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This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Fluid Mechanics knowledge and support exam preparation. Choose a topic below to get started.
1. |
Find the discharge over a cipolletti weir of length 1.3 m when the head over the weir is 0.65 m. Take Cd = 0.60. |
A. | 2.12 m3/s |
B. | 1.21 m3/s |
C. | 2.5 m3/s |
D. | 1.5 m3/s |
Answer» C. 2.5 m3/s | |
2. |
Find the discharge over a cipolletti weir of length 1.5 m when the head over the weir is 0.85 m. Take Cd = 0.61. |
A. | 2.12 m3/s |
B. | 1.25 m3/s |
C. | 2.5 m3/s |
D. | 1.5 m3/s |
Answer» B. 1.25 m3/s | |
3. |
The head of water over a rectangular weir is 26 cm. The length of the crest of the weir end contraction suppressed is 1.25 m. Find the discharge using the Francis formula. |
A. | 0.304 m3/s |
B. | 0.502 m3/s |
C. | 0.350 m3/s |
D. | 0.625 m3/s |
Answer» B. 0.502 m3/s | |
4. |
In Bazin’s formula, the discharge is inversely proportional to the length of weir. |
A. | True |
B. | False |
Answer» C. | |
5. |
In Francis formula, the effective length is – |
A. | L-0.2H |
B. | L-0.4H |
C. | L-0.3H |
D. | L-0.1H |
Answer» B. L-0.4H | |
6. |
FIND_THE_DISCHARGE_OVER_A_CIPOLLETTI_WEIR_OF_LENGTH_1.5_M_WHEN_THE_HEAD_OVER_THE_WEIR_IS_0.85_M._TAKE_CD_=_0.61.?$ |
A. | 2.12 m<sup>3</sup>/s |
B. | 1.25 m<sup>3</sup>/s |
C. | 2.5 m<sup>3</sup>/s |
D. | 1.5 m<sup>3</sup>/s |
Answer» B. 1.25 m<sup>3</sup>/s | |
7. |
Find the discharge over a cipolletti weir of length 1.3 m when the head over the weir is 0.65 m. Take Cd = 0.60.$ |
A. | 2.12 m<sup>3</sup>/s |
B. | 1.21 m<sup>3</sup>/s |
C. | 2.5 m<sup>3</sup>/s |
D. | 1.5 m<sup>3</sup>/s |
Answer» C. 2.5 m<sup>3</sup>/s | |
8. |
The head of water over a rectangular weir is 28 cm. The length of the crest of the weir end contraction suppressed is 1.27 m. Find the discharge using the Francis formula. |
A. | 0.346 m<sup>3</sup>/s |
B. | 0.556 m<sup>3</sup>/s |
C. | 0.788 m<sup>3</sup>/s |
D. | 0.225 m<sup>3</sup>/s |
Answer» B. 0.556 m<sup>3</sup>/s | |
9. |
The head of water over a rectangular weir is 38 cm. The length of the crest of the weir end contraction suppressed is 1.3 m. Find the discharge using the Francis formula. |
A. | 0.56 m<sup>3</sup>/s |
B. | 0.75 m<sup>3</sup>/s |
C. | 0.85 m<sup>3</sup>/s |
D. | 0.69 m<sup>3</sup>/s |
Answer» B. 0.75 m<sup>3</sup>/s | |
10. |
In Bazin’s formula, the discharge is inversely proportional to the length of weir.$ |
A. | True |
B. | False |
Answer» C. | |
11. |
In Francis empirical expression for discharge, the relation between head of water and discharge is |
A. | Q is directly proportional to H |
B. | Q is directly proportional to H<sup>1.5</sup> |
C. | Q is directly proportional to H<sup>2.5</sup> |
D. | Q is directly proportional to H<sup>0.5</sup> |
Answer» C. Q is directly proportional to H<sup>2.5</sup> | |
12. |
In Francis formula, the effective length is –$ |
A. | L-0.2H |
B. | L-0.4H |
C. | L-0.3H |
D. | L-0.1H |
Answer» B. L-0.4H | |
13. |
What is the reduction in crest length due to each end contraction? |
A. | 0.1H |
B. | 0.2H |
C. | 0.15H |
D. | 0.25H |
Answer» B. 0.2H | |