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MCQOPTIONS
This section includes 14620 Mcqs, each offering curated multiple-choice questions to sharpen your NEET knowledge and support exam preparation. Choose a topic below to get started.
| 13901. |
Read the assertion and reason carefully to mark the correct option out of the options given below: Assertion : Nerve supply to a cut part is essential for initiation and completion of regeneration. Reason : Nerve secretes epidermal growth factor and neurotrophic factor for regeneration. |
| A. | If both the assertion and the reason are true and the reason is a correct explanation of the assertion |
| B. | If both the assertion and reason are true but the reason is not a correct explanation of the assertion |
| C. | If the assertion is true but the reason is false |
| D. | If both the assertion and reason are false |
| Answer» E. | |
| 13902. |
In human beings, growth stops completely at the age of |
| A. | 18 years |
| B. | 22-23 years |
| C. | 25 years |
| D. | 20 years |
| Answer» C. 25 years | |
| 13903. |
Which pair is essential for the growth of the fish in water [BHU 2005] |
| A. | Calcium and Phosphorus |
| B. | Phosphates and carbonates |
| C. | Sulphate and carbonates |
| D. | Nitrates and sulphates |
| Answer» B. Phosphates and carbonates | |
| 13904. |
If in a child of 10 years ages of the intelligence is of 14 years child, the I.Q. of this child would be [CPMT 1986] |
| A. | 140 |
| B. | 100 |
| C. | 160 |
| D. | 110 |
| Answer» B. 100 | |
| 13905. |
The grafting between two identical twins is known as |
| A. | Allograft |
| B. | Autograft |
| C. | Isograft |
| D. | Xenograft |
| Answer» D. Xenograft | |
| 13906. |
Euphenics is [DPMT 1992] |
| A. | Improvement of human race by better environment |
| B. | Improvement of human race by genetic engineering |
| C. | Treatment of communicable diseases |
| D. | Treatment of inheritable diseases |
| Answer» C. Treatment of communicable diseases | |
| 13907. |
Sex influenced characters are due to [MH CET 2004] |
| A. | Y-linked genes |
| B. | X-linked genes |
| C. | Autosomal genes |
| D. | Y-linked gene modification |
| Answer» D. Y-linked gene modification | |
| 13908. |
Haemophilic female marries normal male, the theoretical ratio of their offsprings regarding haemophilia will be [CPMT 2005] |
| A. | All offsprings are haemophilic |
| B. | All girls are haemophilic |
| C. | All sons are haemophilic |
| D. | Half daughters and half sons are haemophilic |
| Answer» D. Half daughters and half sons are haemophilic | |
| 13909. |
One of the following is not true to haemophilia [Kerala CET 2003] |
| A. | Royal disease |
| B. | Bleeder?s disease |
| C. | X-linked disease |
| D. | Y-linked disease |
| Answer» E. | |
| 13910. |
A diseased man marries a normal woman. They get three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this disease is [CBSE PMT 2002; BVP 2002] |
| A. | Autosomal dominant |
| B. | Sex linked recessive |
| C. | Sex limited character |
| D. | Sex linked dominant |
| Answer» E. | |
| 13911. |
Persons who are colour blind cannot distinguish [KCET 2000] |
| A. | Red and green |
| B. | Black and yellow |
| C. | Green and blue |
| D. | Yellow and white |
| Answer» B. Black and yellow | |
| 13912. |
Given below is a pedigree chart of a family with five children. It shows the inheritance of attached earlobes as opposed to the free ones. The squares represent the male individuals and circles the female individuals [AIIMS 2004] Which one of the following conclusions drawn is correct |
| A. | The parents are homozygous recessive |
| B. | The trait is Y-linked |
| C. | The parents are homozygous dominant |
| D. | The parents are heterozygous |
| Answer» E. | |
| 13913. |
Which one is a sex-linked disease [CPMT 1971, 74, 75, 80; DPMT 1985; BHU 1985; AFMC 1996] |
| A. | Tylosis |
| B. | Beri-beri |
| C. | Colour blindness |
| D. | Albinism |
| Answer» D. Albinism | |
| 13914. |
Sex-linked genes of man are [Wardha 2005] |
| A. | Present on X-chromosome |
| B. | Present on autosomes |
| C. | Present on short arm (p) of Y-chromosome |
| D. | Present on long arm (q) of Y-chromosome |
| Answer» B. Present on autosomes | |
| 13915. |
A colour blind son will born when [CPMT 1992, 93] |
| A. | Mother is normal and father normal |
| B. | Mother is colour blind and father normal |
