{{\left( C{{H}_{3}} \right)}_{2}}CHCHBr.COOH\] |
| B. | \[{{(C{{H}_{3}})}_{2}}CHC{{H}_{2}}COOH\] |
| C. | \[{{\left( C{{H}_{3}} \right)}_{2}}CHC{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\] |
| D. | \[{{\left( C{{H}_{3}} \right)}_{2}}C=CHCOOH\] |
| Answer» C. \[{{\left( C{{H}_{3}} \right)}_{2}}CHC{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\] | |
| 723. |
Hydrolsis of an ester gives a carboxylic acid which on Kolbe's electrolysis yields ethane. The ester is |
| A. | ethyl methanoate |
| B. | methyl ethanoate |
| C. | methyl methanoate |
| D. | methyl propanoate |
| Answer» C. methyl methanoate | |
| 724. |
An ester is boiled with KOH. The product is cooled and acidified with concentrated\[HCl\]. A white crystalline acid separates. The ester is |
| A. | methyl acetate |
| B. | ethyl acetate |
| C. | ethyl formate |
| D. | ethyl benzoate |
| Answer» E. | |
| 725. |
Among the given compounds, the most susceptible to nucleophilic attack at the carbonyl group is |
| A. | \[MeCOCl\] |
| B. | \[MeCHO\] |
| C. | \[MeCOOMe\] |
| D. | \[MeCOOCOMe\] |
| Answer» B. \[MeCHO\] | |
| 726. |
Which of the following orders of relative strengths of acids is correct? |
| A. | \[FC{{H}_{2}}COOH>ClC{{H}_{2}}COOH>BrC{{H}_{2}}COOH\] |
| B. | \[ClC{{H}_{2}}COOH>BrC{{H}_{2}}COOH>FC{{H}_{2}}COOH\] |
| C. | \[BrC{{H}_{2}}COOH>ClC{{H}_{2}}COOH>FC{{H}_{2}}COOH\] |
| D. | \[ClC{{H}_{2}}C{{O}_{2}}H>FC{{H}_{2}}COOH>BrC{{H}_{2}}COOH\] |
| Answer» B. \[ClC{{H}_{2}}COOH>BrC{{H}_{2}}COOH>FC{{H}_{2}}COOH\] | |
| 727. |
What is X in the following conversion? |
| A. | \[{{K}_{2}}C{{r}_{2}}{{O}_{7}},{{H}_{2}}S{{O}_{4}}/{{H}_{2}}O\] |
| B. | \[HI{{O}_{4}}\] |
| C. | \[PCC/C{{H}_{2}}C{{l}_{2}}\] |
| D. | \[Os{{O}_{4}},{{\left( C{{H}_{3}} \right)}_{3}}C.COOH,{{\left( C{{H}_{3}} \right)}_{3}}COH,O{{H}^{-}}\] |
| Answer» D. \[Os{{O}_{4}},{{\left( C{{H}_{3}} \right)}_{3}}C.COOH,{{\left( C{{H}_{3}} \right)}_{3}}COH,O{{H}^{-}}\] | |
| 728. |
Which of the following acids has the smallest dissociation constant? |
| A. | \[C{{H}_{3}}CH\left( F \right)COOH\] |
| B. | \[FC{{H}_{2}}C{{H}_{2}}COOH\] |
| C. | \[BrC{{H}_{2}}C{{H}_{2}}COOH\] |
| D. | \[C{{H}_{3}}CH(Br)COOH\] |
| Answer» D. \[C{{H}_{3}}CH(Br)COOH\] | |
| 729. |
Carboxylic acids are more acidic than phenol and alcohol because of |
| A. | intermolecular hydrogen bonding |
| B. | formation of dimers |
| C. | highly acidic hydrogen |
| D. | resonance stabilization of their conjugate base |
| Answer» E. | |
| 730. |
Identify the correct order of boiling points of the following compounds:\[\underset{1}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,\] \[\underset{2}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO}}\,\]\[\underset{3}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COOH}}\,\] |
| A. | 1>2>3 |
| B. | 3>1>2 |
| C. | 1>3>2 |
| D. | 3>2>1 |
| Answer» C. 1>3>2 | |
| 731. |
A colourless liquid, at room temperature, reacts with soda-lime to form sodium salt of a carboxylic acid and ammonia gas. The liquid is |
| A. | propanoic acid |
| B. | formamide |
| C. | propanamide |
| D. | methyl enthanoate |
| Answer» C. propanamide | |
| 732. |
