MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 14620 Mcqs, each offering curated multiple-choice questions to sharpen your NEET knowledge and support exam preparation. Choose a topic below to get started.
| 13451. |
A modification of leaf is: |
| A. | Phyllode |
| B. | Phylloclade |
| C. | Cladode |
| D. | Conn |
| Answer» B. Phylloclade | |
| 13452. |
In water chestnut, the thorns are modification of: |
| A. | Leaflet |
| B. | Corolla |
| C. | Leaf |
| D. | Calyx |
| Answer» E. | |
| 13453. |
Match column-I with column-II and select the correct answer using the codes given below. Column-I Column-II A. Leguminosae I. Axile placentation B. Papilionatae II. Tetradynamous C. Solanaceae III. Marginal placentation D. Cruciferae IV. Diadelphous stamens E. Malvaceae V. Epipetalous stamens |
| A. | A-III B-IV C-V D-II E-I |
| B. | A-IV B-III C-V D-II E-I |
| C. | A-III B-IV C-V D-I E-II |
| D. | A-III B-V C-IV D-II E-I |
| Answer» B. A-IV B-III C-V D-II E-I | |
| 13454. |
Flowers are sessile in: |
| A. | Raceme |
| B. | Spike |
| C. | Corymb |
| D. | Umbel |
| Answer» C. Corymb | |
| 13455. |
Branches of stem are: |
| A. | exogenous in origin |
| B. | endogenous in origin |
| C. | partly exogenous and partly endogenous |
| D. | superficial |
| Answer» B. endogenous in origin | |
| 13456. |
A scar on the seed coat through which the developing seeds are attached to the fruit is called as _____. |
| A. | Testa |
| B. | Tegmen |
| C. | Hilum |
| D. | Micropyle |
| Answer» D. Micropyle | |
| 13457. |
Regions of roots from base to root tip are: |
| A. | Maturation zone - Cell division zone-Elongation zone |
| B. | Maturation zone - Elongation zone - Cell division zone |
| C. | Cell division zone - Elongation zone Maturation zone |
| D. | Elongation zone - Cell division zone Maturation zone |
| Answer» C. Cell division zone - Elongation zone Maturation zone | |
| 13458. |
A plant with epidermis specialised to absorb moisture from air is [APMEE 2002] |
| A. | Avicennia |
| B. | Vanda |
| C. | Rhizophora |
| D. | Jussiaea |
| Answer» C. Rhizophora | |
| 13459. |
Which of the following is absent in root hair [BVP 2001] |
| A. | Cell wall |
| B. | Vacuole |
| C. | Nucleus |
| D. | Chloroplast |
| Answer» E. | |
| 13460. |
Velamen takes part in [MP PMT 1986; CPMT 1989, 91; Bihar PMT 1994] |
| A. | Absorption of moisture from air |
| B. | Absorption of water from soil |
| C. | Exchange of gases |
| D. | Transpiration |
| Answer» B. Absorption of water from soil | |
| 13461. |
A root that never develops from radicle is |
| A. | Fibrous roots of grasses |
| B. | Stilt roots of maize |
| C. | Sucking roots of Cuscuta |
| D. | All of these |
| Answer» E. | |
| 13462. |
In roots, branches (Secondary roots) are |
| A. | Stellar in origin |
| B. | Cortical in origin |
| C. | Stellar and endogenous |
| D. | Cortical and exogenous |
| Answer» D. Cortical and exogenous | |
| 13463. |
Root pocket occurs in |
| A. | Maize |
| B. | Pandanus |
| C. | Banyan |
| D. | Water Hyacinth |
| Answer» E. | |
| 13464. |
Roots have thorny branches in [BHU 1989] |
| A. | Vanilla |
| B. | Asparagus |
| C. | Acanthorhiza |
| D. | Pothos |
| Answer» D. Pothos | |
| 13465. |
Choose the correct statement about haustorial (Parasitic) roots of Cuscuta |
| A. | These roots develop contact with xylem of host |
| B. | These develop contact with xylem and phloem of host |
| C. | These develop contact with phloem of host to get food |
| D. | These develop contact with pericycle and lateral roots of host |
| Answer» C. These develop contact with phloem of host to get food | |
| 13466. |
In Pandanus (Screw pine) stilt roots arise from |
| A. | Basal nodes |
| B. | Upper surface of oblique stem |
| C. | Lower side of oblique stem |
| D. | Anywhere |
| Answer» D. Anywhere | |
