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				This section includes 6 Mcqs, each offering curated multiple-choice questions to sharpen your Technical MCQs knowledge and support exam preparation. Choose a topic below to get started.
| 1. | When do you need to use type-conversions? | 
| A. | The value to be stored is beyond the max limit | 
| B. | The value to be stored is in a form not supported by that data type | 
| C. | To reduce the memory in use, relevant to the value | 
| D. | All of the above | 
| E. | |
| Answer» E. | |
| 2. | In Implicit type conversion, If an operand of type long double is present in the expression, then the corresponding operand will also be converted to? | 
| A. | double | 
| B. | long double | 
| C. | int | 
| D. | float | 
| Answer» C. int | |
| 3. | #include<stdio.h> int main() { double x = 1.2; int sum = (int)x + 1; printf(""sum = %d"", sum); return 0; } 6.In Implicit type conversion, If an operand of long int is present then the other operand will be converted to ? | 
| A. | unsigned int | 
| B. | unsigned long int | 
| C. | float | 
| D. | long int | 
| Answer» E. | |
| 4. | #include<stdio.h> int main() { int x = 10; char y = 'a'; x = x + y; float z = x + 1.0; printf(""x = %d, z = %f"", x, z); return 0; } 5.What will be output for the following code? | 
| A. | sum = 2 | 
| B. | sum = 1 | 
| C. | sum = 0 | 
| D. | sum = 3 | 
| Answer» B. sum = 1 | |
| 5. | double da = 4.5;double db = 4.6;double dc = 4.9;//explicitly defined by userint result = (int)da + (int)db + (int)dc; printf(""result = %d"", result);4.What will be output for the following code? | 
| A. | x = 107, z = 108.00 | 
| B. | x = 107, z = 108.0000 | 
| C. | x = 107, z = 108.000000 | 
| D. | x = 108, z = 108.000000 | 
| Answer» D. x = 108, z = 108.000000 | |
| 6. | The following code is an example of? | 
| A. | Implicit Type Conversion | 
| B. | Explicit Type Conversion | 
| C. | Error | 
| D. | Can not Say | 
| Answer» C. Error | |