In the mechanism of Hoffinann reaction, which intermediate rearranges to alkyl isocyanate? |
| A. | Bromamide |
| B. | Nitrene |
| C. | Nitroso |
| D. | Amide |
| Answer» C. Nitroso | |
| 733. |
The order of decreasing ease of reaction with ammonia is |
| A. | anhydrides, esters, ethers |
| B. | anhydrides, ethers, esters |
| C. | ethers, anhydrides, esters |
| D. | esters, ethers, anhydrides |
| Answer» B. anhydrides, ethers, esters | |
| 734. |
\[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow[\operatorname{Red}\,P]{B{{r}_{2}}}X\xrightarrow{N{{H}_{3}}(alc.)}Y\] Y in the above reactions is |
| A. | lactic acid |
| B. | ethyiamine |
| C. | propylamine |
| D. | alanine |
| Answer» E. | |
| 735. |
Propanal on reaction with dilute \[NaOH\] forms |
| A. | \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}CHO\] |
| B. | \[C{{H}_{3}}C{{H}_{2}}CH(OH)C{{H}_{2}}C{{H}_{2}}CHO\] |
| C. | \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH(OH)C{{H}_{2}}CHO\] |
| D. | \[C{{H}_{3}}C{{H}_{2}}CH(OH)CH{{(CH)}_{3}}CHO\] |
| Answer» E. | |
| 736. |
If 3-hexanone is reacted with \[NaB{{H}_{4}}\] followed by hydrolysis with\[{{D}_{2}}O\], the product will be |
| A. | \[C{{H}_{3}}C{{H}_{2}}CH(OH)C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\] |
| B. | \[C{{H}_{3}}C{{H}_{2}}CD\left( OH \right)C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\] |
| C. | \[C{{H}_{3}}C{{H}_{2}}CH\left( OD \right)C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\] |
| D. | \[C{{H}_{3}}C{{H}_{2}}CD\left( OD \right)C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\] |
| Answer» D. \[C{{H}_{3}}C{{H}_{2}}CD\left( OD \right)C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\] | |
| 737. |
Oxidation of acetaldehyde with selenium dioxide produces |
| A. | ethanoicacid |
| B. | methanoic acid |
| C. | glyoxal |
| D. | oxalic acid |
| Answer» D. oxalic acid | |
| 738. |
1-Phenylethanol can be prepared by reaction of benzaldehyde with |
| A. | methyl bromide |
| B. | ethyl iodide and magnesium |
| C. | methyl bromide and aluminium bromide |
| D. | methyl iodide and magnesium |
| Answer» E. | |
| 739. |
Correct order of reactivity of following compounds towards Grignard reagent? |
| A. | I>II>III |
| B. | II>I>III |
| C. | II>III>I |
| D. | I>III>II |
| Answer» C. II>III>I | |
| 740. |
Arrange the following carbonyl compounds in decreasing order of their reactivity in nucleophilic addition reaction. |
| A. | (ii)>(iii)>(i)>(iv) |
| B. | (ii)>(i)>(iv)>(iii) |
| C. | (iii)>(ii)>(i)>(iv) |
| D. | (iii)>(i)>(iv)>(ii) |
| Answer» C. (iii)>(ii)>(i)>(iv) | |
| 741. |
The correct product of the following reactions |
| A. | 2, 2-dimethyl propane diol |
| B. | 2-methyl-1-propanol |
| C. | 2, 2-dimethyl propanedioic acid |
| D. | 2-methyl propanoic acid |
| Answer» B. 2-methyl-1-propanol | |
| 742. |
Identify Z in the following reaction sequence. \[C{{H}_{3}}CHO\xrightarrow[Dil.{{H}_{2}}S{{O}_{4}}]{MnO_{4}^{-}}X\xrightarrow{SOC{{l}_{2}}}Y\xrightarrow[\Delta ]{C{{H}_{3}}COONa}Z\] |
| A. | \[C{{H}_{3}}COC{{H}_{2}}COONa\] |
| B. | \[{{(C{{H}_{3}}CO)}_{2}}O\] |
| C. | \[C{{H}_{3}}CO-O-COC{{H}_{2}}Cl\] |
| D. | \[C{{H}_{3}}CO-OCOCHC{{l}_{2}}\] |
