Write the maximum and minimum values of sin (sin x).
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sin(x) has maximum value at x = π/2 and its minimum at
x = -π/2 which are 1 and -1 respectively.
As 1 < π/2;
so, the argument of the outer sin always lies within the interva
[-π/2, π/2]
So the maximum and minimum of the given function are
in 1 and – sin 1.