| 13467. |
Nodulated roots bearing family is [RPMT 1993, 95, 96] |
| A. | Mimosoideae |
| B. | Caesalpinoideae |
| C. | Papilionatae |
| D. | Solanaceae |
| Answer» D. Solanaceae | |
| 13468. |
Water is absorbed by |
| A. | Root hairs |
| B. | Root cap |
| C. | Root |
| D. | Root apex |
| Answer» B. Root cap | |
| 13469. |
Medullary rays are seen in |
| A. | Dicot root |
| B. | Monocot root |
| C. | Monocot stem |
| D. | Dicot stem |
| Answer» E. | |
| 13470. |
Read the assertion and reason carefully: Assertion : Tepals may be free or fused. Reason : When sepals and petals are similar, they are called as tepals. |
| A. | If both the assertion and the reason are true and the reason is a correct explanation of the assertion |
| B. | If both the assertion and reason are true but the reason is not a correct explanation of the assertion |
| C. | If the assertion is true but the reason is false |
| D. | If both the assertion and reason are false |
| Answer» C. If the assertion is true but the reason is false | |
| 13471. |
Read the assertion and reason carefully: Assertion : Trichomes increase the absorptive surface. Reason : Trichomes are sub epidermal in origin. |
| A. | If both the assertion and the reason are true and the reason is a correct explanation of the assertion |
| B. | If both the assertion and reason are true but the reason is not a correct explanation of the assertion |
| C. | If the assertion is true but the reason is false |
| D. | If both the assertion and reason are false |
| Answer» D. If both the assertion and reason are false | |
| 13472. |
In the diagram of T.S. of Stele of Dicot Root, the different parts have been indicated by alphabets; choose the answer in which these alphabets correctly match with the parts they indicate [KCET 2004] |
| A. | A = Endodermis B = Conjunctive tissue C = Metaxylem D = Protoxylem E = Phloem F = Pith |
| B. | A = Endodermis B = Pith C = Protoxylem D = Metaxylem E = Protoxylem F = Conjuctive tissue |
| C. | A = Pericycle B = Conjuctive tissue C = Metaxylem D = Protoxylem E = Phloem |
| D. | A = Endodermis B = Conjuctive tissue C = Protoxylem D = Metaxylem E = Phloem F = Pith |
| Answer» E. | |
| 13473. |
When the apex is pointed, hard and sharp like a spine as in Date Palm, it is called |
| A. | Emarginate |
| B. | Cuspidate |
| C. | Retuse |
| D. | Mucronate |
| Answer» C. Retuse | |
| 13474. |
In 3/8 alternate phyllotaxy (Called ostastichous) |
| A. | There are 8 leaves in 3 circles |
| B. | 3 leaves in 8 circles |
| C. | There are 3 rows of leaves |
| D. | There are 8 rows of leaves on three sided stem |
| Answer» C. There are 3 rows of leaves | |
| 13475. |
Match column-I with column-II and select the correct answer using the codes given below. Column-I Column-II A. Termination I. Aminoacyl tRNA synthetase B. Translation II. Okazaki fragments C. Transcription III. GTP dependent release factor D. DNA replication IV. RNA polymerase |
| A. | A-II; B-I; C-III; D-IV |
| B. | A-III; B-I; C-IV; D-II |
| C. | A-IV; B-III; C-I; D-II |
| D. | A-II; B-III; C-I; D-IV |
| Answer» D. A-II; B-III; C-I; D-IV | |
| 13476. |
Select the incorrect statement(s) about genetic codon. (i) Six codons do not code for any amino acid. (ii) Codon is read in mRNA in a contiguous fashion. (iii) Three codons function as stop codons. (iv) The initiation codon AUG codes for methionine. |
| A. | (i) only |
| B. | (ii) only |
| C. | (i), (ii) and (iv) |
| D. | (i), (ii) and (iii) |
| Answer» B. (ii) only | |
| 13477. |
Match column-I with column-II and select the correct combination from the given options. Column-I Column-II A. Sigma factor I. 5?-3? B. Capping II. Initiation C. Tailing III. Termination D. Codding strand IV. 5? end V. 3?end |
| A. | A-III; B-V; C-IV; D-II |
| B. | A-II; B-IV; C-V; D-I |