| C. | Mother is normal and father is colour blind |
| D. | All the cases are correct |
| Answer» C. Mother is normal and father is colour blind | |
| 13916. |
Sickle cell anaemia is due to [CBSE PMT 1990] |
| A. | Hormones |
| B. | Viruses |
| C. | Genes |
| D. | Bacteria |
| Answer» C. Genes | |
| 13917. |
Haemophilia A is due to the absence of |
| A. | Antihaemophilic globulin |
| B. | Calcium |
| C. | Plasma thromboplastin |
| D. | X chromosome |
| Answer» B. Calcium | |
| 13918. |
Which of the following human diseases provides an example of sex linked inheritance [AFMC 1985; CPMT 1975, 78, 82, 91; MP PMT 1994] |
| A. | Haemophilia |
| B. | Nightblindness |
| C. | Mongolism |
| D. | Beri-beri |
| Answer» B. Nightblindness | |
| 13919. |
Sex linked characters have one distinct feature [Wardha 2005] |
| A. | Always follows criss-cross inheritance |
| B. | Never follow criss-cross inheritance |
| C. | May be present on Y-chromosome |
| D. | Only present on X-chromosome |
| Answer» B. Never follow criss-cross inheritance | |
| 13920. |
Sex determination in Drosophila melanogaster is based on [MP PMT 1995; AIEEE 2004] |
| A. | X-Y chromosome mechanism |
| B. | Genetic balance between the X-chromosome and autosomes |
| C. | Chromosome - environment interaction |
| D. | Pseudoalleles. |
| Answer» C. Chromosome - environment interaction | |
| 13921. |
The chromosomes responsible for the determination of sex are called [CPMT 1992] |
| A. | Autosomes |
| B. | Allosomes |
| C. | Multiple alleles |
| D. | Heterosis |
| Answer» C. Multiple alleles | |
| 13922. |
If somatic cells of a human male contain single barrbody, the genetic composition of the person would be [JIPMER 1993; MP PMT 2001] |
| A. | XYY |
| B. | XXY |
| C. | XO |
| D. | XXXY |
| Answer» C. XO | |
| 13923. |
Genic balance theory of sex determination was proposed by [MP PMT 1997, 99, 2000; KCET 2004] |
| A. | Morgan |
| B. | Bridges |
| C. | Boveri |
| D. | Wilkins |
| Answer» C. Boveri | |
| 13924. |
For determination of sex, body cells are taken from |
| A. | Buccal epithelium |
| B. | Buccal epithelium and root of hair |
| C. | Gonads |
| D. | Root of hairs |
| Answer» C. Gonads | |
| 13925. |
Drosophila flies with one half of the body male and other half female is referred to as [CBSE PMT 1994] |
| A. | Gynandromorph |
| B. | Hermaphrodite |
| C. | Super female |
| D. | Intersex |
| Answer» B. Hermaphrodite | |
| 13926. |
The average ratio of male to female individuals based on XX and XY type of sex determination, in total world of human population is [CPMT 1979, 81] |
| A. | 3 : 1 |
| B. | 1 : 3 |
| C. | 1 : 4 |
| D. | 1 : 1 |
| Answer» E. | |
| 13927. |
Repressor protein is formed from [MP PMT 1996] |
| A. | Repressor gene |
| B. | Structural gene |
| C. | Operator gene |
| D. | Regulatory gene |
| Answer» E. | |
| 13928. |
Protein synthesis in an animal cell occurs [CBSE PMT 2005] |
| A. | Only on the ribosomes present in cytosol |
| B. | On ribosomes present in cytoplasm as well as in mitochondria |
| C. | Only on ribosomes attached to the nuclear envelope and endoplasmic reticulum |
| D. | On ribosomes present in the nucleolus as well as in cytoplasm |
| Answer» C. Only on ribosomes attached to the nuclear envelope and endoplasmic reticulum | |
| 13929. |
The processes by which mRNA is made by DNA and protein by mRNA are respectively called as [MP PMT 1998] |
| A. | Transcription and translation |
| B. | Translation and transcription |
| C. | Synthesis of mRNA and protein |
| D. | Replication of mRNA and protein |
| Answer» B. Translation and transcription | |
| 13930. |
A polypeptide is produced as dictated by mRNA, the number of bases on the mRNA that code for the polypeptide portion containing N-terminal amino acid and next 13 amino acid is |
| A. | 26 |
| B. | 36 |
| C. | 42 |
| D. | 39 |
| Answer» D. 39 | |
| 13931. |
The genes are responsible for growth and differentiation in an organism through regulation of [MP PMT 1994] |
| A. | Translocation |
| B. | Transformation |
| C. | Transduction and translation |
| D. | Translation and transcription |
| Answer» E. | |
| 13932. |
Which of the following is not correct [DPMT 2003; Haryana PMT 2005] |
| A. | \[\frac{A}{T}=1\] |
| B. | \[\text{A}+\text{T}=\text{G}+\text{C}\] |
| C. | \[A+G=C+T\] |
| D. | None of these |
| Answer» C. \[A+G=C+T\] | |
| 13933. |
