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				This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Fluid Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. | Find the discharge over a cipolletti weir of length 1.3 m when the head over the weir is 0.65 m. Take Cd = 0.60. | 
| A. | 2.12 m3/s | 
| B. | 1.21 m3/s | 
| C. | 2.5 m3/s | 
| D. | 1.5 m3/s | 
| Answer» C. 2.5 m3/s | |
| 2. | Find the discharge over a cipolletti weir of length 1.5 m when the head over the weir is 0.85 m. Take Cd = 0.61. | 
| A. | 2.12 m3/s | 
| B. | 1.25 m3/s | 
| C. | 2.5 m3/s | 
| D. | 1.5 m3/s | 
| Answer» B. 1.25 m3/s | |
| 3. | The head of water over a rectangular weir is 26 cm. The length of the crest of the weir end contraction suppressed is 1.25 m. Find the discharge using the Francis formula. | 
| A. | 0.304 m3/s | 
| B. | 0.502 m3/s | 
| C. | 0.350 m3/s | 
| D. | 0.625 m3/s | 
| Answer» B. 0.502 m3/s | |
| 4. | In Bazin’s formula, the discharge is inversely proportional to the length of weir. | 
| A. | True | 
| B. | False | 
| Answer» C. | |
| 5. | In Francis formula, the effective length is – | 
| A. | L-0.2H | 
| B. | L-0.4H | 
| C. | L-0.3H | 
| D. | L-0.1H | 
| Answer» B. L-0.4H | |
| 6. | FIND_THE_DISCHARGE_OVER_A_CIPOLLETTI_WEIR_OF_LENGTH_1.5_M_WHEN_THE_HEAD_OVER_THE_WEIR_IS_0.85_M._TAKE_CD_=_0.61.?$ | 
| A. | 2.12 m<sup>3</sup>/s | 
| B. | 1.25 m<sup>3</sup>/s | 
| C. | 2.5 m<sup>3</sup>/s | 
| D. | 1.5 m<sup>3</sup>/s | 
| Answer» B. 1.25 m<sup>3</sup>/s | |
| 7. | Find the discharge over a cipolletti weir of length 1.3 m when the head over the weir is 0.65 m. Take Cd = 0.60.$ | 
| A. | 2.12 m<sup>3</sup>/s | 
| B. | 1.21 m<sup>3</sup>/s | 
| C. | 2.5 m<sup>3</sup>/s | 
| D. | 1.5 m<sup>3</sup>/s | 
| Answer» C. 2.5 m<sup>3</sup>/s | |
| 8. | The head of water over a rectangular weir is 28 cm. The length of the crest of the weir end contraction suppressed is 1.27 m. Find the discharge using the Francis formula. | 
| A. | 0.346 m<sup>3</sup>/s | 
| B. | 0.556 m<sup>3</sup>/s | 
| C. | 0.788 m<sup>3</sup>/s | 
| D. | 0.225 m<sup>3</sup>/s | 
| Answer» B. 0.556 m<sup>3</sup>/s | |
| 9. | The head of water over a rectangular weir is 38 cm. The length of the crest of the weir end contraction suppressed is 1.3 m. Find the discharge using the Francis formula. | 
| A. | 0.56 m<sup>3</sup>/s | 
| B. | 0.75 m<sup>3</sup>/s | 
| C. | 0.85 m<sup>3</sup>/s | 
| D. | 0.69 m<sup>3</sup>/s | 
| Answer» B. 0.75 m<sup>3</sup>/s | |
| 10. | In Bazin’s formula, the discharge is inversely proportional to the length of weir.$ | 
| A. | True | 
| B. | False | 
| Answer» C. | |
| 11. | In Francis empirical expression for discharge, the relation between head of water and discharge is | 
| A. | Q is directly proportional to H | 
| B. | Q is directly proportional to H<sup>1.5</sup> | 
| C. | Q is directly proportional to H<sup>2.5</sup> | 
| D. | Q is directly proportional to H<sup>0.5</sup> | 
| Answer» C. Q is directly proportional to H<sup>2.5</sup> | |
| 12. | In Francis formula, the effective length is –$ | 
| A. | L-0.2H | 
| B. | L-0.4H | 
| C. | L-0.3H | 
| D. | L-0.1H | 
| Answer» B. L-0.4H | |
| 13. | What is the reduction in crest length due to each end contraction? | 
| A. | 0.1H | 
| B. | 0.2H | 
| C. | 0.15H | 
| D. | 0.25H | 
| Answer» B. 0.2H | |