| C. | A-II; B-IV; C-V; D-III |
| D. | A-III; B-V; C-IV; D-I |
| Answer» C. A-II; B-IV; C-V; D-III | |
| 13478. |
The scientists involved in discovery of DNA as chemical basis of heredity were: |
| A. | Hershey and Chase |
| B. | Griffith and Avery |
| C. | Avery, Mac Leod and McCarty |
| D. | Watson and Crick |
| Answer» D. Watson and Crick | |
| 13479. |
Transposable genetic elements: |
| A. | Always affect the cell adversely, because when they move, they inactivate genes. |
| B. | Are retroviruses. |
| C. | Provide a mechanism for moving genetic material from organelle genomes to the nuclear genome. |
| D. | Always replicate their DNA when they want. |
| Answer» D. Always replicate their DNA when they want. | |
| 13480. |
During conjugation: |
| A. | DNA from one bacterial cell is transferred to another bacterial cell using a bacteriophage. |
| B. | Mutants that are auxotrophic for one nutrient can be converted to prototrophs when mixed with mutants that are auxotrophic for another nutrient. |
| C. | A pilus is synthesised and DNA is transferred from one bacterium across the conjugation tube to the recipient bacterium. |
| D. | Both [a] and [b] |
| Answer» E. | |
| 13481. |
Code transfer for synthesis of polypeptide involves: |
| A. | DNA, tRNA, rRNA and mRNA. |
| B. | mRNA, tRNA, rRNA and DNA. |
| C. | tRNA, DNA, mRNA and rRNA. |
| D. | DNA, mRNA, tRNA and amino acids. |
| Answer» E. | |
| 13482. |
Choose the sequence in which the following enzymes take part in DNA replication. (i) Helicase (ii) Primase (iii) SSB (iv) DNA polymerase (v) DNA ligase |
| A. | (i) \[\to \] (v) \[\to \] (iv) \[\to \] (iii) \[\to \] (ii) |
| B. | (i) \[\to \] (ii) \[\to \] (iii) \[\to \] (iv) \[\to \] (v) |
| C. | (i) \[\to \] (iii) \[\to \] (ii) \[\to \] (iv) \[\to \] (v) |
| D. | (i) \[\to \] (iv) \[\to \] (iii) \[\to \] (ii) \[\to \] (v) |
| Answer» D. (i) \[\to \] (iv) \[\to \] (iii) \[\to \] (ii) \[\to \] (v) | |
| 13483. |
Match column-I with column-II and choose the correct option. Column-I Column-II A. Exon I. Coding sequence B. Intron II. Cistron C. Genetic code III. Triplet bases on mRNA D. DNA packaging IV. Nucleosome E. V. Non-codding sequence |
| A. | A-I; B-III; C-II; D-V |
| B. | A-I; B-IV; C-II; D-III |
| C. | A-I; B-V; C-III; D-IV |
| D. | A-IV; B-I; C-V; D-III |
| Answer» D. A-IV; B-I; C-V; D-III | |
| 13484. |
DNA binding proteins: |
| A. | Have distinct three-dimensional structures that allow them to bind to the DNA. |
| B. | Are transcription factors. |
| C. | Inhibit the loss of ends from the chromosome and help DNA condense in the nucleus. |
| D. | All of the above |
| Answer» E. | |
| 13485. |
DNA replication is: |
| A. | Conservative and discontinuous. |
| B. | Semi-conservative and semi-discontinuous. |
| C. | Semi-conservative and discontinuous; |
| D. | conservative |
| Answer» D. conservative | |
| 13486. |
The process of the elongation in transcription requires: |
| A. | \[C{{a}^{++}}\,or\,M{{n}^{++}}\] |
| B. | \[N{{a}^{+}}\,or\,C{{l}^{-}}\] |
| C. | \[N{{a}^{+}}\,or\,{{K}^{+}}\] |
| D. | \[M{{n}^{++}}\,or\,M{{g}^{+2}}\] |
| Answer» E. | |
| 13487. |
Which of the following is most abundant in human DNA? |
| A. | Regulatory genes |
| B. | Non-coding DNA |
| C. | Transposons |
| D. | Homeotic genes |
| Answer» C. Transposons | |
| 13488. |
Which of the following does not play a role in the genetic regulation of tryptophan synthesis in the bacterium E. coli? |
| A. | RNA polymerase |
| B. | Homeotic gene |
| C. | Repressor protein |
| D. | Operator |
| Answer» C. Repressor protein | |
| 13489. |
If the nucleus of a frog egg is destroyed and replaced with the nucleus of an intestinal cell from a tadpole, the egg can develop into a normal tadpole. This demonstrates that: |
| A. | Intestinal cells are fully differentiated. |
