

MCQOPTIONS
Saved Bookmarks
This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Chemistry knowledge and support exam preparation. Choose a topic below to get started.
1. |
How can fuel have good flexibility? |
A. | Should have high calorific value |
B. | Should have high moisture content |
C. | Should be easy to handle and control |
D. | Should have high cost |
Answer» D. Should have high cost | |
2. |
Why does the flame temperatures calculated solely are invariably higher? |
A. | Since the combustion takes place instantly and completely |
B. | Since some heat is lost as latent heat of steam produced |
C. | Since the dissociating gas molecules does not absorb a little heat |
D. | Since the specific heat of gases decreases with temperature. |
Answer» C. Since the dissociating gas molecules does not absorb a little heat | |
3. |
On what factors does the temperature of flame depends? |
A. | Calorific value of gas, total gaseous products formed and pressure |
B. | Calorific value of gas, total gaseous products formed and specific heat |
C. | Calorific value of gas, total gaseous products formed and area |
D. | Calorific value of gas, total gaseous products formed and intensity |
Answer» C. Calorific value of gas, total gaseous products formed and area | |
4. |
Flaming fuels burn with lower calorific intensities then the flameless fuels. |
A. | True |
B. | False |
Answer» B. False | |
5. |
When does a fuel burn with high calorific intensity? |
A. | When solid fuel burns in high local fuel-bed temperature |
B. | When the fuel burns with an appreciable flame |
C. | When the combustion of fuel is not proper |
D. | When the fuel is of large size |
Answer» B. When the fuel burns with an appreciable flame | |
6. |
How can we calculate the calorific value of a fuel at constant pressure? |
A. | QC.V. = QC.P. – (Δn)×R×T |
B. | QC.V. = QC.P. + (Δn)×R×T |
C. | QC.P. = QC.V. – (Δn)×R×T |
D. | QC.V. = QC.P. – (Δn)×R×T×S |
Answer» D. QC.V. = QC.P. – (Δn)×R×T×S | |
7. |
Calculate the net calorific value of the fuel if it’s ultimate analysis comes out to be containing C = 64%, O = 14.56%, H = 10.44%, N = 6.52%, S = 4.48%? |
A. | 8245.452 cal/gm |
B. | 7865.550 cal/gm |
C. | 7693.907 cal/gm |
D. | 8890.654 cal/gm |
Answer» D. 8890.654 cal/gm | |
8. |
A coal sample contains C=75.5%, H=11.25%, O=11.25, N=1%, S=1%. Caluclate gross calorific value? |
A. | 9568 cal/gm |
B. | 10000 cal/gm |
C. | 9799.010 cal/gm |
D. | 9518.893 cal/gm |
Answer» E. | |
9. |
Which of the following factor does not affect the gross calorific value? |
A. | CO2 emissions from the fuel |
B. | Latent heat produced in the fuel |
C. | Size of the fuel |
D. | Moisture content of the fuel |
Answer» D. Moisture content of the fuel | |