MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 2167 Mcqs, each offering curated multiple-choice questions to sharpen your Php knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
How is the load transference generally provided in the contraction joints? |
| A. | Reinforcement bars |
| B. | Aggregate interlocking |
| C. | Bitumen filler |
| D. | Concrete strips |
| Answer» C. Bitumen filler | |
| 152. |
Which of the below sealant is commonly used in pavements? |
| A. | Polysulphide sealant |
| B. | Silicone sealant |
| C. | Acrylic sealant |
| D. | Butyl sealant |
| Answer» B. Silicone sealant | |
| 153. |
What is the percentage of thickness recovery recommended for a joint filler after the third application of load? |
| A. | 50% |
| B. | 60% |
| C. | 70% |
| D. | 80% |
| Answer» D. 80% | |
| 154. |
Warping joints are regularly used in all types of pavements to deal with warping. |
| A. | True |
| B. | False |
| Answer» C. | |
| 155. |
Which type of joint is used in a prestressed cement concrete pavement? |
| A. | Contraction |
| B. | Construction |
| C. | None |
| D. | All |
| Answer» D. All | |
| 156. |
Which of the below is not a property of the joint sealant? |
| A. | Durability |
| B. | Resistance to ingress |
| C. | Cohesion |
| D. | Extensibility |
| Answer» D. Extensibility | |
| 157. |
What is the bitumen content required when using preformed fillers? |
| A. | 45% |
| B. | 35% |
| C. | 55% |
| D. | 25% |
| Answer» C. 55% | |
| 158. |
Which of the following is not a type of joint arrangement placed in the transverse direction? |
| A. | Straight |
| B. | Staggered |
| C. | Skewed |
| D. | Uniform |
| Answer» B. Staggered | |
| 159. |
Longitudinal joints are provided in pavements that have width ______ than ______ |
| A. | Less, 5 m |
| B. | Less, 4.5 m |
| C. | Greater, 5 m |
| D. | Greater, 4.5 m |
| Answer» E. | |
| 160. |
Which are the characteristics of an isolation joint provided in the pavement? |
| A. | Half width, full depth |
| B. | Full width, half depth |
| C. | Full width, full depth |
| D. | Half width, half depth |
| Answer» D. Half width, half depth | |
| 161. |
All types of joints are used in all types of rigid pavements. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 162. |
Which of the below joints is not useful in controlling the effects due to temperature stresses? |
| A. | Warping |
| B. | Expansion |
| C. | Contraction |
| D. | Shrinkage |
| Answer» E. | |
| 163. |
______ joint is the most common one. |
| A. | Contraction |
| B. | Expansion |
| C. | Construction |
| D. | Warping |
| Answer» B. Expansion | |
| 164. |
It takes approximately _____ pounds of skim milk to make one pound of non-fat dry-milk. |
| A. | 10 |
| B. | 11 |
| C. | 12 |
| D. | 20 |
| Answer» C. 12 | |
| 165. |
Light whipping cream has a minimum of _____% milk fat. |
| A. | 18 |
| B. | 30 |
| C. | 35 |
| D. | 40 |
| Answer» C. 35 | |
| 166. |
Butter production now accounts for _______% of the total milk supply. |
| A. | 8 |
| B. | 15 |
| C. | 18 |
| D. | 25 |
| Answer» D. 25 | |
| 167. |
If vitamin A is added to milk, it must be at a level of no less than ______ international units (I.U.) per quart. |
| A. | 400 |
| B. | 1000 |
| C. | 1500 |
| D. | 2000 |
| Answer» E. | |
| 168. |
Adolescents have a recommendation of _________ milligrams of calcium per day. |
| A. | 1000 |
| B. | 1200 |
| C. | 1300 |
| D. | 1500 |
| Answer» D. 1500 | |
| 169. |
The whey proteins in milk constitute about _____% of the protein found in milk. |
| A. | 10 |
| B. | 15 |
| C. | 18 |
| D. | 20 |
| Answer» D. 20 | |
| 170. |
To make Mozzarella cheese the pasteurized milk is curded at ____________degrees F. |
| A. | 45 |
| B. | 88 |
| C. | 145 |
| D. | 190 |
| Answer» C. 145 | |
| 171. |
Diastereomers are _________ |
| A. | Geometrical isomers |
| B. | Mirror images |
| C. | Non-mirror images |
| D. | Unstable molecules |
| Answer» D. Unstable molecules | |