| B. | There is little functional difference between an egg cell and an intestinal cell. |
| C. | An intestinal cell possesses a full set of genes. |
| D. | Intestinal cells are not differentiated. |
| Answer» D. Intestinal cells are not differentiated. | |
| 13490. |
The lagging daughter strand of DNA is synthesised in what appears to be the "wrong" direction. This synthesis is accomplished by: |
| A. | Ligating (connecting) short Okazaki fragments that are synthesised in short spurts in the "right" direction. |
| B. | Primase. |
| C. | Using multiple primers and DNA polymerase I. |
| D. | Both [a] and [b] |
| Answer» E. | |
| 13491. |
Which of the following statements about RNA polymerase are correct? (i) RNA polymerase I transcribes rRNAs. (ii) RNA polymerase II transcribes snRNAs. (iii) RNA polymerase III transcribes hnRNA. (iv) RNA polymerase II transcribes hnRNAs. |
| A. | (i) and (ii) |
| B. | (i) and (iii) |
| C. | (ii) and (iii) |
| D. | (i) and (iv) |
| Answer» E. | |
| 13492. |
Regulated unit of genetic material is termed as: |
| A. | Operon |
| B. | Regulator gene |
| C. | Operator gene |
| D. | Okazaki segment |
| Answer» B. Regulator gene | |
| 13493. |
Wobble hypothesis establishes: |
| A. | Peptide chain formation |
| B. | Initiation of peptide chain |
| C. | Termination of peptide chain |
| D. | Economy in t RNA molecules. |
| Answer» E. | |
| 13494. |
Termination of polypeptide chain is brought about by: |
| A. | UUG |
| B. | UAA |
| C. | UUG |
| D. | UCG |
| Answer» C. UUG | |
| 13495. |
AUG initiation codon occurs over: |
| A. | 3'end of mRNA |
| B. | 5'end of m RNA |
| C. | Short arm of t RNA |
| D. | long arm of t RNA |
| Answer» C. Short arm of t RNA | |
| 13496. |
Information flow or central dogma of modem biology is: |
| A. | RNA \[\to \] Proteins \[\to \] DNA. |
| B. | DNA \[\to \] RNA \[\to \] Proteins. |
| C. | RNA \[\to \] DNA \[\to \] Proteins. |
| D. | DNA \[\to \] RNA \[\to \] Proteins. |
| Answer» E. | |
| 13497. |
Nonsense codon takes part in: |
| A. | Terminating message of gene controlled protein synthesis. |
| B. | Formation of unspecified amino acids. |
| C. | Conversion of sense DNA into non-sense one. |
| D. | Releasing t RNA from polypeptide chain. |
| Answer» B. Formation of unspecified amino acids. | |
| 13498. |
Find out the correct statement. |
| A. | Uracil is present in RNA at the place of thymine. |
| B. | The complex of DNA and protein in chromosome is called chromatin. |
| C. | Heterochromatin is the most highly condensed form of chromatin. |
| D. | The process involved in the RNA formation on the DNA template is called replication. |
| Answer» E. | |
| 13499. |
Identify the labels A, B, C and D in the given structure of t RNA and select the correct option. |
| A. | ABCDAnticodon loop\[T\psi C\,loop\]AA binding siteDHU loop |
| B. | AA binding site\[T\psi C\,loop\]Anticodon loopDHU loop |
| C. | AA binding siteDHU loopAnticodon loop\[T\psi C\,loop\] |
| D. | AA binding siteDHU loop\[T\psi C\,loop\]Anticodon loop |
| Answer» C. AA binding siteDHU loopAnticodon loop\[T\psi C\,loop\] | |
| 13500. |
The given figure shows lac operon model and its functioning. Select the option which correctly labels A, B, X, Y and Z marked in the figure and also identify the label (L) which is primarily responsible for the hydrolysis of the disaccharide, lactose, into galactose & glucose. |
| A. | ABXYZLRepressorInducer\[\beta \]-GalactosidasePermeaseTransacetylaseX |
| B. | RepressorInducerPermease\[\beta \]- GalactosidaseTransacetylaseY |
| C. | InducerRepressor\[\beta \]- GalactosidasePermeaseTransacetylaseZ |
| D. | InducerRepressor\[\beta \]- GalactosidaseTransacetylasePermeaseB |
| Answer» B. RepressorInducerPermease\[\beta \]- GalactosidaseTransacetylaseY | |