The enzyme that breaks \[{{H}_{2}}\]bonds in DNA is [Kerala CET 2002] |
| A. | Helicase |
| B. | Topoisomerase |
| C. | Ligase |
| D. | Polymerase |
| Answer» B. Topoisomerase | |
| 13934. |
DNA multiplication is called [CPMT 1998, 2003; KCET 1999; MP PMT 2003] |
| A. | Replication |
| B. | Transduction |
| C. | Transcription |
| D. | Translation |
| Answer» B. Transduction | |
| 13935. |
If the base sequence in one polynucleotide series of DNA is G-C-A-T-G, what shall be the sequence in the replicated complementary strand [MP PMT 1995] |
| A. | G-C-A-T-G |
| B. | C-G-T-A-C |
| C. | A-T-G-C-G |
| D. | G-C-A-T-C |
| Answer» C. A-T-G-C-G | |
| 13936. |
Transcription of DNA is aided by [MP PMT 1996, 2001, CPMT 2001] |
| A. | RNA polymerase |
| B. | DNA polymerase |
| C. | Exonuclease |
| D. | Recombinase |
| Answer» B. DNA polymerase | |
| 13937. |
DNA consists of two complementary nucleotide chains. If the sequence of nucleotide in one of the chains is AGCTTCGA, then the nucleotide sequence in the other chain shall be [BHU 1994; MP PMT 2000; DPMT 2003] |
| A. | TAGCATAT |
| B. | GATCCTAG |
| C. | TCGAAGCT |
| D. | GCTAAGCT |
| Answer» D. GCTAAGCT | |
| 13938. |
Adenine is 30% then what would be the % of guanine [Haryana PMT 2005] |
| A. | 0.1 |
| B. | 0.2 |
| C. | 0.3 |
| D. | 0.4 |
| Answer» C. 0.3 | |
| 13939. |
In eukaryotes mRNA transcribed is called |
| A. | Heterogenous nuclear RNA |
| B. | tRNA |
| C. | Genetic RNA |
| D. | None of the above |
| Answer» B. tRNA | |
| 13940. |
Which one of the following is called polynucleotide joining enzyme [CBSE PMT 2002] |
| A. | Polymerase I |
| B. | Polymerase II |
| C. | Ligase |
| D. | Ribonuclease |
| Answer» D. Ribonuclease | |
| 13941. |
Which one of the following pair is correctly matched [MP PMT 1993] |
| A. | Frederick Griffith Discovered the phenomenon of transformation |
| B. | Linus Pauling Isolated the DNA for the first time |
| C. | Francis Crick Proposed one gene one polypeptide hypothesis |
| D. | George Beadle Proposed the concept of inborn errors |
| Answer» B. Linus Pauling Isolated the DNA for the first time | |
| 13942. |
Micrococcas nuclease enzyme |
| A. | Cuts the DNA from a specific site |
| B. | Joins the DNA segment |
| C. | Cuts the DNA at the junction between nucleosome |
| D. | Binds the DNA with histone |
| Answer» D. Binds the DNA with histone | |
| 13943. |
DNA polymerase helps in [BHU 1987; CPMT 2003] |
| A. | Joining bits of DNA |
| B. | Splitting or separation of two strands of DNA |
| C. | Renaturation |
| D. | Denaturation |
| Answer» C. Renaturation | |
| 13944. |
The eukaryotic genome differs from the prokaryotic genome because [CBSE PMT 1999] |
| A. | Repetitive sequences are present in eukaryotes |
| B. | Genes in the former case are organized into operons |
| C. | The DNA is complexed with histones in prokaryotes |
| D. | The DNA is circular and single stranded in prokaryotes |
| Answer» E. | |
| 13945. |
What are informosomes |
| A. | They are special types of tRNA |
| B. | They are more stable forms of eukaryotic mRNA |
| C. | They are eukaryotic rRNA |
| D. | Both (b) and (c) |
| Answer» C. They are eukaryotic rRNA | |
| 13946. |
What is Okazaki segment |
| A. | DNA segment concerning recombination |
| B. | Nucleotide chain segment formed during transcription |
| C. | Nucleotide chain formed during DNA duplication |
| D. | Segment of gene responsible for recombination |
| Answer» D. Segment of gene responsible for recombination | |
| 13947. |
Which is the hereditary material in bacteria [BCECE 2005] |
| A. | Nucleic acid |
| B. | Nucleic acid and cytoplasm |
| C. | Nucleic acid and Histone |
| D. | None of these |
| Answer» B. Nucleic acid and cytoplasm | |
| 13948. |
In a given DNA segment the number of nucleotides of guanine is 75 and those of thymine is 75. The total number of nucleotides in the segment will be [MHCET 2002] |
| A. | 75 |
| B. | 750 |
| C. | 225 |
| D. | 300 |
| Answer» E. | |
| 13949. |
Triticale is a man-made cereal which has been developed through hybridization between [CPMT 1989; HP PMT 2005] |
| A. | Wheat and Gram |
| B. | Wheat and Rye |
| C. | Wheat and Oat |
| D. | Wheat and Rice |
| Answer» C. Wheat and Oat | |
| 13950. |
A social forest tree is [APMEE 1996] |
| A. | Teak |
| B. | Sandal wood |
| C. | Subabul |
| D. | Rosewood |
| Answer» D. Rosewood | |