| 172. |
The plane which divides the molecule into two equal parts so that each half is the mirror image of other half is called _________ |
| A. | Centre of symmetry |
| B. | Plane of symmetry |
| C. | Axis of symmetry |
| D. | Angle of symmetry |
| Answer» C. Axis of symmetry | |
| 173. |
Optical activity can also result from the lack of molecular symmetry in molecules. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 174. |
Enantiomerism is the phenomenon of existence of enantiomers in a single structural formula, in _________ configuration. |
| A. | Same |
| B. | Opposite |
| C. | Same as well as opposite |
| D. | Initially opposite and then same |
| Answer» C. Same as well as opposite | |
| 175. |
Chiral molecules which are non-super-imposable mirror images of each other are called _________ |
| A. | Diastereomers |
| B. | Meso compounds |
| C. | Racemic mixture |
| D. | Enantiomers |
| Answer» E. | |
| 176. |
To avoid excessive high value of molecular rotation, concentration is taken as _________ |
| A. | 1 centi-mole/mL |
| B. | 1 milli-mole/mL |
| C. | 1 mole/mL |
| D. | 1 kilo-mole/mL |
| Answer» B. 1 milli-mole/mL | |
| 177. |
0.5 g of an optically active compound was dissolved in 2mL of solvent at 250C. The solution was kept in a cell of length 10 cm and observed rotation was +100. What is the specific rotation of its enantiomer? |
| A. | -400 |
| B. | +400 |
| C. | -100 |
| D. | +100 |
| Answer» C. -100 | |
| 178. |
The specific rotation is inversely proportional to _________ |
| A. | Observed rotation |
| B. | Temperature |
| C. | Concentration of solution |
| D. | D-line of sodium vapour light |
| Answer» D. D-line of sodium vapour light | |
| 179. |
For any given substance, the amount of rotation does not depends upon _________ |
| A. | Wavelength of light used |
| B. | Nature of the solvent |
| C. | Temperature |
| D. | Pressure |
| Answer» E. | |
| 180. |
Chiral molecules are those which are? |
| A. | Shows geometrical isomerism |
| B. | Superimposable on their mirror images |
| C. | Not superimposable on their mirror images |
| D. | Unstable molecules |
| Answer» D. Unstable molecules | |
| 181. |
Causal systems are ______ |
| A. | Anticipative |
| B. | Non anticipative |
| C. | For certain cases anticipative |
| D. | For certain cases anticipative and non anticipative |
| Answer» C. For certain cases anticipative | |
| 182. |
The overall impulse response of the system is given by ______ |
| A. | h(t) = (h1(t) + h2(t) * h3(t)) – h4(t) |
| B. | y(t) = x(t) * (h1(t) + h2(t)*h3(t)) – h4(t) |
| C. | h(t) = (h1(t) + h2(t) * h3(t)) + h4(t) * x(t) |
| D. | h(t) = (h1(t) h2(t) * h3(t)) – h4(t) |
| Answer» B. y(t) = x(t) * (h1(t) + h2(t)*h3(t)) – h4(t) | |
| 183. |
What is this property of impulse response is called ___________h1(t) * h2(t) = h2(t) * h1(t) |
| A. | Associative property |
| B. | Commutative property |
| C. | Distributive property |
| D. | Closure law |
| Answer» C. Distributive property | |
| 184. |
If two LTI systems with impulse response h1 (t) and h2 (t) and are connected in parallel then output is given by ______ |
| A. | y(t) = x(t) *(h1(t) + h2(t)) |
| B. | y(t) = x(t) + (h1(t) + h2(t)) |
| C. | y(t) = x(t) * (h1(t) h2(t)) |
| D. | y(t) = (x(t) * h1(t)) + h2(t) |
| Answer» B. y(t) = x(t) + (h1(t) + h2(t)) | |
| 185. |
In shunted rheostatic armature control method ______________ |
| A. | Variable resistor is added in parallel with armature |
| B. | Variable resistor is added in series with armature |
| C. | Variable resistor is added in parallel with armature and another variable resistor is added in series |
| D. | Variable resistor is not added in whole circuit |
| Answer» D. Variable resistor is not added in whole circuit | |
| 186. |
Speed regulation of armature series control method is __________ |
| A. | Very good |
| B. | Zero |
| C. | Poor |
| D. | Cannot comment |
| Answer» D. Cannot comment | |
| 187. |
