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This section includes 24 Mcqs, each offering curated multiple-choice questions to sharpen your Electrical Engineering knowledge and support exam preparation. Choose a topic below to get started.
1. |
Third-order determinants are evaluated by the expansion method or by the cofactor method. |
A. | True |
B. | False |
Answer» B. False | |
2. |
When assigning branch currents, you need not be concerned with the direction you choose. |
A. | True |
B. | False |
Answer» B. False | |
3. |
The mesh current method is based on Kirchhoff's current law. |
A. | True |
B. | False |
Answer» C. | |
4. |
Second-order determinants are evaluated by subtracting the signed cross-products. |
A. | True |
B. | False |
Answer» C. | |
5. |
The mesh method can be applied to circuits with any number of loops. |
A. | True |
B. | False |
Answer» B. False | |
6. |
The first row of a certain determinant has the numbers 3 and 5. The second row has the numbers 7 and 2. The value of this determinant is |
A. | 31 |
B. | -31 |
C. | 39 |
D. | -29 |
Answer» E. | |
7. |
In assigning the direction of branch currents. |
A. | The directions are critical |
B. | The directions are not critical |
C. | They must point into a node |
D. | They must point out of a node |
Answer» C. They must point into a node | |
8. |
The branch current method uses. |
A. | Kirchhoff's voltage and current laws |
B. | Thevenin's theorem and Ohm's law |
C. | Kirchhoff's current law and Ohm's law |
D. | The superposition theorem and Thevenin's theorem |
Answer» B. Thevenin's theorem and Ohm's law | |
9. |
Using the mesh current method, find the branch current, IR1, in the above figure. |
A. | 115 mA |
B. | 12.5 mA |
C. | 12.5 A |
D. | 135 mA |
Answer» B. 12.5 mA | |
10. |
What is the voltage drop across R2? |
A. | 3.5 V |
B. | 4.18 V |
C. | 1.5 V |
D. | 145 mV |
Answer» C. 1.5 V | |
11. |
In assigning the direction of branch currents, |
A. | the directions are critical |
B. | the directions are not critical |
C. | they must point into a node |
D. | they must point out of a node |
Answer» C. they must point into a node | |
12. |
Find I1. 4I1 + 4I2 = 2 6I1 + 7I2 = 4 |
A. | 0.5 A |
B. | 50 mA |
C. | –0.5 A |
D. | –50 mA |
Answer» D. ‚Äì50 mA | |
13. |
The branch current method is based on Kirchhoff's voltage law and Kirchhoff's current law. |
A. | 1 |
B. | |
Answer» B. | |
14. |
The expansion method for evaluating determinants is |
A. | better than any other method |
B. | good for only one determinant |
C. | more flexible than the cofactor method |
D. | good for second- and third-order determinants |
Answer» E. | |
15. |
A loop current is an actual current in a branch. |
A. | 1 |
B. | |
Answer» C. | |
16. |
Generally, the mesh current method results in fewer equations than the node voltage method. |
A. | 1 |
B. | |
C. | 1 |
D. | |
Answer» C. 1 | |
17. |
The first row of a certain determinant has the numbers 10 and 6. The second row has the numbers 3 and 5. The value of this determinant is |
A. | 18 |
B. | 50 |
C. | 32 |
D. | –32 |
Answer» D. ‚Äì32 | |
18. |
Find I2. 4I1 + 4I2 = 2 6I1 + 7I2 = 4 |
A. | 0.041666666666667 |
B. | –1 A |
C. | 100 mA |
D. | –100 mA |
Answer» B. ‚Äì1 A | |
19. |
What is the current through R2? |
A. | 177 mA |
B. | 250 mA |
C. | 500 mA |
D. | 125 mA |
Answer» B. 250 mA | |
20. |
The node voltage method is based on Kirchhoff's voltage law. |
A. | 1 |
B. | |
C. | 1 |
D. | |
Answer» C. 1 | |
21. |
What is the voltage drop across R1? |
A. | 850 mV |
B. | 7.82 V |
C. | 9.18 V |
D. | 918 mV |
Answer» C. 9.18 V | |
22. |
Find branch current IR2. |
A. | 5.4 mA |
B. | –5.4 mA |
C. | 113.0 mA |
D. | 119.6 mA |
Answer» D. 119.6 mA | |
23. |
The branch current method uses |
A. | Kirchhoff's voltage and current laws |
B. | Thevenin's theorem and Ohm's law |
C. | Kirchhoff's current law and Ohm's law |
D. | the superposition theorem and Thevenin's theorem |
Answer» B. Thevenin's theorem and Ohm's law | |
24. |
Find the node voltage VA. |
A. | 6 V |
B. | 12 V |
C. | 4.25 V |
D. | 3 V |
Answer» D. 3 V | |