यदि `xsin^(3)theta+ycos^(3)theta=sinthetacostheta` हो और `xsintheta-ycostheta=0` हो तो `x^(2)+y^(2)` का मान बताइए ?
A. 1
B. 2
C. `1//2`
D. `3//2`
A. 1
B. 2
C. `1//2`
D. `3//2`
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Correct Answer – a
`x sintheta-ycos theta=0`
`x sin theta=ycos theta`
`(sintheta)/(cos theta)=(y)/(x)`
By comparing
`sin theta=y,costheta=x`
Now,
`xsin^(2)theta+ycos^(2)theta=sin theta.costheta`
Put values of x,y
`xy^(2)+yx^(2)=y.x`
`xy(x^(2)+y^(@))=xy`
`x^(2)+y^(2)=1`