Consider the armature control method, where 10 Ω resistance is connected in series with armature in first case. For second case resistance value is changed 100 Ω. Then ____________ |
| A. | Speed-torque characteristic of both will start from same point |
| B. | For first case speed-torque characteristic will start below to the case 2 |
| C. | For first case speed-torque characteristic will start above to the case 2 |
| D. | Can’t say because other parameters are unavailable |
| Answer» B. For first case speed-torque characteristic will start below to the case 2 | |
| 188. |
By series armature resistance method, we can get _________________________ |
| A. | Speed above rated speed |
| B. | Speed equal to rated speed |
| C. | Speed below rated speed |
| D. | All speeds are possible |
| Answer» D. All speeds are possible | |
| 189. |
In rheostatic series control method of armature we add ____________a) Variable resistor in parallel with armatureb) Variable resistor in series with armature |
| A. | Variable resistor in parallel with armatureb) Variable resistor in series with armaturea) Fixed resistor in parallel with armature |
| B. | Variable resistor in series with armaturea) Fixed resistor in parallel with armatureb) Fixed resistor in series with armature |
| Answer» C. | |
| 190. |
For which speed control method we get minimum efficiency? |
| A. | Voltage control method |
| B. | Field control method |
| C. | Armature control method |
| D. | Cannot be determined |
| Answer» D. Cannot be determined | |
| 191. |
Full-length RNA undergoes splicing allowing _______ gene to be translated. |
| A. | Integrase |
| B. | Env |
| C. | Transcriptase |
| D. | Pol |
| Answer» C. Transcriptase | |
| 192. |
The genomic RNA is capped and polyadenylated, allowing the ____ gene to be translated. |
| A. | Gag |
| B. | Pol |
| C. | Env |
| D. | Transcriptase |
| Answer» B. Pol | |
| 193. |
Viral genomic RNA is synthesized by ___________ |
| A. | Gag, pol, env |
| B. | Long terminal repeats (LTR) |
| C. | Reverse transcriptase |
| D. | Single promoter |
| Answer» C. Reverse transcriptase | |
| 194. |
The _______ gene of the integrated provirus codes for viral envelope protein. |
| A. | Gag |
| B. | Env |
| C. | Pol |
| D. | LTR |
| Answer» C. Pol | |
| 195. |
Retroviral vectors can be used to make stably transformed cell lines because____________ |
| A. | Cloning efficiency |
| B. | Stable transformation |
| C. | No host lysis |
| D. | Cost efficiency |
| Answer» D. Cost efficiency | |
| 196. |
What is the nucleation rate ifMass of production of crystals C=10kgVolume shape factor fv= 0.5Density of particle= 5kg/m3Characteristic size of crystal L= 0.5volume of mother liquor in magma V= 1m3 |
| A. | 9 |
| B. | 18 |
| C. | 180 |
| D. | 36 |
| Answer» D. 36 | |
| 197. |
What is the nucleation rate ifMass of production of crystals C=0.5kgVolume shape factor fv= 0.5Density of particle= 0.5kg/m3Characteristic size of crystal L= 0.5volume of mother liquor in magma V= 1m3 |
| A. | 0.5 |
| B. | 15 |
| C. | 1.8 |
| D. | 18 |
| Answer» E. | |
| 198. |
What is the nucleation rate ifMass of production of crystals C=0.5kgVolume shape factor fv= 0.5Density of particle= 5kg/m3Characteristic size of crystal L= 0.6volume of mother liquor in magma V= 1m3 |
| A. | 1.45 |
| B. | 1.5 |
| C. | 1.07 |
| D. | 1.04 |
| Answer» E. | |
| 199. |
What is the nucleation rate ifMass of production of crystals C=0.5kgVolume shape factor fv= 0.5Density of particle= 5kg/m3Characteristic size of crystal L= 0.5volume of mother liquor in magma V= 0.5m3 |
| A. | 5.4 |
| B. | 3.6 |
| C. | 1.8 |
| D. | 2.7 |
| Answer» C. 1.8 | |
| 200. |
What is the nucleation rate ifMass of production of crystals C=0.5kgVolume shape factor fv= 0.5Density of particle= 5kg/m3Characteristic size of crystal L= 0.5volume of mother liquor in magma V= 1m3 |
| A. | 0.5 |
| B. | 1.5 |
| C. | 1.8 |
| D. | 2.7 |
| Answer» D. 2.7 | |