MCQOPTIONS
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MCQOPTIONS
This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Analog Communications knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which of the following cannot be the Fourier series of a periodic signal? |
| A. | x(t) = 2Cost + 4Cos7t |
| B. | x(t) = 2Cosπt + 4Cos7t |
| C. | x(t) = Cost + 0.7 |
| D. | x(t) = 2Cost + 4Sin7t |
| Answer» D. x(t) = 2Cost + 4Sin7t | |
| 2. |
Commercial frequency deviation is ________ |
| A. | 75 KHz |
| B. | 80 KHz |
| C. | 85 KHz |
| D. | 65 KHz |
| Answer» B. 80 KHz | |
| 3. |
Modulation is also called detection. |
| A. | True |
| B. | False |
| Answer» C. | |
| 4. |
COMMERCIAL_FREQUENCY_DEVIATION_IS_________?$ |
| A. | 75 KHz |
| B. | 80 KHz |
| C. | 85 KHz |
| D. | 65 KHz |
| Answer» B. 80 KHz | |
| 5. |
Which of the following cannot be the Fourier series of a periodic signal?$ |
| A. | x(t) = 2Cost + 4Cos7t |
| B. | x(t) = 2Cosπt + 4Cos7t |
| C. | x(t) = Cost + 0.7 |
| D. | x(t) = 2Cost + 4Sin7t |
| Answer» D. x(t) = 2Cost + 4Sin7t | |
| 6. |
Power of carrier wave is 500W and modulation index is 0.25. Find its total power? |
| A. | 500W |
| B. | 415W |
| C. | 375W |
| D. | 516W |
| Answer» E. | |
| 7. |
The radiation at right angles is zero means ________ |
| A. | l =  é |
| B. | l = <sup> é</sup>‚ÅÑ<sub>4</sub> |
| C. | l = 2  é |
| D. | l = <sup> é</sup>‚ÅÑ<sub>2</sub> |
| Answer» B. l = <sup>¬¨‚Ć‚àö¬©</sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>4</sub> | |
| 8. |
It is suitable to connect woofer from the input through ________ |
| A. | band pass filter |
| B. | band stop filter |
| C. | low pass filter |
| D. | high pass filter |
| Answer» D. high pass filter | |
| 9. |
A modem is classified as low if speed of data rate is ________ |
| A. | upto 600bps |
| B. | upto 200bps |
| C. | upto 400bps |
| D. | upto 500bps |
| Answer» B. upto 200bps | |
| 10. |
If each element of signal occupies 40ms, determine its speed? |
| A. | 20 bauds |
| B. | 25 bauds |
| C. | 40 bauds |
| D. | 0.05 bauds |
| Answer» C. 40 bauds | |
| 11. |
For attenuation of high frequencies we can use ________ |
| A. | inductor |
| B. | shunt capacitance |
| C. | series capacitance |
| D. | combination of inductor and resistor |
| Answer» C. series capacitance | |
| 12. |
AM waves is represented by which equation? |
| A. | [1 + m(t)].c(t) |
| B. | [1 – m(t)].c(t) |
| C. | [1 + m(t)].2c(t) |
| D. | [1 + 2m(t)].c(t) |
| Answer» B. [1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® m(t)].c(t) | |