Explore topic-wise MCQs in Engineering Chemistry.

This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Chemistry knowledge and support exam preparation. Choose a topic below to get started.

1.

How can fuel have good flexibility?

A. Should have high calorific value
B. Should have high moisture content
C. Should be easy to handle and control
D. Should have high cost
Answer» D. Should have high cost
2.

Why does the flame temperatures calculated solely are invariably higher?

A. Since the combustion takes place instantly and completely
B. Since some heat is lost as latent heat of steam produced
C. Since the dissociating gas molecules does not absorb a little heat
D. Since the specific heat of gases decreases with temperature.
Answer» C. Since the dissociating gas molecules does not absorb a little heat
3.

On what factors does the temperature of flame depends?

A. Calorific value of gas, total gaseous products formed and pressure
B. Calorific value of gas, total gaseous products formed and specific heat
C. Calorific value of gas, total gaseous products formed and area
D. Calorific value of gas, total gaseous products formed and intensity
Answer» C. Calorific value of gas, total gaseous products formed and area
4.

Flaming fuels burn with lower calorific intensities then the flameless fuels.

A. True
B. False
Answer» B. False
5.

When does a fuel burn with high calorific intensity?

A. When solid fuel burns in high local fuel-bed temperature
B. When the fuel burns with an appreciable flame
C. When the combustion of fuel is not proper
D. When the fuel is of large size
Answer» B. When the fuel burns with an appreciable flame
6.

How can we calculate the calorific value of a fuel at constant pressure?

A. QC.V. = QC.P. – (Δn)×R×T
B. QC.V. = QC.P. + (Δn)×R×T
C. QC.P. = QC.V. – (Δn)×R×T
D. QC.V. = QC.P. – (Δn)×R×T×S
Answer» D. QC.V. = QC.P. – (Δn)×R×T×S
7.

Calculate the net calorific value of the fuel if it’s ultimate analysis comes out to be containing C = 64%, O = 14.56%, H = 10.44%, N = 6.52%, S = 4.48%?

A. 8245.452 cal/gm
B. 7865.550 cal/gm
C. 7693.907 cal/gm
D. 8890.654 cal/gm
Answer» D. 8890.654 cal/gm
8.

A coal sample contains C=75.5%, H=11.25%, O=11.25, N=1%, S=1%. Caluclate gross calorific value?

A. 9568 cal/gm
B. 10000 cal/gm
C. 9799.010 cal/gm
D. 9518.893 cal/gm
Answer» E.
9.

Which of the following factor does not affect the gross calorific value?

A. CO2 emissions from the fuel
B. Latent heat produced in the fuel
C. Size of the fuel
D. Moisture content of the fuel
Answer» D. Moisture content of the fuel