| Answer» C. \[C{{H}_{3}}CO-O-COC{{H}_{2}}Cl\] | |
| 743. |
Identify the missing reagent in the reaction given below |
| A. | Diethyl carbonate \[{{\left( EtO \right)}_{2}}C=O\] |
| B. | Ethyl acetate \[C{{H}_{3}}COOEt\] |
| C. | Ethyl formate \[HCOOEt\] |
| D. | Diethyl oxalate \[Et.OOC.COOEt\] |
| Answer» B. Ethyl acetate \[C{{H}_{3}}COOEt\] | |
| 744. |
An organic compound 'A' has the molecular formula \[{{C}_{3}}{{H}_{6}}O\]. It undergoes iodoform test. When staturated with \[HCl\] it gives 'B' of molecula formula \[{{C}_{9}}{{H}_{14}}O\]. 'A' and 'B' respectively are |
| A. | Propanal and mesitylene |
| B. | Propanone and mesityl oxide |
| C. | Propanone and 2,6-dimethyl-2,5-heptadien- 4-one |
| D. | Propanone and mesitylene oxide |
| Answer» E. | |
| 745. |
The correct set of reagents to carry out the following conversion |
| A. | \[{{B}_{2}}{{H}_{6}}/diglyme,{{H}_{2}}{{O}_{2}}/NaOH,\]\[PCC/C{{H}_{2}}C{{l}_{2}}\] |
| B. | \[B{{r}_{2}},NaN{{H}_{2}},HgS{{O}_{4}}/{{H}_{2}}S{{O}_{4}}\] |
| C. | \[{{H}_{2}}O/{{H}_{2}}S{{O}_{4}},Cr{{O}_{3}}/{{H}_{2}}S{{O}_{4}}\] |
| D. | None of the above |
| Answer» B. \[B{{r}_{2}},NaN{{H}_{2}},HgS{{O}_{4}}/{{H}_{2}}S{{O}_{4}}\] | |
| 746. |
Compound 'A' (molecular formula \[{{C}_{3}}{{H}_{8}}O\]) is treated with acidified potassium dichromate to form a product 'B' (molecular formula \[{{C}_{3}}{{H}_{6}}O\]). 'B' forms a shining silver mirror on warming with ammonical silver nitrate. 'B' when treated with an aqueous solution of \[{{H}_{2}}NCONHN{{H}_{2}}.HCl\] and sodium acetate gives a product 'C'. Identify the structure of 'C'? |
| A. | \[C{{H}_{3}}C{{H}_{2}}CH=NNHCON{{H}_{2}}\] |
| B. | \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=NNHCON{{H}_{2}}\] |
| C. | \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=NCONHN{{H}_{2}}\] |
| D. | \[C{{H}_{3}}C{{H}_{2}}CH=NCONHN{{H}_{2}}\] |
| Answer» B. \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=NNHCON{{H}_{2}}\] | |
| 747. |
The most reactive compound towards formation of cyanohydrin on treatment with KCN followed by acidification is |
| A. | benzaldehyde |
| B. | p-nitrobenzaldehyde |
| C. | phenylacetaldehyde |
| D. | p-hydroxybenzaldehyde |
| Answer» C. phenylacetaldehyde | |
| 748. |
Formaldehyde can be distinguished from acetaldehyde by the use of: |
| A. | Schiffs reagent |
| B. | Tollen's reagent |
| C. | \[{{I}_{2}}\]/Alkali |
| D. | Fehling's solution |
| Answer» D. Fehling's solution | |
| 749. |
Tischenko reaction is a modification of: |
| A. | Aldol condensation |
| B. | Claisen condensation |
| C. | Cannizzaro reaction |
| D. | Pinacol-pinacolon reaction |
| Answer» D. Pinacol-pinacolon reaction | |
| 750. |
Which of the following will not give butyl acetate when treated with 1-butanol |
| A. | \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-Cl\left( pyridene \right)\] |
| B. | \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH\left( {{H}_{2}}S{{O}_{4}} \right)\] |
| C. | \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\left( pyridene \right)\] |
| D. | \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H\left( {{H}_{2}}S{{O}_{4}} \right)\] |
| Answer» E. | |